Tamil Nadu Board of Secondary EducationHSC Science Class 11th
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Tamil Nadu Board Samacheer Kalvi solutions for Class 11th Chemistry Volume 1 and 2 Answers Guide chapter 10 - Chemical bonding [Latest edition]

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Class 11th Chemistry Volume 1 and 2 Answers Guide - Shaalaa.com
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Chapter 10: Chemical bonding

Choose the best answerWrite brief answer to the following questions.
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Choose the best answer [Pages 104 - 106]

Tamil Nadu Board Samacheer Kalvi solutions for Class 11th Chemistry Volume 1 and 2 Answers Guide Chapter 10 Chemical bondingChoose the best answer [Pages 104 - 106]

Choose the best answer | Q I. 1. | Page 104

In which of the following Compounds does the central atom obey the octet rule?

  • XeF4

  • AlCl3

  • SF6

  • SCl2

Choose the best answer | Q I. 2. | Page 104

In the molecule OA = C = OB, the formal charge on OA, C and OB are respectively.

  • -1, 0, +1

  • +1, 0, -1

  • -2, 0, +2

  • 0, 0, 0

Choose the best answer | Q I. 3. | Page 104

Which of the following is electron deficient?

  • PH3

  • (CH3)2

  • BH3

  • NH3

Choose the best answer | Q I. 4. | Page 104

Which of the following molecule contain no л bond?

  • SO2

  • SO2

  • CO2

  • H2O

Choose the best answer | Q I. 5. | Page 104

The ratio of number of sigma (σ) and pi (л) bonds in 2- butynal is ______.

  • `8/3`

  • `5/3`

  • `8/2`

  • `9/2`

Choose the best answer | Q I. 6. | Page 104

Which one of the following is the likely bond angles of sulphur tetrafluoride molecule?

  • 120°, 80°

  • 109°28’

  • 90°

  • 89°, 117°

Choose the best answer | Q I. 7. | Page 104

Assertion: Oxygen molecule is paramagnetic.

Reason: It has two unpaired electron in its bonding molecular orbital.

  • Both assertion and reason are true and reason is the correct explanation of assertion

  • Both assertion and reason are true but reason is not the correct explanation of assertion

  • Assertion is true but reason is false

  • Both assertion and reason are false

Choose the best answer | Q I. 8. | Page 104

According to Valence bond theory, a bond between two atoms is formed when ______.

  • fully filled atomic orbitals overlap

  • half-filled atomic orbitals overlap

  • non – bonding atomic orbitals overlap

  • empty atomic orbitals overlap

Choose the best answer | Q I. 9. | Page 104

In ClF3, NF3 and BF3 molecules the chlorine, nitrogen and boron atoms are ______.

  • sp3 hybridised

  • sp3, sp3 and sp2 respectively

  • sp3 hybridised

  • sp3d, sp3 and sp hybridised respectively

Choose the best answer | Q I. 10. | Page 104

When ones and three p orbitals hybridise,

  • four equivalent orbitals at 90° to each other will be formed

  • four equivalent orbitals at 109°28’ to each other will be formed

  • four equivalent orbitals, that are lying the same plane will be formed

  • none of these

Choose the best answer | Q I. 11. | Page 105

Which of these represents the correct order of their increasing bond order.

  • C2+ < C22- < O22- < O2

  • C22- < C2+ < O2 < O22-

  • O22- < O2 < C22- < C2+

  • O22- < C2+ < O2 < C22-

Choose the best answer | Q I. 12. | Page 105

Hybridisation of central atom in PCl5 involves the mixing of orbitals.

