Chapters
Chapter 2: Rational Numbers
Chapter 3: Fractions (Including Problems)
Chapter 4: Decimal Fractions (Decimals)
Chapter 5: Exponents (Including Laws of Exponents)
Chapter 6: Ratio and Proportion (Including Sharing in a Ratio)
Chapter 7: Unitary Method (Including Time and Work)
Chapter 8: Percent and Percentage
Chapter 9: Profit, Loss and Discount
Chapter 10: Simple Interest
Chapter 11: Fundamental Concepts (Including Fundamental Operations)
Chapter 12: Simple Linear Equations (Including Word Problems)
Chapter 13: Set Concepts (Some Simple Divisions by Vedic Method)
Chapter 14: Lines and Angles (Including Construction of angles)
Chapter 15: Triangles
Chapter 16: Pythagoras Theorem
Chapter 17: Symmetry (Including Reflection and Rotation)
Chapter 18: Recognition of Solids (Representing 3-D in 2-D)
Chapter 19: Congruency: Congruent Triangles
Chapter 20: Mensuration
Chapter 21: Data Handling
Chapter 22: Probability
Chapter 16: Pythagoras Theorem
Selina solutions for Concise Mathematics Class 7 ICSE Chapter 16 Pythagoras TheoremExercise 16
Triangle ABC is right-angled at vertex A. Calculate the length of BC, if AB = 18 cm and AC = 24 cm.
Triangle XYZ is right-angled at vertex Z. Calculate the length of YZ, if XY = 13 cm and XZ = 12 cm.
Triangle PQR is right-angled at vertex R. Calculate the length of PR, if: PQ = 34 cm and QR = 33.6 cm.
The sides of a certain triangle is given below. Find, which of them is right-triangle
16 cm, 20 cm, and 12 cm
The sides of a certain triangle is given below. Find, which of them is right-triangle
6 m, 9 m, and 13 m
In the given figure, angle BAC = 90°, AC = 400 m, and AB = 300 m. Find the length of BC.
In the given figure, angle ACP = ∠BDP = 90°, AC = 12 m, BD = 9 m and PA= PB = 15 m. Find:
(i) CP
(ii) PD
(iii) CD
In triangle PQR, angle Q = 90°, find: PR, if PQ = 8 cm and QR = 6 cm
In triangle PQR, angle Q = 90°, find: PQ, if PR = 34 cm and QR = 30 cm
Show that the triangle ABC is a right-angled triangle; if: AB = 9 cm, BC = 40 cm and AC = 41 cm
In the given figure, angle ACB = 90° = angle ACD. If AB = 10 m, BC = 6 cm and AD = 17 cm, find :
(i) AC
(ii) CD
In the given figure, angle ADB = 90°, AC = AB = 26 cm and BD = DC. If the length of AD = 24 cm; find the length of BC.
In the given figure, AD = 13 cm, BC = 12 cm, AB = 3 cm and angle ACD = angle ABC = 90°. Find the length of DC.
A ladder, 6.5 m long, rests against a vertical wall. If the foot of the ladder is 2.5 m from the foot of the wall, find up to how much height does the ladder reach?
A boy first goes 5 m due north and then 12 m due east. Find the distance between the initial and the final position of the boy.
Use the information given in the figure to find the length AD.
Chapter 16: Pythagoras Theorem
Selina solutions for Concise Mathematics Class 7 ICSE chapter 16 - Pythagoras Theorem
Selina solutions for Concise Mathematics Class 7 ICSE chapter 16 (Pythagoras Theorem) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the CISCE Concise Mathematics Class 7 ICSE solutions in a manner that help students grasp basic concepts better and faster.
Further, we at Shaalaa.com provide such solutions so that students can prepare for written exams. Selina textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.
Concepts covered in Concise Mathematics Class 7 ICSE chapter 16 Pythagoras Theorem are Right-angled Triangles and Pythagoras Property.
Using Selina Class 7 solutions Pythagoras Theorem exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in Selina Solutions are important questions that can be asked in the final exam. Maximum students of CISCE Class 7 prefer Selina Textbook Solutions to score more in exam.
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