∫ 1 ( 7 X − 5 ) 3 + 1 √ 5 X − 4 D X - Mathematics

प्रश्न

\[\int\frac{1}{\left( 7x - 5 \right)^3} + \frac{1}{\sqrt{5x - 4}} dx\]

योग

उत्तर

\[\int\left[ \frac{1}{\left( 7x - 5 \right)^3} + \frac{1}{\sqrt{5x - 4}} \right]dx\]
\[ = \int\left[ \left( 7x - 5 \right)^{- 3} + \left( 5x - 4 \right)^{- \frac{1}{2}} \right]dx\]
\[ = \frac{\left( 7x - 5 \right)^{- 3 + 1}}{7\left( - 3 + 1 \right)} + \frac{\left( 5x - 4 \right)^{- \frac{1}{2} + 1}}{5\left( - \frac{1}{2} + 1 \right)} + C\]
\[ = \frac{\left( 7x - 5 \right)^{- 2}}{- 14} + \frac{2}{5} \left( 5x - 4 \right)^\frac{1}{2} + C\]

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Indefinite Integral Problems

क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

Q 2 Q 1 Q 3

अध्याय 19: Indefinite Integrals - Exercise 19.03 [पृष्ठ २३]

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आरडी शर्मा Mathematics [English] Class 12

अध्याय 19 Indefinite Integrals
Exercise 19.03 | Q 2 | पृष्ठ २३

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Indefinite Integral Problems

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