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A committee of 7 peoples has to be formed from 8 men and 4 women. In how many ways can this be done when the committee consists of at least 3 women? - Mathematics

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प्रश्न

A committee of 7 peoples has to be formed from 8 men and 4 women. In how many ways can this be done when the committee consists of at least 3 women?

योग
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उत्तर

Number of men = 8

Number of women = 4

Number of peoples in the committee = 7

At least 3 women

The 7 members committee must contain at least 3 women

∴ We have the following possibilities

(i) 4 women + 3 men

(ii) 3 women + 4 men

Case (i): 4 women + 3 men

The number ways of selecting 4 women .from

4 women is = 4C4 = 1 way

The number of ways of selecting 3 men from 8 men = 8C

= `(8!)/(3! xx (8 - 3)!)`

= `(8!)/(3! xx 5!)`

= `(8 xx 7 xx 6 xx 5!)/(3!xx 5!)`

= `(8 xx 7 xx 6)/(3 xx 2 xx 1)`

= 8 × 7

= 56

∴ The total number of ways = 1 × 56 = 56

Case (ii): 3 women + 4 men

The number of ways of selecting 3 women from 4 women is = 4C3

The number of ways of selecting 4 men from 8 men is = 8C4

∴ The total number of ways = 4C3 × 8C

= `(4!)/(3! xx (4 - 3)!) xx (8!)/(4!(8 - 4)!)`

= `(4!)/(3! xx 1!) xx (8!)/(4! xx 4!)`

= `(4 xx 3!)/(3!) xx (8 xx 7 xx 6 xx 5 xx 4!)/(4! xx 4!)`

= `(4 xx 8 xx 7 xx 6 xx 5)/(4!)`

= `(4 xx 8 xx 7 xx 6 xx 5)/(4 xx 3 xx 2 xx 1)`

= 8 × 7 × 5 = 280

∴ The required number of ways of forming the committee = 56 + 280 = 336

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Combinations
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Combinatorics and Mathematical Induction - Exercise 4.3 [पृष्ठ १८७]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 4 Combinatorics and Mathematical Induction
Exercise 4.3 | Q 18. (ii) | पृष्ठ १८७

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