#### Chapters

Chapter 2: Polynomials

Chapter 3: Pair of Linear Equations in Two Variables

Chapter 4: Quadratic Equations

Chapter 5: Arithmetic Progression

Chapter 6: Co-Ordinate Geometry

Chapter 7: Triangles

Chapter 8: Circles

Chapter 9: Constructions

Chapter 10: Trigonometric Ratios

Chapter 11: Trigonometric Identities

Chapter 12: Trigonometry

Chapter 13: Areas Related to Circles

Chapter 14: Surface Areas and Volumes

Chapter 15: Statistics

Chapter 16: Probability

#### RD Sharma 10 Mathematics

## Chapter 13: Areas Related to Circles

#### Chapter 13: Areas Related to Circles Exercise 13.10 solutions [Pages 12 - 13]

Find the circumference and area of circle of radius 4.2 cm

Find the circumference of a circle whose area is 301.84 cm^{2}.

Find the area of circle whose circumference is 44 cm.

The circumference of a circle exceeds diameter by 16.8 cm. Find the circumference of

circle.

A horse is tied to a pole with 28m long string. Find the area where the horse can graze.

A steel wire when bent is the form of square encloses an area of 12 cm2. If the same wire is bent in form of circle. Find the area of circle.

A horse is placed for grazing inside a rectangular field 40m by 36m and is tethered to one corner by a rope 14m long. Over how much area can it graze.

A sheet of paper is in the form of rectangle ABCD in which AB = 40cm and AD = 28 cm. A semicircular portion with BC as diameter is cut off. Find the area of remaining paper.

The circumference of two circles are in ratio 2:3. Find the ratio of their areas

The side of a square is 10 cm. find the area of circumscribed and inscribed circles.

The sum of the radii of two circles is 140 cm and the difference of their circumferences in 88 cm. Find the diameters of the circles.

The area of circle, inscribed in equilateral triangle is 154 cms2. Find the perimeter of

triangle.

A field is in the form of circle. A fence is to be erected around the field. The cost of fencing would to Rs. 2640 at rate of Rs.12 per metre. Then the field is to be thoroughs ploughed at cost of Rs. 0.50 per m2. What is amount required to plough the field?

If a square is inscribed in a circle, find the ratio of areas of the circle and the square.

A park is in the form of rectangle 120m × 100m. At the centre of park there is a circular lawn. The area of park excluding lawn is 8700m2. Find the radius of circular lawn.

The radii of two circles are 8 cm and 6 cm respectively. Find the radius of the circle having area equal to the sum of the areas of the two circles.

The radii of two circles are 19cm and 9 cm respectively. Find the radius and area of the circle which has circumferences is equal to sum of circumference of two circles.

A car travels 1 km distance in which each wheel makes 450 complete revolutions. Find the radius of wheel.

The area enclosed between the concentric circles is 770cm2. If the radius of outer circle 21cm. find the radius of inner circle

An archery target has three regions formed by three concentric circles as shown in figure15.8. If the diameters of the concentric circles are in the ratios 1 : 2 : 3 , then find the ratio of the areas of three regions .

The wheel of a motor cycle is of radius 35 cm . How many revolutions per minute must the wheel make so as to keep a speed of 66 km / hr ?

A circular pond is 17.5 m in diameter. It is surrounded by a 2m wide path, Find the cost of constructing the path at the rate of ₹ 25 per m^{2 }.

A circular park is surroundeed by a rod 21 m wide. If the radius of the park is 105 m, find the area of the road .

A square of diagonal 8 cm is inscribed in a circle. Find the area of the region lying outside the circle and inside the square .

Find the area enclosed between two concentric circles of radii 3.5 cm and 7 cm. A third concentric circle is drawn outside the 7 cm circle , such that the area enclosed between it and the 7 cm circle is same as that between the two inner circles . Find the radius of the third circle correct to one decimal place.

A path of width 3.5 m runs around a semi-circular grassy plot whose perimeter is 72 m . Find the area of the path .

`("Use" pi= 22/7) `

A circular pond is of diameter 17.5 m . It is surrounded by a 2m wide path . Find the cost of constructing the path at the rate of ₹25 per square metre (Use `pi=22/7`)

The outer circumference of a circular race-track is 528 m . The track is everywhere 14 m wide. Calculate the cost of levelling the track at the rate of 50 paise per square metre.

