Question

20 g of ice at 0°C absorbs 10,920 J of heat energy to melt and change to water at 50°C. Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200 J kg^-1 K^-1.

Answer 1

Let Specific Latent heat of fusion of ice = L

Heat required to change ice at 0° C to water 0°C + water 50°C

∴ Heat required = `20"L" + 20 xx 4200/1000 xx (50 - 0)`

= 10,920

Q = 20L + 4200

= 10,920

20L = 6720

L = `6720/20`

= 336 J g^-1