#### Chapters

Chapter 2: Rational Numbers

Chapter 3: Fractions (Including Problems)

Chapter 4: Decimal Fractions (Decimals)

Chapter 5: Exponents (Including Laws of Exponents)

Chapter 6: Ratio and Proportion (Including Sharing in a Ratio)

Chapter 7: Unitary Method (Including Time and Work)

Chapter 8: Percent and Percentage

Chapter 9: Profit, Loss and Discount

Chapter 10: Simple Interest

Chapter 11: Fundamental Concepts (Including Fundamental Operations)

Chapter 12: Simple Linear Equations (Including Word Problems)

Chapter 13: Set Concepts (Some Simple Divisions by Vedic Method)

Chapter 14: Lines and Angles (Including Construction of angles)

Chapter 15: Triangles

Chapter 16: Pythagoras Theorem

Chapter 17: Symmetry (Including Reflection and Rotation)

Chapter 18: Recognition of Solids (Representing 3-D in 2-D)

Chapter 19: Congruency: Congruent Triangles

Chapter 20: Mensuration

Chapter 21: Data Handling

Chapter 22: Probability

## Chapter 16: Pythagoras Theorem

### Selina solutions for Concise Mathematics Class 7 ICSE Chapter 16 Pythagoras Theorem Exercise 16

Triangle ABC is right-angled at vertex A. Calculate the length of BC, if AB = 18 cm and AC = 24 cm.

Triangle XYZ is right-angled at vertex Z. Calculate the length of YZ, if XY = 13 cm and XZ = 12 cm.

Triangle PQR is right-angled at vertex R. Calculate the length of PR, if: PQ = 34 cm and QR = 33.6 cm.

**The sides of a certain triangle is given below. Find, which of them is right-triangle**

16 cm, 20 cm, and 12 cm

**The sides of a certain triangle is given below. Find, which of them is right-triangle**

6 m, 9 m, and 13 m

In the given figure, angle BAC = 90°, AC = 400 m, and AB = 300 m. Find the length of BC.

In the given figure, angle ACP = ∠BDP = 90°, AC = 12 m, BD = 9 m and PA= PB = 15 m. Find:**(i)** CP**(ii)** PD**(iii)** CD

In triangle PQR, angle Q = 90°, find: PR, if PQ = 8 cm and QR = 6 cm

In triangle PQR, angle Q = 90°, find: PQ, if PR = 34 cm and QR = 30 cm

Show that the triangle ABC is a right-angled triangle; if: AB = 9 cm, BC = 40 cm and AC = 41 cm

In the given figure, angle ACB = 90° = angle ACD. If AB = 10 m, BC = 6 cm and AD = 17 cm, find :

(i) AC

(ii) CD

In the given figure, angle ADB = 90°, AC = AB = 26 cm and BD = DC. If the length of AD = 24 cm; find the length of BC.

In the given figure, AD = 13 cm, BC = 12 cm, AB = 3 cm and angle ACD = angle ABC = 90°. Find the length of DC.

A ladder, 6.5 m long, rests against a vertical wall. If the foot of the ladder is 2.5 m from the foot of the wall, find up to how much height does the ladder reach?

A boy first goes 5 m due north and then 12 m due east. Find the distance between the initial and the final position of the boy.

Use the information given in the figure to find the length AD.

## Chapter 16: Pythagoras Theorem

## Selina solutions for Concise Mathematics Class 7 ICSE chapter 16 - Pythagoras Theorem

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Concepts covered in Concise Mathematics Class 7 ICSE chapter 16 Pythagoras Theorem are Pythagoras Theorem.

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