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# RD Sharma solutions for Class 11 Mathematics Textbook chapter 27 - Hyperbola [Latest edition]

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## Chapter 27: Hyperbola

Exercise 27.1Others
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Exercise 27.1[Pages 13 - 14]

### RD Sharma solutions for Class 11 Mathematics Textbook Chapter 27 HyperbolaExercise 27.1[Pages 13 - 14]

Exercise 27.1 | Q 1 | Page 13

The equation of the directrix of a hyperbola is x − y + 3 = 0. Its focus is (−1, 1) and eccentricity 3. Find the equation of the hyperbola.

Exercise 27.1 | Q 2.1 | Page 13

Find the equation of the hyperbola whose focus is (0, 3), directrix is x + y − 1 = 0 and eccentricity = 2 .

Exercise 27.1 | Q 2.2 | Page 13

Find the equation of the hyperbola whose focus is (1, 1), directrix is 3x + 4y + 8 = 0 and eccentricity = 2 .

Exercise 27.1 | Q 2.3 | Page 13

Find the equation of the hyperbola whose focus is (1, 1) directrix is 2x + y = 1 and eccentricity = $\sqrt{3}$.

Exercise 27.1 | Q 2.4 | Page 13

Find the equation of the hyperbola whose focus is (2, −1), directrix is 2x + 3y = 1 and eccentricity = 2 .

Exercise 27.1 | Q 2.5 | Page 13

Find the equation of the hyperbola whose focus is (a, 0), directrix is 2x − y + a = 0 and eccentricity = $\frac{4}{3}$.

Exercise 27.1 | Q 2.6 | Page 13

Find the equation of the hyperbola whose focus is (2, 2), directrix is x + y = 9 and eccentricity = 2.

Exercise 27.1 | Q 3.1 | Page 13

Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

9x2 − 16y2 = 144

Exercise 27.1 | Q 3.2 | Page 13

Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

16x2 − 9y2 = −144

Exercise 27.1 | Q 3.3 | Page 13

Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

4x2 − 3y2 = 36

Exercise 27.1 | Q 3.4 | Page 13

Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

3x2 − y2 = 4

Exercise 27.1 | Q 3.5 | Page 13

Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

2x2 − 3y2 = 5.

Exercise 27.1 | Q 4 | Page 13

Find the axes, eccentricity, latus-rectum and the coordinates of the foci of the hyperbola 25x2 − 36y2 = 225.

Exercise 27.1 | Q 5.1 | Page 13

Find the centre, eccentricity, foci and directrice of the hyperbola .

16x2 − 9y2 + 32x + 36y − 164 = 0

Exercise 27.1 | Q 5.2 | Page 13

Find the centre, eccentricity, foci and directrice of the hyperbola .

x2 − y2 + 4x = 0

Exercise 27.1 | Q 5.3 | Page 13

Find the centre, eccentricity, foci and directrice of the hyperbola .

x2 − 3y2 − 2x = 8.

Exercise 27.1 | Q 6.1 | Page 13

Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in  the distance between the foci = 16 and eccentricity = $\sqrt{2}$.

Exercise 27.1 | Q 6.2 | Page 13

Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in  the  conjugate axis is 5 and the distance between foci = 13 .

Exercise 27.1 | Q 6.3 | Page 13

Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in  the conjugate axis is 7 and passes through the point (3, −2).

Exercise 27.1 | Q 7.1 | Page 14

Find the equation of the hyperbola whose foci are (6, 4) and (−4, 4) and eccentricity is 2.

Exercise 27.1 | Q 7.2 | Page 14

Find the equation of the hyperbola whose vertices are (−8, −1) and (16, −1) and focus is (17, −1).

Exercise 27.1 | Q 7.3 | Page 14

Find the equation of the hyperbola whose  foci are (4, 2) and (8, 2) and eccentricity is 2.

Exercise 27.1 | Q 7.4 | Page 14

Find the equation of the hyperbola whose vertices are at (0 ± 7) and foci at $\left( 0, \pm \frac{28}{3} \right)$ .

