Question

`3x^2-2x-1=0` 

Answer 1

`3x^2-2x-1=0`  

⇒`9x^2-6x-3=0`              (Multiplying both sides by 3)

`9x^2-6x-3=0 ` 

`(3x)^2-2xx3x xx1+1^2=3+1^2`                [Adding `1^2` on both sides]

`(3x-1)^2=3+1=4(2)^2` 

`3x-1=+-2`                          (Taking square root on both sides) 

`3x-1=2  or  3x-1=-2` 

`3x=3  or  3x=-1` 

`x=1  or  x=-1/3` 

Hence, 1 and `-1/3` are the roots of the given equation.