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प्रश्न
2875 J of heat is required to melt 115 g of lead at its melting point. Calculate the specific latent heat capacity of fusion of lead.
संक्षेप में उत्तर
उत्तर
Mass of lead m = 115 g
Heat required Q = 2875 J
Specific latent heat of lead L =?
We know that Q = m L
L = \(\frac{Q}{m}=\frac{2875}{115}\)
= 25 Jg-1
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