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प्रश्न
A diverging mirror of radius of curvature 40 cm forms an image which is half the height of the object. Find the object and image positions.
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उत्तर
Given,
The mirror is convex.
The mirror is convex.
Magnification 'm' = 12
Radius of curvature 'R' = 40 cm
Focal length of the convex mirror 'f=2 = 20 cm`
We have to find the position of the image 'v' and distance of the object from the mirror 'u'.
Using the mirror formula, we get
`1/f=1/u+1/v`
Given, m=`1/2`
Again, m =`-v/u`
Therefore,V =-`-1/2u`
By puting the value of `V` in the mirror formula, We get
`1/f=1/u-2/u(-1)/u`
⇒`1/20=(-1)/u`
⇒`u=-20cm`
⇒`v=-((-20))/2`
⇒`v=10 cm`
⇒`1/20=(-1)/u`
⇒`u=-20cm`
⇒`v=-((-20))/2`
⇒`v=10 cm`
If an objet is placed at a distance of 20 cm in front of the mirror, the image will be formed 10 cm behind the mirror.
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Notes
`1/f=1/u-2/u(-1)/u`
⇒`1/20=(-1)/u`
⇒`u=-20cm`
⇒`v=-((-20))/2`
⇒`v=10 cm`
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