Exercise 27.1 | Q 7.5 | Page 14

Find the equation of the hyperbola whose vertices are at (± 6, 0) and one of the directrices is x = 4.

Exercise 27.1 | Q 7.6 | Page 14

Find the equation of the hyperbola whose foci at (± 2, 0) and eccentricity is 3/2.

Exercise 27.1 | Q 8 | Page 14

Find the eccentricity of the hyperbola, the length of whose conjugate axis is $\frac{3}{4}$ of the length of transverse axis.

Exercise 27.1 | Q 9.1 | Page 14

Find the equation of the hyperboala whose focus is at (5, 2), vertex at (4, 2) and centre at (3, 2).

Exercise 27.1 | Q 9.2 | Page 14

Find the equation of the hyperboala whose focus is at (4, 2), centre at (6, 2) and e = 2.

Exercise 27.1 | Q 10 | Page 14

If P is any point on the hyperbola whose axis are equal, prove that SP. S'P = CP2.

Exercise 27.1 | Q 11.01 | Page 14

Find the equation of the hyperbola satisfying the given condition :

vertices (± 2, 0), foci (± 3, 0)

Exercise 27.1 | Q 11.02 | Page 14

Find the equation of the hyperbola satisfying the given condition :

vertices (0, ± 5), foci (0, ± 8)

Exercise 27.1 | Q 11.03 | Page 14

Find the equation of the hyperbola satisfying the given condition :

vertices (0, ± 3), foci (0, ± 5)

Exercise 27.1 | Q 11.04 | Page 14

Find the equation of the hyperbola satisfying the given condition :

foci (± $3\sqrt{5}$ 0), the latus-rectum = 8

Exercise 27.1 | Q 11.05 | Page 14

Find the equation of the hyperbola satisfying the given condition :

foci (0, ± 13), conjugate axis = 24

Exercise 27.1 | Q 11.06 | Page 14

find the equation of the hyperbola satisfying the given condition:

foci (± $3\sqrt{5}$  0), the latus-rectum = 8

Exercise 27.1 | Q 11.07 | Page 14

(vii)  find the equation of the hyperbola satisfying the given condition:

foci (± 4, 0), the latus-rectum = 12

Exercise 27.1 | Q 11.08 | Page 14

find the equation of the hyperbola satisfying the given condition:

vertices (± 7, 0), $e = \frac{4}{3}$

Exercise 27.1 | Q 11.09 | Page 14

find the equation of the hyperbola satisfying the given condition:

foci (0, ± $\sqrt{10}$, passing through (2, 3).

Exercise 27.1 | Q 11.1 | Page 14

find the equation of the hyperbola satisfying the given condition:

foci (0, ± 12), latus-rectum = 36

Exercise 27.1 | Q 12 | Page 14

If the distance between the foci of a hyperbola is 16 and its ecentricity is $\sqrt{2}$,then obtain its equation.

Exercise 27.1 | Q 13 | Page 14

Show that the set of all points such that the difference of their distances from (4, 0) and (− 4,0) is always equal to 2 represents a hyperbola.

[Page 18]

### RD Sharma solutions for Class 11 Mathematics Textbook Chapter 27 Hyperbola[Page 18]

Q 1 | Page 18

Write the eccentricity of the hyperbola 9x2 − 16y2 = 144.

Q 2 | Page 18

Write the eccentricity of the hyperbola whose latus-rectum is half of its transverse axis.

Q 3 | Page 18

Write the coordinates of the foci of the hyperbola 9x2 − 16y2 = 144.

Q 4 | Page 18

Write the equation of the hyperbola of eccentricity $\sqrt{2}$,  if it is known that the distance between its foci is 16.

Q 5 | Page 18

If the foci of the ellipse $\frac{x^2}{16} + \frac{y^2}{b^2} = 1$ and the hyperbola $\frac{x^2}{144} - \frac{y^2}{81} = \frac{1}{25}$ coincide, write the value of b2.

Q 6 | Page 18

Write the length of the latus-rectum of the hyperbola 16x2 − 9y2 = 144.

Q 7 | Page 18

If the latus-rectum through one focus of a hyperbola subtends a right angle at the farther vertex, then write the eccentricity of the hyperbola.

