# Selina solutions for Concise Mathematics Class 8 ICSE chapter 14 - Linear Equations in one Variable [Latest edition]

## Solutions for Chapter 14: Linear Equations in one Variable

Below listed, you can find solutions for Chapter 14 of CISCE Selina for Concise Mathematics Class 8 ICSE.

Exercise 14 (A)Exercise 14 (B)Exercise 14 (C)
Exercise 14 (A) [Pages 165 - 166]

### Selina solutions for Concise Mathematics Class 8 ICSE Chapter 14 Linear Equations in one Variable Exercise 14 (A) [Pages 165 - 166]

Exercise 14 (A) | Q 1 | Page 165

Solve the following equation:

20 = 6 + 2x

Exercise 14 (A) | Q 2 | Page 165

Solve the following equation:

15 + x = 5x + 3

Exercise 14 (A) | Q 3 | Page 165

Solve the following equation:

(3"x" + 2)/("x" - 6) = -7

Exercise 14 (A) | Q 4 | Page 165

Solve the following equation:

3a - 4 = 2(4 - a)

Exercise 14 (A) | Q 5 | Page 165

Solve the following equation:

3(b - 4) = 2(4 - b)

Exercise 14 (A) | Q 6 | Page 165

Solve the following equation:

("x"+2)/9 = ("x" + 4)/11

Exercise 14 (A) | Q 7 | Page 165

Solve the following equation:

("x"- 8)/5 = ("x" - 12)/9

Exercise 14 (A) | Q 8 | Page 165

Solve the following equation:

5(8x + 3) = 9(4x + 7)

Exercise 14 (A) | Q 9 | Page 165

Solve the following equation:

3(x + 1) = 12 + 4(x - 1)

Exercise 14 (A) | Q 10 | Page 165

Solve the following equation:

"3x"/4 - 1/4("x" - 20) = "x"/4 + 32

Exercise 14 (A) | Q 11 | Page 165

Solve the following equation:

3"a" - 1/5 = "a"/5 + 5 2/5

Exercise 14 (A) | Q 12 | Page 165

Solve the following equation:

"x"/3 - 2 1/2 = "4x"/9 - "2x"/3

Exercise 14 (A) | Q 13 | Page 165

Solve the following equation:

(4(y + 2))/5 = 7 + "5y"/13

Exercise 14 (A) | Q 14 | Page 165

Solve the following equation:

("a" + 5)/6 - ("a" + 1)/9 = ("a" + 3)/4

Exercise 14 (A) | Q 15 | Page 165

Solve the following equation:

("2x" - 13)/5 - ("x" - 3)/11 = ("x" - 9)/5 + 1

Exercise 14 (A) | Q 16 | Page 165

Solve the following equation:

6(6x - 5) - 5(7x - 8) = 12(4 - x) + 1

Exercise 14 (A) | Q 17 | Page 165

Solve the following equation:

(x - 5)(x + 3) = (x - 7)(x + 4)

Exercise 14 (A) | Q 18 | Page 165

Solve the following equation:

(x – 5)2 – (x + 2)2 = -2

Exercise 14 (A) | Q 19 | Page 165

Solve the following equation:

(x - 1 )(x + 6) - (x - 2)(x - 3) = 3

Exercise 14 (A) | Q 20 | Page 166

Solve the following equation:

(3"x")/("x" + 6) - "x"/("x" + 5) = 2

Exercise 14 (A) | Q 21 | Page 166

Solve the following equation:

1/("x - 1") + 2/("x" - 2) = 3/("x" - 3)

Exercise 14 (A) | Q 22 | Page 166

Solve the following equation:

("x" - 1)/("7x" - 14) = ("x" - 3)/("7x" - 26)

Exercise 14 (A) | Q 23 | Page 166

Solve the following equation:

1/("x" - 1) - 1/"x" = 1/("x" + 3) - 1/("x" + 4)

Exercise 14 (A) | Q 24 | Page 166

Solve: "2x"/3 - ("x" - 1)/6 + ("7x" - 1)/4 = 2 1/6 Hence, find the value of 'a', if 1/"a" + 5"x" = 8

