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RD Sharma solutions for Class 9 Mathematics chapter 16 - Constructions

Mathematics for Class 9 by R D Sharma (2018-19 Session)

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RD Sharma Mathematics Class 9 by R D Sharma (2018-19 Session)

Mathematics for Class 9 by R D Sharma (2018-19 Session)

Chapter 16: Constructions

Ex. 16.1Ex. 16.2Ex. 16.3

Chapter 16: Constructions Exercise 16.1 solutions [Pages 3 - 4]

Ex. 16.1 | Q 1 | Page 3

Draw a line segment of length 8.6 cm. Bisect it and measure the length of each part.

Ex. 16.1 | Q 2 | Page 3

Draw a line segment AB of length 5.8 cm. Draw the perpendicular bisector of this line
segment.

Ex. 16.1 | Q 3 | Page 4

Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the
perpendicular bisector of line segment AB. Does it pass through the centre of the circle?

Ex. 16.1 | Q 4 | Page 4

Draw a circle with centre at point O. Draw its two chords AB and CD such that AB is not
parallel to CD. Draw the perpendicular bisectors of AB and CD. At what point do they
intersect?

Ex. 16.1 | Q 5 | Page 4

Draw a line segment of length 10 cm and bisect it. Further bisect one of the equal parts and
measure its length.

Ex. 16.1 | Q 6 | Page 4

Draw a line segment AB and bisect it. Bisect one of the equal parts to obtain a line segment of length `1/2` (AB).

Ex. 16.1 | Q 7 | Page 4

7. Draw a line segment AB and by ruler and compasses1 obtain a line segment of length `3/4`AB. 

Chapter 16: Constructions Exercise 16.2 solutions [Page 9]

Ex. 16.2 | Q 1 | Page 9

 Draw an angle and label it as ∠BAC. Construct another angle, equal to ∠BAC.

Ex. 16.2 | Q 2 | Page 9

Draw an obtuse angle, Bisect it. Measure each of the angles so obtained.

Ex. 16.2 | Q 3 | Page 9

Using your protractor, draw an angle of measure 108°. With this angle as given, draw an
angle of 54°.

Ex. 16.2 | Q 4 | Page 9

Using protractor, draw a right angle. Bisect it to get an angle of measure 45°.

Ex. 16.2 | Q 5 | Page 9

Draw a linear pair of angles. Bisect each of the two angles. Verify that the two bisecting rays are perpendicular to each other.

Ex. 16.2 | Q 6 | Page 9

Draw a pair of vertically opposite angles. Bisect each of the two angles. Verify that the bisecting rays are in the same line.

Ex. 16.2 | Q 7 | Page 9

Using ruler and compasses only, draw a right angle.

Ex. 16.2 | Q 8 | Page 9

Using ruler and compasses only, draw an angle of measure 135°.

Ex. 16.2 | Q 9 | Page 9

Using a protractor, draw an angle of measure 72°. With this angle as given, draw angles of measure 36° and 54°.

Ex. 16.2 | Q 10.1 | Page 9

Construct the following angles at the initial point of a given ray and justify the construction 45°

Ex. 16.2 | Q 10.2 | Page 9

Construct the following angles at the initial point of a given ray and justify the construction 90°. 

Ex. 16.2 | Q 11.1 | Page 9

Construct the angle of the measurement :

 1. 30°

 

Ex. 16.2 | Q 11.2 | Page 9

Construct the angle of the measurement:

1 . 75°

Ex. 16.2 | Q 11.3 | Page 9

Construct the angle of the measurement:

1 . 105°

Ex. 16.2 | Q 11.4 | Page 9

Construct the angle of the measurement:

1. 135°

Ex. 16.2 | Q 11.5 | Page 9

Construct the angle of the measurement:

1. 15°

Ex. 16.2 | Q 11.6 | Page 9

Construct the angle of the measurement:

1. 22 `(1°)/2`

Chapter 16: Constructions Exercise 16.3 solutions [Page 18]

Ex. 16.3 | Q 1 | Page 18

Construct a ΔABC in which BC = 3.6 cm, AB + AC = 4.8 cm and ∠B = 60°.

Ex. 16.3 | Q 2 | Page 18

Construct a ΔABC in which AB + AC = 5.6 cm, BC = 4.5 cm, AB − AC = 1.5 cm and ∠B = 45°.

Ex. 16.3 | Q 3 | Page 18

Construct a ΔABC in which BC = 3.4 cm, AB − AC = 1.5 cm and ∠B = 45°.

Ex. 16.3 | Q 4 | Page 18

Using ruler and compasses only, construct a ΔABC, given base BC = 7cm, ∠ABC = 60° and AB + AC = 12 cm.

Ex. 16.3 | Q 5 | Page 18

Construct a right-angled triangle whose perimeter is equal to 10 cm and one acute angle equal to 60°.

Ex. 16.3 | Q 6 | Page 18

Construct a triangle ABC such that BC = 6 cm, AB = 6 cm and median AD = 4 cm.

Ex. 16.3 | Q 7 | Page 18

Construct a right triangle ABC whose base BC is 6 cm and the sum of hypotenuse AC and other side AB is 10 cm.

Ex. 16.3 | Q 8 | Page 18

Construct a triangle whose perimeter is 6.4 cm, and angles at the base are 60° and 45° .

Ex. 16.3 | Q 9 | Page 18

Using ruler and compasses only, construct a ΔABC from the following data:
AB + BC + CA = 12 cm, ∠B = 45° and ∠C = 60°.

Ex. 16.3 | Q 10 | Page 18

Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11.

Chapter 16: Constructions

Ex. 16.1Ex. 16.2Ex. 16.3

RD Sharma Mathematics Class 9 by R D Sharma (2018-19 Session)

Mathematics for Class 9 by R D Sharma (2018-19 Session)

RD Sharma solutions for Class 9 Mathematics chapter 16 - Constructions

RD Sharma solutions for Class 9 Maths chapter 16 (Constructions) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the CBSE Mathematics for Class 9 by R D Sharma (2018-19 Session) solutions in a manner that help students grasp basic concepts better and faster.

Further, we at shaalaa.com are providing such solutions so that students can prepare for written exams. RD Sharma textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.

Concepts covered in Class 9 Mathematics chapter 16 Constructions are Some Constructions of Triangles, Basic Constructions, Introduction of Constructions.

Using RD Sharma Class 9 solutions Constructions exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in RD Sharma Solutions are important questions that can be asked in the final exam. Maximum students of CBSE Class 9 prefer RD Sharma Textbook Solutions to score more in exam.

Get the free view of chapter 16 Constructions Class 9 extra questions for Maths and can use shaalaa.com to keep it handy for your exam preparation

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