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प्रश्न
0.25 gram of a organic compound gave 31.1 mL N2 by Duma method % of nitrogen will be ______.
विकल्प
18.55
15.55
21.45
31.56
MCQ
रिक्त स्थान भरें
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उत्तर
0.25 gram of a organic compound gave 31.1 mL N2 by Duma method % of nitrogen will be 15.55.
Explanation:
Wt of organic compound = 0.25 gram volume of nitrogen = 31.1
\[\%\mathrm{N}=\frac{28\times\mathrm{V}\quad100}{22400\times w}=\frac{0.125\times\mathrm{V}}{w}\]
\[=\frac{0.125\times31.1}{0.25}=15.55\%\]
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