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A drop of water placed between two parallel glass plates which are then pressed together until the water film is 0.01 cm thick. If the area of water in contact with either plate is 5 cm2, then the

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प्रश्न

A drop of water placed between two parallel glass plates which are then pressed together until the water film is 0.01 cm thick. If the area of water in contact with either plate is 5 cm2, then the force due to surface tension drawing the plates together is ______.

(S.T. of water is 75 dyne/cm)

विकल्प

  • 75 gm-wt

  • 150 gm-wt

  • 750 gm-wt

  • 425 gm-wt

MCQ
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उत्तर

A drop of water placed between two parallel glass plates which are then pressed together until the water film is 0.01 cm thick. If the area of water in contact with either plate is 5 cm2, then the force due to surface tension drawing the plates together is 75 gm-wt.

Explanation:

`Delta "P" = "T" (1/"r"_1 + 1/"r"_2)`

As r1 = r and r2 = `alpha`,

`Delta "P" = "T"/"r"` But r = d/2

∴ `Delta "P" = "2T"/"d"`

∴ F = P.A = `"2T"/"d" "A" = (2 xx 75 xx 5)/0.01`

= 75 x 103 dyne

= 75 gm-wt

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