Question

`9x^2+6x+1=0`

Answer 1

`9x^2+6x+1=0` 

`⇒ 9x^2+3x+3x+1=0` 

`⇒3x(3x+1)+1(3x+1)=0` 

`⇒(3x+1) (3x+1)=0` 

`⇒ 3x+1=0  or  3x+1=0` 

`⇒ x=(-1)/3  or  x(-1)/3` 

Hence, `(-1)/3`is the root of the equation `9x^2+6x+1=0`