  • s, Px, Py, dx2, `"d"_("x"^2 – "y"^2)`

  • s, px, py, pxy, `"d"_("x"^2 – "y"^2)`

  • s, px, py, pz, `"d"_("x"^2 – "y"^2)`

  • s, px, Py, dxy, `"d"_("x"^2 – "y"^2)`

Choose the best answer | Q I. 13. | Page 105

The correct order of O – O bond length in hydrogen peroxide, ozone and oxygen is

  • H2O2 > O3 > O2

  • O2 > O3 > H2O2

  • O2 > H2O2 > O3

  • O3 > O2 > H2O2

Choose the best answer | Q I. 14. | Page 105

Which one of the following is diamagnetic?

  • O2

  • O22-

  • O2+

  • None of these

Choose the best answer | Q I. 15. | Page 105

Bond order of a species is 2.5 and the number of electons in its bonding molecular orbital is formd to be 8 The no. of electons in its antibonding molecular orbital is

  • three

  • four

  • Zero

  • can not be calculated from the given information.

Choose the best answer | Q I. 16. | Page 105

Shape and hybridisation of IF5 are ______.

  • Trigonal bipyramidal, sp3d2

  • Trigonal bipyramidal, sp3d

  • Square pyramidal, sp3d2

  • Octahedral, sp3d2

Choose the best answer | Q I. 17. | Page 105

Pick out the incorrect statement from the following:

  • sp3 hybrid orbitals are equivalent and are at an angle of 109°28’ with each other

  • dsp2 hybrid orbitals are equivalent and bond angle between any two of them is 90°

  • All five sp3d hybrid orbitals are not equivalent out of these five sp3d hybrid orbitals, three are at an angle of 120° remaining two are perpendicular to the plane containing the other three

  • none of these

Choose the best answer | Q I. 18. | Page 105

The molecules having same hybridisation, shape and number of lone pairs of electons are ______.

  • SeF4, XeO2F2

  • SF4, XeF2

  • XeOF4, TeF4

  • SeCl4, XeF4

Choose the best answer | Q I. 19. | Page 105

In which of the following molecules / ions BF3, NO2 H20 the central atom is sp2 hybridised?

  • NH2 and H2O

  • NO2 and H2O

  • BF3 and NO2

  • BF3 and NH2

Choose the best answer | Q I. 20. | Page 106

Some of the following properties of two species, NO3 and H3O+ are described below. Which one of them is correct?

  • dissimilar in hybridization for the central atom with different structure.

  • isostructural with same hybridisation for the central atom.

  • different hybridisation for the central atom with same structure.

  • none of these

Choose the best answer | Q I. 21. | Page 106

The types of hybridiration on the five carbon atom from right to left in the, 2,3 pentadiene.

  • sp3, sp2, sp, sp2, sp3

  • sp3, sp, sp, sp, sp3

  • sp2, sp, sp2, sp2, sp3

  • sp3, sp3, sp2, sp3, sp3

Choose the best answer | Q I. 22. | Page 106

XeF2 is isostructural with ______.

  • SbCl2

  • BaCl2

  • TeF2

  • ICl2

Choose the best answer | Q I. 23. | Page 106

The percentage of s-character of the hybrid orbitals in methane, ethane, ethene and ethyne are respectively.

  • 25, 25, 33.3, 50

  • 50, 50, 33.3, 25

  • 50, 25, 33.3, 50

  • 50, 25, 25, 50

Choose the best answer | Q I. 24. | Page 106

Of the following molecules, which have shape similar to carbon dioxide?

  • SnCl2

  • NO2

  • C2H2

  • All of these

Choose the best answer | Q I. 25. | Page 106

According to VSEPR theory, the repulsion between different parts of electrons obey the order.

  • l.p – l.p > b.p–b.p> l.p–b.p

  • b.p–b.p> b.p–l.p> l.p–b.p

  • l.p–l.p> b.p–l.p > b.p–b.p

  • b.p–b.p> l.p–l.p> b.p–l.p

Choose the best answer | Q I. 26. | Page 106

Shape of ClF3 is ______.

  • Planar triangular

  • Pyramidal

  • "T” Shaped

  • none of these

Choose the best answer | Q I. 27. | Page 106

Non – Zero dipole moment is shown by ______.

