Question

A flag pole 18 m high casts a shadow 9.6 m long. Find the distance of the top of the pole from the far end of the shadow.

Answer 1

Let BC = 18 m be the flag pole and its shadow be AB = 9.6 m.

The distance of the top of the pole, C from the far end i.e., A of the shadow is AC.

In right angled ∆ABC,

AC² = AB² + BC²   ...[By pythagoras theorem]

⇒ AC² = (9.6)² + (18)²

⇒ AC² = 92.16 + 324

⇒ AC² = 416.16

∴ AC = `sqrt(416.16)` = 20.4 m

Hence, the required distance is 20.4 m.