Q 8 | Page 18

Write the distance between the directrices of the hyperbola x = 8 sec θ, y = 8 tan θ.

Q 9 | Page 18

Write the equation of the hyperbola whose vertices are (± 3, 0) and foci at (± 5, 0).

Q 10 | Page 18

If e1 and e2 are respectively the eccentricities of the ellipse $\frac{x^2}{18} + \frac{y^2}{4} = 1$

and the hyperbola $\frac{x^2}{9} - \frac{y^2}{4} = 1$ then write the value of 2 e12 + e22.

[Pages 18 - 20]

### RD Sharma solutions for Class 11 Mathematics Textbook Chapter 27 Hyperbola[Pages 18 - 20]

Q 1 | Page 18

Equation of the hyperbola whose vertices are (± 3, 0) and foci at (± 5, 0), is

• 16x2 − 9y2 = 144

• 9x2 − 16y2 = 144

•  25x2 − 9y= 225

• 9x2 − 25y2 = 81

Q 2 | Page 18

If e1 and e2 are respectively the eccentricities of the ellipse $\frac{x^2}{18} + \frac{y^2}{4} = 1$ and the hyperbola $\frac{x^2}{9} - \frac{y^2}{4} = 1$ , then the relation between e1 and e2 is

•  3 e12 + e22 = 2

•  e12 + 2 e22 = 3

• e12 + e22 = 3

• e12 + 3 e22 = 2

Q 3 | Page 19

The distance between the directrices of the hyperbola x = 8 sec θ, y = 8 tan θ, is

• $8\sqrt{2}$

• $16\sqrt{2}$

• $4\sqrt{2}$

• $6\sqrt{2}$

Q 4 | Page 19

The equation of the conic with focus at (1, 1) directrix along x − y + 1 = 0 and eccentricity $\sqrt{2}$ is

• xy = 1

•  2xy + 4x − 4y − 1= 0

• x2 − y2 = 1

• 2xy − 4x + 4y + 1 = 0

Q 5 | Page 19

The eccentricity of the conic 9x2 − 16y2 = 144 is

• $\frac{5}{4}$

• $\frac{4}{3}$

• $\frac{4}{5}$

• $\sqrt{7}$

Q 6 | Page 19

A point moves in a plane so that its distances PA and PB from two fixed points A and B in the plane satisfy the relation PA − PB = k (k ≠ 0), then the locus of P is

•  a hyperbola

•  a branch of the hyperbola

• a parabola

• an ellipse

Q 7 | Page 19

The eccentricity of the hyperbola whose latus-rectum is half of its transverse axis, is

• $\frac{1}{\sqrt{2}}$

• $\sqrt{\frac{2}{3}}$

• $\sqrt{\frac{3}{2}}$

•  none of these.

Q 8 | Page 19

The eccentricity of the hyperbola x2 − 4y2 = 1 is

• $\frac{\sqrt{3}}{2}$

• $\frac{\sqrt{5}}{2}$

• $\frac{2}{\sqrt{3}}$

• $\frac{2}{\sqrt{5}}$

Q 9 | Page 19

The difference of the focal distances of any point on the hyperbola is equal to

• length of the conjugate axis

•  eccentricity

• length of the transverse axis

• Latus-rectum

Q 10 | Page 19

The foci of the hyperbola 9x2 − 16y2 = 144 are

• (± 4, 0)

• (0, ± 4)

•  (± 5, 0)

• (0, ± 5)

Q 11 | Page 19

The distance between the foci of a hyperbola is 16 and its eccentricity is $\sqrt{2}$, then equation of the hyperbola is

•  x2 + y2 = 32

• x2 − y2 = 16

• x2 + y2 = 16

•  x2 − y2 = 32

Q 12 | Page 19

If e1 is the eccentricity of the conic 9x2 + 4y2 = 36 and e2 is the eccentricity of the conic 9x2 − 4y2 = 36, then