  • CO2

  • p – dichlorobenzene

  • carbon tetrachloride

  • water

Choose the best answer | Q I. 28. | Page 106

Which of the following conditions is not correct for resonating structures?

  • the contributing structure must have the same number of unpaired electrons

  • the contributing structures should have similar energies

  • the resonance hybrid should have higher energy than any of the contributing structure.

  • none of these

Choose the best answer | Q I. 29. | Page 106

Among the following, the compound that contains, ionic, covalent and Coordinate linkage is ______.

  • NH4Cl

  • NH3

  • NaCl

  • none of these

Choose the best answer | Q I. 30. | Page 106

CaO and NaCl have the same crystal structure and approximately the same radii. If U is the lattice energy of NaCl, the approximate lattice energy of CaO is ______.

  • U

  • 2U

  • `"U"/2`

  • 4U

Write brief answer to the following questions. [Pages 106 - 107]

Tamil Nadu Board Samacheer Kalvi solutions for Class 11th Chemistry Volume 1 and 2 Answers Guide Chapter 10 Chemical bondingWrite brief answer to the following questions. [Pages 106 - 107]

Write brief answer to the following questions. | Q II. 1. i) | Page 106

Define bond order.

Write brief answer to the following questions. | Q II. 1. ii) | Page 107

Define Hybridisation.

Write brief answer to the following questions. | Q II. 1. iii) | Page 107

Define σ – bond.

Write brief answer to the following questions. | Q II. 2. | Page 107

What is a pi - bond?

Write brief answer to the following questions. | Q II. 3. | Page 107

In CH4, NH3, and H2O, the central atom undergoes sp3 hybridization – yet their bond angles are different. Why?

Write brief answer to the following questions. | Q II. 4. | Page 107

Explain Sp2 hybridization in BF3.

Write brief answer to the following questions. | Q II. 5. | Page 107

Draw the M.O diagram for oxygen molecule calculate its bond order and show that O2 is paramagnetic.

Write brief answer to the following questions. | Q II. 6. | Page 107

Draw MO diagram of CO and calculate its bond order.

Write brief answer to the following questions. | Q II. 7. | Page 107

What do you understand by Linear combination of atomic orbitals in MO theory?

Write brief answer to the following questions. | Q II. 8. | Page 107

Discuss the formation of N2 molecule using MO Theory.

Write brief answer to the following questions. | Q II. 9. | Page 107

What is dipole moment?

Write brief answer to the following questions. | Q I. 10. | Page 107

Linear form of carbondioxide molecule has two polar bonds. Yet the molecule has Zero dipole moment. Why?

Write brief answer to the following questions. | Q II. 11. i) | Page 107

Draw the Lewis structure for the following species.

NO3

Write brief answer to the following questions. | Q II. 11. ii) | Page 107

Draw the Lewis structure for the following species.

SO42-

Write brief answer to the following questions. | Q II. 11. iii) | Page 107

Draw the Lewis structure for the following species.

HNO3

Write brief answer to the following questions. | Q II. 11. iv) | Page 107

Draw the Lewis structure for the following species.

O3

Write brief answer to the following questions. | Q II. 12. | Page 107

Explain the bond formation if BeCl2 and MgCl2.

Write brief answer to the following questions. | Q II. 13. | Page 107

Which bond is stronger σ or π? Why?

Write brief answer to the following questions. | Q II. 14. | Page 107

Define bond energy.

Write brief answer to the following questions. | Q II. 15. | Page 107

Hydrogen gas is diatomic whereas inert gases are monoatomic – Explain on the basis of MO theory.

Write brief answer to the following questions. | Q II. 16. | Page 107

What is the Polar Covalent bond?

Write brief answer to the following questions. | Q II. 16. | Page 107

Explain an example of a Polar Covalent bond.

