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प्रश्न
A coin kept inside water [µ = 4/3] when viewed from air in a vertical direction appears to be raised by 3.0 mm. Find the depth of the coin in water.
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उत्तर
Using the relation,
Refractive index = `"Real depth"/"Apparent depth"`
∴ `4/3=("RD")/("RD"-"shift")`
∴ 4(RD - Shift) = 3(RD)
∴ RD = 4 (Shift)
= 4(3)
= 12 mm
Hence, depth of coin in water = 12 mm and length of the image of coin in water
= 12 - 3 = 9 mm.
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संबंधित प्रश्न
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