• e12 − e22 = 2

• 2 < e22 − e12 < 3

• e22 − e12 = 2

• e22 − e12 > 3

Q 13 | Page 19

If the eccentricity of the hyperbola x2 − y2 sec2α = 5 is $\sqrt{3}$  times the eccentricity of the ellipse x2 sec2 α + y2 = 25, then α =

• $\frac{\pi}{6}$

• $\frac{\pi}{4}$

• $\frac{\pi}{3}$

• $\frac{\pi}{2}$

Q 14 | Page 19

The equation of the hyperbola whose foci are (6, 4) and (−4, 4) and eccentricity 2, is

• $\frac{(x - 1 )^2}{25/4} - \frac{(y - 4 )^2}{75/4} = 1$

• $\frac{(x + 1 )^2}{25/4} - \frac{(y + 4 )^2}{75/4} = 1$

• $\frac{(x - 1 )^2}{75/4} - \frac{(y - 4 )^2}{25/4} = 1$

• none of these

Q 15 | Page 19

The length of the straight line x − 3y = 1 intercepted by the hyperbola x2 − 4y2 = 1 is

• $\frac{6}{\sqrt{5}}$

• $3\sqrt{\frac{2}{5}}$

• $6\sqrt{\frac{2}{5}}$

•  none of these

Q 16 | Page 20

The latus-rectum of the hyperbola 16x2 − 9y2 = 144 is

• 16/3

•  32/3

•  8/3

•  4/3

Q 17 | Page 20

The foci of the hyperbola 2x2 − 3y2 = 5 are

• $( \pm 5/\sqrt{6}, 0)$

• (± 5/6, 0)

• $( \pm \sqrt{5}/6, 0)$

• none of these

Q 18 | Page 20

The eccentricity the hyperbola $x = \frac{a}{2}\left( t + \frac{1}{t} \right), y = \frac{a}{2}\left( t - \frac{1}{t} \right)$ is

• $\sqrt{2}$

• $\sqrt{3}$

• $2\sqrt{3}$

• $3\sqrt{2}$

Q 19 | Page 20

The equation of the hyperbola whose centre is (6, 2) one focus is (4, 2) and of eccentricity 2 is

• 3 (x − 6)2 − (y −2)2 = 3

• (x − 6)2 − 3 (y − 2)2 = 1

• (x − 6)2 − 2 (y −2)2 = 1

• 2 (x − 6)2 − (y − 2)2 = 1

Q 20 | Page 20

The locus of the point of intersection of the lines $\sqrt{3}x - y - 4\sqrt{3}\lambda = 0 \text { and } \sqrt{3}\lambda + \lambda - 4\sqrt{3} = 0$  is a hyperbola of eccentricity

• 1

• 2

• 3

• 4

## Chapter 27: Hyperbola

Exercise 27.1Others ## RD Sharma solutions for Class 11 Mathematics Textbook chapter 27 - Hyperbola

RD Sharma solutions for Class 11 Mathematics Textbook chapter 27 (Hyperbola) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the CBSE Class 11 Mathematics Textbook solutions in a manner that help students grasp basic concepts better and faster.

Further, we at Shaalaa.com provide such solutions so that students can prepare for written exams. RD Sharma textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.

Concepts covered in Class 11 Mathematics Textbook chapter 27 Hyperbola are Sections of a Cone, Concept of Circle, Introduction of Parabola, Standard Equations of Parabola, Latus Rectum, Introduction of Ellipse, Relationship Between Semi-major Axis, Semi-minor Axis and the Distance of the Focus from the Centre of the Ellipse, Special Cases of an Ellipse, Standard Equations of an Ellipse, Latus Rectum, Introduction of Hyperbola, Eccentricity, Standard Equation of Hyperbola, Latus Rectum, Standard Equation of a Circle, Eccentricity.

Using RD Sharma Class 11 solutions Hyperbola exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in RD Sharma Solutions are important questions that can be asked in the final exam. Maximum students of CBSE Class 11 prefer RD Sharma Textbook Solutions to score more in exam.

Get the free view of chapter 27 Hyperbola Class 11 extra questions for Class 11 Mathematics Textbook and can use Shaalaa.com to keep it handy for your exam preparation

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