Tamil Nadu Board of Secondary EducationHSC Science Class 11th
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Tamil Nadu Board Samacheer Kalvi solutions for Class 11th Chemistry Volume 1 and 2 Answers Guide chapter 9 - Solutions [Latest edition]

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Class 11th Chemistry Volume 1 and 2 Answers Guide - Shaalaa.com
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Chapter 9: Solutions

Choose the best answerWrite brief answer to the following questions.
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Choose the best answer [Pages 61 - 64]

Tamil Nadu Board Samacheer Kalvi solutions for Class 11th Chemistry Volume 1 and 2 Answers Guide Chapter 9 SolutionsChoose the best answer [Pages 61 - 64]

Choose the best answer | Q I. 1. | Page 61

The molality of a solution containing 1.8 g of glucose dissolved in 250 g of water is

  • 0.2 M

  • 0.01 M

  • 0.02 M

  • 0.04 M

Choose the best answer | Q I. 2. | Page 61

Which of the following concentration terms is/are independent of temperature

  • molality

  • molarity

  • mole fraction

  • molality and molarity

Choose the best answer | Q I. 3. | Page 61

Stomach acid, a dilute solution of HCl can be neutralized by reaction with aluminium hydroxide \[\ce{Al(OH)3 + 3HCl (aq) -> AlCl3 + 3H2O}\]

How many milliliters of 0.1 M Al(OH)3 solution is needed to neutralize 21 ml of 0.1 M HCl?

  • 14 mL

  • 7 mL

  • 21 mL

  • none of these

Choose the best answer | Q I. 4. | Page 61

The partial pressure of nitrogen in air is 0.76 atm and its Henry’s law constant is 7.6 × 104 atm at 300 K. What is the mole fraction of nitrogen gas in the solution obtained when air is bubbled through water at 300 K?

  • 1 × 10-4

  • 1 × 104

  • 2 × 10-5

  • 1 × 10-5

Choose the best answer | Q I. 5. | Page 61

Henry’s law constant for the solubility of Nitrogen gas in water at 350 K is 8 × 104 atm. The mole fraction of nitrogen in air is 0.5. The number of moles of Nitrogen from air dissolved in 10 moles of water at 350 K and 4 atm pressure is

  • 4 × 10-4

  • 4 × 104

  • 2 × 10-2

  • 2.5 × 10-4

Choose the best answer | Q I. 6. | Page 61

Which one of the following is incorrect for an ideal solution?

  • ∆Hmix = 0

  • ∆Umix = 0

  • ∆P = `"P"_"observed"  -  "P"_"calculated by Raoults law" = 0`

  • ∆Gmix = 0

Choose the best answer | Q I. 7. | Page 61

Which one of the following gases has the lowest value of Henry’s law constant?

  • N2

  • He

  • CO2

  • H2

Choose the best answer | Q I. 8. | Page 62

P1 and P2 are the vapour pressures of pure liquid components, 1 and 2 respectively of an ideal binary solution If x1 represents the mole fraction of component 1, the total pressure of the solution formed by 1 and 2 will be

  • P1 + x1 (P2 – P1)

  • P2 – x1 (P2 + P1)

  • P1 – x2(P1 – P2)

  • P1 + x2(P1 – P2)

Choose the best answer | Q I. 9. | Page 62

Osomotic pressure (π) of a solution is given by the relation

  • π = nRT

  • πV = nRT

  • πRT = n

  • none of these

Choose the best answer | Q 10. | Page 62

Which one of the following binary liquid mixtures exhibits positive deviation from Raoults law?

  • Acetone + chloroform

  • Water + nitric acid

  • HCl + water

  • ethanol + water

Choose the best answer | Q I. 11. | Page 62

The Henry’s law constants for two gases A and B are x and y respectively. The ratio of mole fractions of A to B 0.2. The ratio of mole fraction of B and A dissolved in water will be

  • `(2x)/"y"`

  • `"y"/(0.2 x)`

  • `(0.2 x)/"y"`

  • `(5x)/"y"`

Choose the best answer | Q I. 12. | Page 62

At 100°C the vapour pressure of a solution containing 6.5g a solute in 100g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be

  • 102°C

  • 100°C

  • 101°C

  • 100.52°C

Choose the best answer | Q I. 13. | Page 62

According to Raoults law, the relative lowering of vapour pressure for a solution is equal to ______.

  • mole fraction of solvent

  • mole fraction of solute

  • number of moles of solute

  • number of moles of solvent

Choose the best answer | Q I. 14. | Page 62

At same temperature, which pair of the following solutions are isotonic?

