Question

`3x^2x-1=0` 

Answer 1

We Write, `-2x=-3x+x   as   3x^2xx(-1)=-3x^2=(-3x)xx x` 

∴` 3x^2-2x-1=0`

⇒`3x^2-3x+x-1=0` 

⇒`3x(x-1)+1(x-1)=0` 

⇒`(x-1)(3x+1)=0` 

⇒`x-1=0  or  3x+1=0` 

`⇒x=1 or x=-1/3` 

Hence, the roots of the given equation are 1 and -1/3