हिंदी

A convex mirror has a focal length of 18 cm. The image of an object kept in front of the mirror is half the height of the object. What is the distance of the object from the mirror?

Advertisements
Advertisements

प्रश्न

A convex mirror has a focal length of 18 cm. The image of an object kept in front of the mirror is half the height of the object. What is the distance of the object from the mirror?  

योग
Advertisements

उत्तर

Given:

Focal length (f) = 18 cm

Magnifiction (M) = `("Height of the image"  ("h"_2))/("Height of the object"  ("h"_1))`

= `1/2`

Find: Object distance (u)

Formula:

  1. M = `("h"_2)/("h"_1) = -"v"/"u"`
  2. `1/"f" = 1/"v" + 1/"u"`

Calculations:

According to formula (i),

`1/2 = -"v"/"u"`

∴ v = `-"u"/2`

According to formula (ii),

`1/"f" = 1/"v" + 1/"u" = ("u" + "v")/("uv")`

∴ f = `("uv")/ ("u" + "v")`

Now, v = `-"u"/2`

∴ f = `("u"((-"u")/2))/("u" + ((-"u")/2))`

∴ `18 = ((-"u"^2)/2)/((2"u" - "u")/2)  = (-"u"^2)/"u"`

∴ u = −18 cm

A negative sign indicates that the object is placed to the left of the mirror.

Hence, the distance of the object from the mirror is 18 cm.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Reflection of Light - Exercise [पृष्ठ १२७]

APPEARS IN

बालभारती Science and Technology [English] Standard 9 Maharashtra State
अध्याय 11 Reflection of Light
Exercise | Q 5. b. | पृष्ठ १२७

संबंधित प्रश्न

An object of 10 cm is placed in front of a plane mirror. The height of image will be …………….
(a) 5 cm
(b) 15 cm
(c) 20 cm
(d) 10 cm


A student has obtained an image of a well-illuminated distant object on a screen to determine the focal length, F1of the given spherical mirror. The teacher then gave him another mirror of focal length, F2 and asked him to obtain a focused image of the same object on the same screen. The student found that in order to focus the same object using the second mirror, he has to move the mirror away from the screen. From this observation, it may be concluded that both the spherical mirrors given to the student were (select the correct option)

(A) Concave and F1 < F2

(B) Concave and F1 > F2

(C) Convex and F1 < F2

(D) Convex and F1 > F2


The image formed by a concave mirror is virtual, erect and magnified. The position of object is:

(a) at focus
(b) between focus and centre of curvature
(c) at pole
(d) between pole and focus


The image formed by a concave mirror is real, inverted and of the same size as the object. The position of the object must then be:

(a) at the focus
(b) between the centre of curvature and focus
(c) at the centre of curvature
(d) beyond the centre of curvature


What sign (+ve or −ve) has been given to the following on the basis of Cartesian Sign Convention?

  1. Height of a real image.
  2. Height of a virtual image.

According to New Cartesian Sign Convention:

(a) focal length of concave mirror is positive and that of convex mirror is negative
(b) focal length of both concave and convex mirrors is positive
(c) focal length of both concave and convex mirrors is negative
(d) focal length of concave mirror is negative and that of convex mirror is positive


What is the nature of image formed by a concave mirror if the magnification produced by the mirror  

 +4 


A dentist's mirror has a radius of curvature of 3 cm. How far must it be placed from a small dental cavity to give a virtual image of the cavity that is magnified five times?


An object 20 cm from a spherical mirror gives rise to virtual image 15 cm behind the mirror. Determine the magnification of the image and the type of mirror used. 


A virtual, erect and magnified image of an object is to be obtained with a convex lens. For this purpose,the object should be placed:

(a) between 2F and infinity
(b) between F and optical centre
(c) between F and 2F
(d) at F


If a magnification of, –1 (minus 1) is obtained by using a converging lens, then the object has to be placed:
(a) within f
(b) at 2f
(c) beyond 2f
(d) at infinity


An object is 0.09 m from a magnifying lens and the image is formed 36 cm from the lens. The magnification produced is:
(a) 0.4
(b) 1.4
(c) 4.0
(d) 4.5 


To obtain a magnification of, –2 with a convex lens of focal length 10 cm, the object should be placed:
(a) between 5 cm and 10 cm
(b) between 10 cm and 20 cm
(c) at 20 cm
(d) beyond 20 cm


A magnifying lens has a focal length of 100 mm. An object whose size is 16 mm is placed at some distance from the lens so that an image is formed at a distance of 25 cm in front of the lens.

  1. What is the distance between the object and the lens?
  2. Where should the object be placed if the image is to form at infinity?

The magnification produced by a spherical lens and a spherical mirror is + 2.0.
(a) The lens and mirror are both concave
(b) The lens and mirror are both convex
(c) The lens is convex but the mirror is concave
(d) The lens is concave but the mirror is convex


An image formed on a screen is three times the size of the object. The object and screen are 80 cm apart when the image is sharply focussed. 

 Calculate focal length of the lens.


An object of height 7 cm is kept at a distance of 25 cm in front of a concave mirror. The focal length of the mirror is 15 cm. At what distance from the mirror should a screen be kept so as to get a clear image? What will be the size and nature of the image?


What is meant by magnification? Write its expression. What is its sign for real image and virtual image?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×