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RD Sharma solutions for Class 8 Mathematics chapter 18 - Practical Geometry (Constructions)

Mathematics for Class 8 by R D Sharma (2019-2020 Session)

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RD Sharma Mathematics Class 8 by R D Sharma (2019-2020 Session)

Mathematics for Class 8 by R D Sharma (2019-2020 Session) - Shaalaa.com

Chapter 18: Practical Geometry (Constructions)

Ex. 18.10Ex. 18.20Ex. 18.30Ex. 18.40Ex. 18.50

Chapter 18: Practical Geometry (Constructions) Exercise 18.10 solutions [Page 4]

Ex. 18.10 | Q 1 | Page 4

Construct a quadrilateral ABCD in which AB = 4.4 cm, BC = 4 cm, CD = 6.4 cm, DA = 3.8 cm and BD= 6.6 cm.

Ex. 18.10 | Q 2 | Page 4

Construct a quadrilateral ABCD such that AB = BC = 5.5 cm, CD = 4 cm, DA = 6.3 cm and AC = 9.4 cm. Measure BD.

Ex. 18.10 | Q 3 | Page 4

Construct a quadrilateral XYZW in which XY = 5 cm, YZ = 6 cm, ZW = 7 cm, WX = 3 cm and XZ = 9 cm.

Ex. 18.10 | Q 4 | Page 4

Construct a parallelogram PQRS such that PQ = 5.2 cm, PR = 6.8 cm and QS = 8.2 cm.

Ex. 18.10 | Q 5 | Page 4

Construct a rhombus with side 6 cm and one diagonal 8 cm. Measure the other diagonal.

Ex. 18.10 | Q 6 | Page 4

Construct a kite ABCD in which AB = 4 cm, BC = 4.9 cm and AC = 7.2 cm.

Ex. 18.10 | Q 7 | Page 4

Construct, if possible, a quadrilateral ABCD given AB = 6 cm, BC = 3.7 cm, CD = 5.7 cm, AD = 5.5 cm and BD = 6.1 cm. Give reasons for not being able to construct it, if you cannot.

Ex. 18.10 | Q 8 | Page 4

Construct, if possible, a quadrilateral ABCD in which AB = 6 cm, BC = 7 cm, CD = 3 cm, AD = 5.5 cm and AC = 11 cm. Give reasons for not being able to construct, if you cannot. (Not possible, because in triangle ACD, AD + CD < AC).

Chapter 18: Practical Geometry (Constructions) Exercise 18.20 solutions [Page 6]

Ex. 18.20 | Q 1 | Page 6

Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 cm, AC = 4.5 cm and BD = 3.8 cm.

Ex. 18.20 | Q 2 | Page 6

Construct a quadrilateral ABCD in which BC = 7.5 cm, AC = AD = 6 cm, CD = 5 cm and BD = 10 cm.

Ex. 18.20 | Q 3 | Page 6

Construct a quadrilateral ABCD, when AB = 3 cm, CD = 3 cm, DA = 7.5 cm, AC = 8 cm and BD = 4 cm.

Ex. 18.20 | Q 4 | Page 6

Construct a quadrilateral ABCD given AD = 3.5 cm, BC = 2.5 cm, CD = 4.1 cm, AC = 7.3 cm and BD = 3.2 cm.

Ex. 18.20 | Q 5 | Page 6

Construct a quadrilateral ABCD given AD = 5 cm, AB = 5.5 cm, BC = 2.5 cm, AC = 7.1 cm and BD = 8 cm.

Ex. 18.20 | Q 6 | Page 6

Construct a quadrilateral ABCD in which BC = 4 cm, CA = 5.6 cm, AD = 4.5 cm, CD = 5 cm and BD = 6.5 cm. 

Chapter 18: Practical Geometry (Constructions) Exercise 18.30 solutions [Page 8]

Ex. 18.30 | Q 1 | Page 8

Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 cm, AD = 5 cm and ∠B= 80°.

Ex. 18.30 | Q 2 | Page 8

Construct a quadrilateral ABCD, given that AB = 8 cm, BC = 8 cm, CD = 10 cm, AD = 10 cm and ∠A = 45°.

Ex. 18.30 | Q 3 | Page 8

Construct a quadrilateral ABCD in which AB = 7.7 cm, BC = 6.8 cm, CD = 5.1 cm, AD = 3.6 cm and ∠C = 120°.

Ex. 18.30 | Q 4 | Page 8

Construct a quadrilateral ABCD in which AB = BC = 3 cm, AD = CD = 5 cm, and ∠B = 120°.

Ex. 18.30 | Q 5 | Page 8

Construct a quadrilateral ABCD in which AB = 2.8 cm, BC = 3.1 cm, CD = 2.6 cm, and DA = 3.3 cm and ∠A = 60°.

