Question

`48x^2-13x1=0` 

 

Answer 1

Given: 

`48x^2-13x-1=0` 

⇒` 48x^2-(16x-3x)-1=0` 

⇒`48x^2-16x+3x-1=0` 

⇒`16x(3x-1)+1(3x-1)=0` 

⇒`(16x+1)(3x-1)=0` 

⇒`16x+1=0  or  3x-1=0` 

⇒`x=-1/16  or  x=1/3` 

Hence, the roots of the equation are `-1/16` and `1/3`