Write brief answer to the following questions. | Q II. 17. i) | Page 107

Considering x-axis as the molecular axis which out of the following will form a sigma bond.

1s and 2py

Write brief answer to the following questions. | Q II. 17. ii) | Page 107

Considering x-axis as the molecular axis which out of the following will form a sigma bond.

2px and 2py

Write brief answer to the following questions. | Q II. 17. iii) | Page 107

Considering x-axis as the molecular axis which out of the following will form a sigma bond.

2px and 2pz

Write brief answer to the following questions. | Q II. 17. iv) | Page 107

Considering x-axis as the molecular axis which out of the following will form a sigma bond.

1s and 2pz

Write brief answer to the following questions. | Q II. 18. | Page 107

Explain resonance with reference to a carbonate ion.

Write brief answer to the following questions. | Q II. 19. | Page 107

Explain the bond formation in ethylene.

Write brief answer to the following questions. | Q II. 19. | Page 107

Explain the bond formation in acetylene.

Write brief answer to the following questions. | Q II. 20. a) | Page 107

What type of hybridisation is possible in the following geometeries?

octahedral

Write brief answer to the following questions. | Q II. 20. b) | Page 107

What type of hybridisation is possible in the following geometeries?

tetrahedral

Write brief answer to the following questions. | Q II. 20. c) | Page 107

What type of hybridisation is possible in the following geometeries?

square planer

Write brief answer to the following questions. | Q II. 21. | Page 107

Explain VSEPR theory. Applying this theory to predict the shapes of IF7 and SF6.

Write brief answer to the following questions. | Q II. 22. | Page 107

CO2 and H2O both are triatomic molecule but their dipole moment values are different. Why?

Write brief answer to the following questions. | Q II. 23. | Page 107

Which one of the following has the highest bond order?

  1. N2
  2. N2+
  3. N2
Write brief answer to the following questions. | Q II. 24. | Page 107

Explain the covalent character in ionic bond.

Write brief answer to the following questions. | Q II. 25. | Page 107

Describe Fajan’s rule.

Chapter 10: Chemical bonding

Choose the best answerWrite brief answer to the following questions.
Class 11th Chemistry Volume 1 and 2 Answers Guide - Shaalaa.com

Tamil Nadu Board Samacheer Kalvi solutions for Class 11th Chemistry Volume 1 and 2 Answers Guide chapter 10 - Chemical bonding

Tamil Nadu Board Samacheer Kalvi solutions for Class 11th Chemistry Volume 1 and 2 Answers Guide chapter 10 (Chemical bonding) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the Tamil Nadu Board of Secondary Education Class 11th Chemistry Volume 1 and 2 Answers Guide solutions in a manner that help students grasp basic concepts better and faster.

Further, we at Shaalaa.com provide such solutions so that students can prepare for written exams. Tamil Nadu Board Samacheer Kalvi textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.

Concepts covered in Class 11th Chemistry Volume 1 and 2 Answers Guide chapter 10 Chemical bonding are Molecular Orbital Theory, Introduction of Chemical Bonding, Types of Chemical Bonds, Ionic or Electrovalent Bond, Coordinate Covalent Bond, Bond Parameters, Valence Shell Electron Pair Repulsion Theory (VSEPR), Valence Bond Theory, Valence Bond Theory - Orbital Overlap Concept, Hybridisation - Introduction.

Using Tamil Nadu Board Samacheer Kalvi Class 11th solutions Chemical bonding exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in Tamil Nadu Board Samacheer Kalvi Solutions are important questions that can be asked in the final exam. Maximum students of Tamil Nadu Board of Secondary Education Class 11th prefer Tamil Nadu Board Samacheer Kalvi Textbook Solutions to score more in exam.

Get the free view of chapter 10 Chemical bonding Class 11th extra questions for Class 11th Chemistry Volume 1 and 2 Answers Guide and can use Shaalaa.com to keep it handy for your exam preparation

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