Question

`(2x-3) (3x+1)=0` 

 

 

Answer 1

⇒ (2x-3) (3x+1)=0  

`⇒2x-3=0 or 3x+1=0` 

`⇒2x=3 or 3x=-1`  

`⇒x=3/2 or x-1/3` 

Hence the roots of the given equation are` 3/2 and -1/3`