Advertisements
Advertisements
प्रश्न
A bulb is connected to a battery of e.m.f. 6V and internal resistance 2Ω A steady current of 0.5A flows through the bulb. Calculate the resistance of the bulb.
Advertisements
उत्तर
Given: E = 6V, r = 2Ω, i = 0.5A, t = 10 minute = 10 × 60s = 600s.
Let the resistance of bulb is R. Then i =`"E"/("R + r")`
or `0.5 = 6/("R" + 2)` or 0.5 (E + 2) = 6
or 0.5 R + 1 = 6 or 0.5 R = 6 - 1 = 5
or R = `5/0.5 = 10 Omega`
संबंधित प्रश्न
1 kWh = ________ J
An electric motor takes 5 amperes current form a 220 volt supply line. Calculate the power of the motor and electric energy consumed by it in 2 hours.
How many joules are there in one kilowatt-hour?
A simple electric circuit has 24 V battery and a resistor of 60 Ω. What will be the current in the circuit? The resistance of the connecting wires is negligible.
State three factors on which the heat produced in a metallic wire due to passage of current in it depends.
State other bigger units of electric power and express them in watt.
A. bulb is rated at 100W, 250V and another one at 60W, 250V. What is the current flowing in the circuit if the two bulbs are put in series across a 220 V mains supply?
The electrical power and current in the circuit relates by ______
