Question

`2/x^2-5/x+2=0` 

Answer 1

`2/x^2-5/x+2=0` 

⇒`2-5x+2x^2=0`                    [Multiplying both sides by  `x^2` ]  

⇒`2x^-5x+2=0` 

⇒`2x^2-(4x+x)+2=0` 

⇒`2x^2-4x-x+2=0` 

⇒`2x(x-2)-1(x-2)=0` 

⇒`(2x-1) (x-2)=0` 

⇒`2x=1=0  or  x-2=0` 

⇒ `x=1/2 or x=2` 

Hence, the roots of the equation are `1/2` and 2.