Question

40000 litre of oil of density 0.9 g/cc is pumped from an oil tanker ship into a storage tank at 10 m higher level than the ship in half an hour. What should be the power of the pump?

Answer 1

Given:
h = 10 m, ρ = 0.9 g/cc = 900 kg/m³, g = 10 m/s²,

V = 40000 litre = 40000 × 10³ × 10^-6 m³ = 40 m³

T = 30 min = 1800 s

To find: Power(P)

Formula: P = `"W"/"t" = ("h"rho"gV")/"t"`

Calculation: From formula,

P = `(10 xx 900 xx 10 xx 40)/1800`

∴ P = 2000 W

∴ P = 2 kW

The power of the pump is 2 kW.