  • 0.2 M BaCl2 and 0.2 M urea

  • 0.1 M glucose and 0.2 M urea

  • 0.1 M NaCl and 0.1 M K2SO4

  • 0.1 M Ba(NO3)2 and 0.1 M Na2SO4

Choose the best answer | Q I. 15. | Page 62

The empirical formula of a nonelectrolyte(X) is CH2 O. A solution containing six gram of X exerts the same osmotic pressure as that of 0.025M glucose solution at the same temperature. The molecular formula of X is

  • C2H4O2

  • C8H16O8

  • C4H8O4

  • CH2O

Choose the best answer | Q I. 16. | Page 62

The KH for the solution of oxygen dissolved in water is 4 × 104 atm at a given temperature. If the partial pressure of oxygen in air is 0.4 atm, the mole fraction of oxygen in solution is ______.

  • 4.6 × 103

  • 1.6 × 104

  • 1 × 10-5

  • 1 × 105

Choose the best answer | Q I. 17. | Page 62

Normality of 1.25M sulphuric acid is ______.

  • 1.25 N

  • 3.75 N

  • 2.5 N

  • 2.25 N

Choose the best answer | Q I. 18. | Page 62

Two liquids X and Y on mixing gives a warm solution. The solution is ______.

  • ideal

  • non-ideal and shows positive deviation from Raoults law

  • ideal and shows negative deviation from Raoults Law

  • non-ideal and shows negative deviation from Raoults Law

Choose the best answer | Q I. 19. | Page 63

The relative lowering of vapour pressure of a sugar solution in water is 2.5 × 10-3. The mole fraction of water in that solution is ______.

  • 0.0035

  • 0.35

  • 0.0035/18

  • 0.9965

Choose the best answer | Q I. 20. | Page 63

The mass of a non – volatile solute (molar mass 80 g mol-1) should be dissolved in 92g of toluene to reduce its vapour pressure to 90% ______.

  • 10 g

  • 20 g

  • 9.2 g

  • 8 g

Choose the best answer | Q I. 21. | Page 63

For a solution, the plot of osmotic pressure (π) versus the concentration (c in mol L-1) gives a straight line with slope 310 R where ‘R’ is the gas constant. The temperature at which osmotic pressure measured is ______.

  • 310 × 0.082 K

  • 310° C

  • 37°C

  • `310/0.082`K

Choose the best answer | Q I. 22. | Page 63

200 ml of an aqueous solution of a protein contains 1.26 g of protein. At 300 K, the osmotic pressure of this solution is found to be 2.52 × 10-3 bar. The molar mass of protein will be (R = 0.083 L bar mol-1 K-1)

  • 62.22 kg mol-1

  • 12444 g mol-1

  • 300 g mol-1

  • None of these

Choose the best answer | Q I. 23. | Page 63

The Van't Hoff factor (i) for a dilute aqueous solution of the strong elecrolyte barium hydroxide is (NEET) ______.

  • 0

  • 1

  • 2

  • 3

Choose the best answer | Q I. 24. | Page 63

Which is the molality of a 10% w/w aqueous sodium hydroxide solution?

  • 2.778

  • 2.5

  • 10

  • 0.4

Choose the best answer | Q I. 25. | Page 63

The correct equation for the degree of an associating solute, ‘n’ molecules of which undergoes association in solution, is

  • α = `("n"("i" - 1))/("n - 1")`

  • α2 = `("n"(1 - "i"))/("n - 1")`

  • α = `("n"("i" - 1))/("1 - n")`

  • α = `("n"(1 - "i"))/("n"("1 - i"))`

Choose the best answer | Q I. 26. | Page 63

Which of the following aqueous solutions has the highest boiling point?

  • 0.1 M KNO3

  • 0.1 M Na3PO4

  • 0.1 M BaCl2

  • 0.1 M K2SO4

Choose the best answer | Q I. 27. | Page 63

The freezing point depression constant for water is 1.86° K Kg mol-1. If 5 g Na2SO4 is dissolved in 45 g water, the depression in freezing point is 3.64°C. The Vant Hoff factor for Na2SO4 is ______.

  • 2.57

  • 2.63

  • 3.64

  • 5.50

Choose the best answer | Q I. 28. | Page 63

Equimolal aqueous solutions of NaCl and KCl are prepared, If the freezing point of NaCl is -2°C, the freezing point of KCl solution is expected to be ______.

  • -2°C

  • -4°C

  • -1°C

  • 0°C

Choose the best answer | Q I. 29. | Page 63

Phenol dimerizes in benzene having van’t Hoff factor 0.54. What is the degree of association?

  • 0.46

  • 92

  • 46

  • 0.92

Choose the best answer | Q I. 30. | Page 64

Assertion: An ideal solution obeys Raoults Law.

Reason: In an ideal solution, solvent – solvent as well as solute – solute interactions are similar to solute-solvent interactions.

  • Both assertion and reason are true and reason is the correct explanation of assertion

  • Both assertion and reason are true but reason is not the correct explanation of assertion.

  • Assertion is true but reason is false

  • Both assertion and reason are false

Write brief answer to the following questions. [Page 64]

Tamil Nadu Board Samacheer Kalvi solutions for Class 11th Chemistry Volume 1 and 2 Answers Guide Chapter 9 SolutionsWrite brief answer to the following questions. [Page 64]

Write brief answer to the following questions. | Q II. 1. (i) | Page 64

Define molality.