Ex. 18.30 | Q 6 | Page 8

Construct a quadrilateral ABCD in which AB = BC = 6 cm, AD = DC = 4.5 cm and ∠B = 120°.

Chapter 18: Practical Geometry (Constructions) Exercise 18.40 solutions [Pages 10 - 11]

Ex. 18.40 | Q 1 | Page 10

Construct a quadrilateral ABCD, in which AB = 6 cm, BC = 4 cm, CD = 4 cm, ∠B = 95° and ∠C = 90°.

Ex. 18.40 | Q 2 | Page 10

Construct a quadrilateral ABCD, where AB = 4.2 cm, BC = 3.6 cm, CD = 4.8 cm, ∠B = 30° and ∠C = 150°.

Ex. 18.40 | Q 3 | Page 10

Construct a quadrilateral PQRS, in which PQ = 3.5 cm, QR = 2.5 cm, RS = 4.1 cm, ∠Q = 75° and ∠R = 120°.

Ex. 18.40 | Q 4 | Page 11

Construct a quadrilateral ABCD given BC = 6.6 cm, CD = 4.4 cm, AD = 5.6 cm and ∠D = 100° and ∠C= 95°.

Ex. 18.40 | Q 5 | Page 11

Construct a quadrilateral ABCD, in which AD = 3.5 cm, AB = 4.4 cm, BC = 4.7 cm, ∠A = 125° and ∠B= 120°.

Ex. 18.40 | Q 6 | Page 11

Construct a quadrilateral PQRS, in which ∠Q = 45°, ∠R = 90°, QR = 5 cm, PQ = 9 cm and Rs = 7 cm.

Ex. 18.40 | Q 7 | Page 11

Construct a quadrilateral ABCD, in which AB = BC = 3 cm, AD = 5 cm, ∠A = 90° and ∠B = 105°.

Ex. 18.40 | Q 8 | Page 11

Construct a quadrilateral BDEF, where DE = 4.5 cm, EF = 3.5 cm, FB = 6.5 cm, ∠F = 50° and ∠E = 100°.

Chapter 18: Practical Geometry (Constructions) Exercise 18.50 solutions [Page 13]

Ex. 18.50 | Q 1 | Page 13

Construct a quadrilateral ABCD given that AB = 4 cm, BC = 3 cm, ∠A = 75°, ∠B = 80° and ∠C = 120°.

Ex. 18.50 | Q 2 | Page 13

Construct a quadrilateral ABCD, where AB = 5.5 cm, BC = 3.7 cm, ∠A = 60°, ∠B = 105° and ∠D = 90°.

Ex. 18.50 | Q 3 | Page 13

Construct a quadrilateral PQRS, where PQ = 3.5 cm, QR = 6.5 cm, ∠P = ∠R = 105° and ∠S = 75°.

Ex. 18.50 | Q 4 | Page 13

Construct a quadrilateral ABCD when BC = 5.5 cm, CD = 4.1 cm, ∠A = 70°, ∠B = 110° and ∠D = 85°.

Ex. 18.50 | Q 5 | Page 13

Construct a quadrilateral ABCD, where ∠A = 65°, ∠B = 105°, ∠C = 75° BC = 5.7 cm and CD = 6.8 cm.

Ex. 18.50 | Q 6 | Page 13

Construct a quadrilateral PQRS, in which PQ = 4 cm, QR = 5 cm, ∠P = 50°, ∠Q = 110° and ∠R = 70°.

Chapter 18: Practical Geometry (Constructions)

Ex. 18.10Ex. 18.20Ex. 18.30Ex. 18.40Ex. 18.50

RD Sharma Mathematics Class 8 by R D Sharma (2019-2020 Session)

Mathematics for Class 8 by R D Sharma (2019-2020 Session) - Shaalaa.com

RD Sharma solutions for Class 8 Mathematics chapter 18 - Practical Geometry (Constructions)

RD Sharma solutions for Class 8 Maths chapter 18 (Practical Geometry (Constructions)) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the CBSE Mathematics for Class 8 by R D Sharma (2019-2020 Session) solutions in a manner that help students grasp basic concepts better and faster.

Further, we at Shaalaa.com provide such solutions so that students can prepare for written exams. RD Sharma textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.

Concepts covered in Class 8 Mathematics chapter 18 Practical Geometry (Constructions) are Introduction of Pratical Geometry, When the Lengths of Four Sides and a Diagonal Are Given, When Two Diagonals and Three Sides Are Given, When Two Adjacent Sides and Three Angles Are Known, When Three Sides and Two Included Angles Are Given, Some Special Cases.

Using RD Sharma Class 8 solutions Practical Geometry (Constructions) exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in RD Sharma Solutions are important questions that can be asked in the final exam. Maximum students of CBSE Class 8 prefer RD Sharma Textbook Solutions to score more in exam.

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