Exercise 14 (A) | Q 25 | Page 166

Solve: (4-3"x")/5 + (7 - "x")/3 + 4 1/3 = 0 Hence, find the value of 'p', if 3p - 2x + 1 = 0

Exercise 14 (A) | Q 26 | Page 166

Solve: 0.25 + 1.95/"x" = 0.9

Exercise 14 (A) | Q 27 | Page 166

Solve: 5x - ("4x" + (5"x" -  4)/7) = ("4x" - 14)/3

Exercise 14 (B) [Page 169]

### Selina solutions for Concise Mathematics Class 8 ICSE Chapter 14 Linear Equations in one Variable Exercise 14 (B) [Page 169]

Exercise 14 (B) | Q 1 | Page 169

Fifteen less than 4 times a number is 9. Find the number.

Exercise 14 (B) | Q 2 | Page 169

If Megha’s age is increased by three times her age, the result is 60 years. Find her age

Exercise 14 (B) | Q 3 | Page 169

28 is 12 less than 4 times a number. Find the number.

Exercise 14 (B) | Q 4 | Page 169

Five less than 3 times a number is -20. Find the number.

Exercise 14 (B) | Q 5 | Page 169

Fifteen more than 3 times Neetu’s age is the same as 4 times her age. How old is she ?

Exercise 14 (B) | Q 6 | Page 169

A number decreased by 30 is the same as 14 decreased by 3 times the number; Find the number.

Exercise 14 (B) | Q 7 | Page 169

A’s salary is same as 4 times B’s salary. If together they earn Rs.3,750 a month, find the salary of each.

Exercise 14 (B) | Q 8 | Page 169

Separate 178 into two parts so that the first part is 8 less than twice the second part.

Exercise 14 (B) | Q 9 | Page 169

Six more than one-fourth of a number is two-fifth of the number. Find the number.

Exercise 14 (B) | Q 10 | Page 169

The length of a rectangle is twice its width. If its perimeter is 54 cm; find its length.

Exercise 14 (B) | Q 11 | Page 169

A rectangle’s length is 5 cm less than twice its width. If the length is decreased by 5 cm and width is increased by 2 cm; the perimeter of the resulting rectangle will be 74 cm. Find the length and width of the origi¬nal rectangle.

Exercise 14 (B) | Q 12 | Page 169

The sum of three consecutive odd numbers is 57. Find the numbers.

Exercise 14 (B) | Q 13 | Page 169

A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.

Exercise 14 (B) | Q 14 | Page 169

A man is 42 years old and his son is 12 years old. In how many years will the age of the son be half the age of the man at that time?

Exercise 14 (B) | Q 15 | Page 169

A man completed a trip of 136 km in 8 hours. Some part of the trip was covered at 15 km/hr and the remaining at 18 km/hr. Find the part of the trip covered at 18 km/hr.

Exercise 14 (B) | Q 16 | Page 169

The difference of two numbers is 3 and the difference of their squares is 69. Find the numbers.

Exercise 14 (B) | Q 17 | Page 169

Two consecutive natural numbers are such that one-fourth of the smaller exceeds one-fifth of the greater by 1. Find the numbers.

Exercise 14 (B) | Q 18 | Page 169

Three consecutive whole numbers are such that if they be divided by 5, 3 and 4 respectively; the sum of the quotients is 40. Find the numbers.

Exercise 14 (B) | Q 19 | Page 169

If the same number be added to the numbers 5, 11, 15 and 31, the resulting numbers are in proportion. Find the number.

