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प्रश्न
63.2 g of copper at 50°C can just melt 3.8g of ice. If the specific latent heat of ice is 336 J/g, find the specific heat capacity of copper.
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उत्तर
Let the specific heat capacity of copper be s
∴ Heat lost by copper = 63.2 × s × (50 - 0) = 3160 s joule
Heat gained by ice = 3.8 × 336 joule
Since Heat gained = Heat lost
We have 3160s = 3.8 × 336 = 1276.8
Or s = (1276.8/3160) K/g °C = 0.404 J/g °C.
संबंधित प्रश्न
A refrigerator converts 100 g of water at 20°C to ice at -10°C in 35 minutes. Calculate the average rate of heat extraction in terms of watts.
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Specific heat capacity of water = 4.2 J g-1°C-1
Specific latent heat of fusion of ice = 336 J g-1
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