Write brief answer to the following questions. | Q II. 1. (ii) | Page 64

Define Normality.

Write brief answer to the following questions. | Q II. 2. | Page 64

What is a vapour pressure of liquid?

Write brief answer to the following questions. | Q II. 2. | Page 64

What is a relative lowering of vapour pressure?

Write brief answer to the following questions. | Q II. 3. | Page 64

State and explain Henry’s law.

Write brief answer to the following questions. | Q II. 4. | Page 64

State Raoult law and obtain the expression for lowering of vapour pressure when the nonvolatile solute is dissolved Insolvent.

Write brief answer to the following questions. | Q II. 5. | Page 64

What is molal depression constant? Does it depend on nature of the solute?

Write brief answer to the following questions. | Q II. 6. | Page 64

What is osmosis?

Write brief answer to the following questions. | Q II. 7. | Page 64

Define isotonic solutions

Write brief answer to the following questions. | Q II. 8. | Page 64

You are provided with a solid ‘A’ and three solutions of A dissolved in water – one saturated, one unsaturated, and one super saturated. How would you determine each solution?

Write brief answer to the following questions. | Q II. 9. | Page 64

Explain the effect of pressure on solubility.

Write brief answer to the following questions. | Q II. 10. | Page 64

A sample of 12 M Concentrated hydrochloric acid has a density 1.2 M gL-1 calculate the molality.

Write brief answer to the following questions. | Q II. 11. | Page 64

A 0.25 M glucose solution, at 370.28 K has approximately the pressure as blood does what is the osmotic pressure of blood?

Write brief answer to the following questions. | Q II. 12. | Page 64

Calculate the molality of a solution containing 7.5 g glycine(NH2-CH2-COOH) dissolved in 500g of water.

Write brief answer to the following questions. | Q II. 13. | Page 64

Which solution has the lower freezing point? 10 g of methanol (CH3OH) in 100g g of water (or) 20 g of ethanol (C2H5OH) in 200 g of water.

Write brief answer to the following questions. | Q II. 14. | Page 64

How many moles of solute particles are present in one liter of 10-4 M potassium sulphate?

Write brief answer to the following questions. | Q II. 15. | Page 64

Henry’s law constant for solubility of methane in benzene is 4.2 × 10-5 mm Hg at a particular constant temperature. At this temperature calculate the solubility of methane at

  1. 750 mm Hg
  2. 840 mm Hg.
Write brief answer to the following questions. | Q II. 16. | Page 64

The observed depression in the freezing point of water for a particular solution is 0.093°C calculate the concentration of the solution in molality. Given that molal depression constant for water is 1.86 K Kg mol-1.

Write brief answer to the following questions. | Q II. 17. | Page 64

The vapour pressure of pure benzene (C6H6) at a given temperature is 640 mm Hg. 2.2 g of non – volatile solute is added to 40 g of benzene. The vapour pressure of the solution is 600 mm Hg. Calculate the molar mass of the solute?

Chapter 9: Solutions

Choose the best answerWrite brief answer to the following questions.
Class 11th Chemistry Volume 1 and 2 Answers Guide - Shaalaa.com

Tamil Nadu Board Samacheer Kalvi solutions for Class 11th Chemistry Volume 1 and 2 Answers Guide chapter 9 - Solutions

Tamil Nadu Board Samacheer Kalvi solutions for Class 11th Chemistry Volume 1 and 2 Answers Guide chapter 9 (Solutions) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the Tamil Nadu Board of Secondary Education Class 11th Chemistry Volume 1 and 2 Answers Guide solutions in a manner that help students grasp basic concepts better and faster.

Further, we at Shaalaa.com provide such solutions so that students can prepare for written exams. Tamil Nadu Board Samacheer Kalvi textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.

Concepts covered in Class 11th Chemistry Volume 1 and 2 Answers Guide chapter 9 Solutions are Abnormal Molar Masses, Solutions, Types of Solutions, Expressing Concentration of Solutions, Solubility of the Solutes, Henry's Law, Vapour Pressure of Liquid Solutions - Introduction, Vapour Pressure of Liquid, Ideal and Non-ideal Solutions, Colligative Properties, Reverse Osmosis (RO).

Using Tamil Nadu Board Samacheer Kalvi Class 11th solutions Solutions exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in Tamil Nadu Board Samacheer Kalvi Solutions are important questions that can be asked in the final exam. Maximum students of Tamil Nadu Board of Secondary Education Class 11th prefer Tamil Nadu Board Samacheer Kalvi Textbook Solutions to score more in exam.

Get the free view of chapter 9 Solutions Class 11th extra questions for Class 11th Chemistry Volume 1 and 2 Answers Guide and can use Shaalaa.com to keep it handy for your exam preparation

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