Exercise 14 (B) | Q 20 | Page 169

The present age of a man is twice that of his son. Eight years hence, their ages will be in the ratio 7 : 4. Find their present ages

Exercise 14 (C) [Pages 169 - 170]

### Selina solutions for Concise Mathematics Class 8 ICSE Chapter 14 Linear Equations in one Variable Exercise 14 (C) [Pages 169 - 170]

Exercise 14 (C) | Q 1.01 | Page 169

Solve: 1/3"x" - 6 = 5/2

Exercise 14 (C) | Q 1.02 | Page 169

Solve: (2"x")/3 - (3"x")/8 = 7/12

Exercise 14 (C) | Q 1.03 | Page 169

Solve the following equation and also verify your solution:
(x + 2)(x + 3) + (x − 3)(x − 2) − 2x(x + 1) = 0

Exercise 14 (C) | Q 1.04 | Page 169

Solve: 1/10 - 7/"x" = 35

Exercise 14 (C) | Q 1.05 | Page 169

Solve: 13(x - 4) - 3(x - 9) - 5(x + 4) = 0

Exercise 14 (C) | Q 1.06 | Page 169

Solve: "x" + 7 - "8x"/3 = "17x"/6 - "5x"/8

Exercise 14 (C) | Q 1.07 | Page 169

Solve: (3"x" - 2)/4 - ("2x" + 3)/3 = 2/3 - "x"

Exercise 14 (C) | Q 1.08 | Page 169

Solve: ("x" + 2)/6 - ((11 - "x")/3 - 1/4) = (3"x" - 4)/12

Exercise 14 (C) | Q 1.09 | Page 169

Solve: 2/"5x" - 5/"3x" = 1/15

Exercise 14 (C) | Q 1.1 | Page 169

Solve: ("x" + 2)/3 - ("x" + 1)/5 = ("x" - 3)/4 - 1

Exercise 14 (C) | Q 1.11 | Page 169

Solve: (3"x" - 2)/3 + (2"x" + 3)/2 = "x" + 7/6

Exercise 14 (C) | Q 1.12 | Page 169

Solve: "x" - ("x" - 1)/2 = 1 - ("x" - 2)/3

Exercise 14 (C) | Q 1.13 | Page 170

Solve: ("9x" + 7)/2 - ("x" - ("x" - 2)/7) = 36

Exercise 14 (C) | Q 1.14 | Page 170

Solve: ("6x" + 1)/2 + 1 = ("7x" - 3)/3

Exercise 14 (C) | Q 2 | Page 170

After 12 years, I shall be 3 times as old as 1 was 4 years ago. Find my present age.

Exercise 14 (C) | Q 3 | Page 170

A man sold an article for ₹ 396 and gained 10% on it. Find the cost price of the article

Exercise 14 (C) | Q 4 | Page 170

The sum of two numbers is 4500. If 10% of one number is 12.5% of the other, find the numbers.

Exercise 14 (C) | Q 5 | Page 170

The sum of two numbers is 405 and their ratio is 8 : 7. Find the numbers.

Exercise 14 (C) | Q 6 | Page 170

The ages of A and B are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.

Exercise 14 (C) | Q 7 | Page 170

Find a number whose double is 45 greater than its half.

Exercise 14 (C) | Q 8 | Page 170

The difference between the squares of two consecutive numbers is 31. Find the numbers.

Exercise 14 (C) | Q 9 | Page 170

Find a number such that when 5 is subtracted from 5 times the number, the result is 4 more than twice the number.

Exercise 14 (C) | Q 10 | Page 170

The numerator of a fraction is 5 less than its denominator. If 3 is added to the numerator, and denominator both, the fraction becomes4/5. Find the original fraction.

## Solutions for Chapter 14: Linear Equations in one Variable

Exercise 14 (A)Exercise 14 (B)Exercise 14 (C)

## Selina solutions for Concise Mathematics Class 8 ICSE chapter 14 - Linear Equations in one Variable

Shaalaa.com has the CISCE Mathematics Concise Mathematics Class 8 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Selina solutions for Mathematics Concise Mathematics Class 8 ICSE CISCE 14 (Linear Equations in one Variable) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

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Concepts covered in Concise Mathematics Class 8 ICSE chapter 14 Linear Equations in one Variable are Simple Linear Equations in One Variable, Solving Linear Inequations, Equations Reducible to the Linear Form, Linear Equation in One Variable.

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