Question

A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is Not black

Answer 1

Total no. of possible outcomes = 8 + 6 + 4 = 18 {8 red, 6 white, 4 black}

E ⟶ event of getting no black ball

No. of favourable outcomes = 4 {4 black balls}

Probability, P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`

P(E) = 4/18 = 2/9

(`barE`) ⟶ 𝑒𝑣𝑒𝑛𝑡 𝑜𝑓 𝑛𝑜𝑡 𝑔𝑒𝑡𝑡𝑖𝑛𝑔 𝑏𝑙𝑎𝑐𝑘 𝑏𝑎𝑙𝑙

P(`barE`) = 1 − 𝑃(𝐸)

= 1 − 2/9 = 7/9