`(use pi=22/7). `

A road which is 7 m wide surrounds a circular park whose circumference is 352 m . Find the area of the road .

Prove that the area of a circular path of uniform width* h* surrounding a circular region of radius* r* is `pih(2r+h)`

#### Chapter 13: Areas Related to Circles Exercise 13.20 solutions [Pages 24 - 26]

Find in terms of x the length of the arc that subtends an angle of 30°, at the centre of circle of radius 4 cm.

Find the angle subtended at the centre of circle of radius 5cm by an arc of length `((5pi)/3)` cm

An arc of length 20𝜋 cm subtends an angle of 144° at centre of circle. Find the radius of the circle.

An arc of length 15 cm subtends an angle of 45° at the centre of a circle. Find in terms of 𝜋, radius of the circle.

Find the angle subtended at the centre of circle of radius ‘a’ cm by an arc of length

`(api)/4` 𝑐𝑚

A sector of circle of radius 4cm contains an angle of 30°. Find the area of sector

A sector of a circle of radius 8cm contains the angle of 135°. Find the area of sector.

The area of sector of circle of radius 2cm is 𝜋cm2. Find the angle contained by the sector.

The area of sector of circle of radius 5cm is 5𝜋 cm2. Find the angle contained by the sector.

AB is a chord of circle with centre O and radius 4cm. AB is length of 4cm. Find the area of sector of the circle formed by chord AB

In a circle of radius 35 cm, an arc subtends an angle of 72° at the centre. Find the length of arc and area of sector

The perimeter of a sector of circle of radius 5.7m is 27.2 m. Find the area of sector.

The perimeter of certain sector of circle of radius 5.6 m is 27.2 m. Find the area of sector.

A sector is cut-off from a circle of radius 21 cm the angle of sector is 120°. Find the length of its arc and its area.

The minute hand of a clock is √21 𝑐𝑚 long. Find area described by the minute hand on the face of clock between 7 am and 7:05 am

The minute hand of clock is10cm long. Find the area of the face of the clock described by the minute hand between 8am and 8:25 am

A sector of 56° cut out from a circle contains area of 4.4 cm2. Find the radius of the circle

Area of sector of central angle 200^{0} of a circle is 770 cm^{2} . Find the length of the corresponding arc of this sector .

The length of minute hand of a clock is 5 cm . Find the area swept by the minute hand during the time period 6:05 am and 6:40 am.

The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.

In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre. Find the length of the arc (Use π = 22/7)

In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre. Find area of the sector formed by the arc. (Use π = 22/7)

From a circular piece of cardboard of radius 3 cm two sectors of 90^{0} have been cutoff . Find the perimeter of the remaining portion nearest hundredth centimeters ( `"Take" pi = 22/ 7`).

The area of sector is one-twelfth that of the complete circle. Find the angle of the sector .

*AB* is a chord of a circle with centre *O* and radius 4 cm. *AB* is of length 4 cm. Find the area of the sector of the circle formed by chord *AB*.

In circle of radius 6cm, chord of length 10 cm makes an angle of 110° at the centre of circle find Circumference of the circle

In circle of radius 6cm, chord of length 10 cm makes an angle of 110° at the centre of circle find Area of the circle

In circle of radius 6cm, chord of length 10 cm makes an angle of 110° at the centre of circle find Length of arc

In circle of radius 6cm, chord of length 10 cm makes an angle of 110° at the centre of circle find The area of sector

Below fig shows a sector of a circle, centre O. containing an angle 𝜃°. Prove that

Area of shaded region is`r^2/2(tantheta −(pitheta)/180)`

Below fig shows a sector of a circle, centre O. containing an angle 𝜃°. Prove that Perimeter of shaded region is 𝑟 (tan 𝜃 + sec 𝜃 +`(pitheta)/180`− 1)

The diagram shows a sector of circle of radius ‘r’ can containing an angle 𝜃. The area of sector is A cm2 and perimeter of sector is 50 cm. Prove that

(i) 𝜃 =`360/pi(25/r− 1)`

(ii) A = 25r – r^{2}

#### Chapter 13: Areas Related to Circles Exercise 13.30 solutions [Pages 32 - 33]

AB is a chord of a circle with centre O and radius 4 cm. AB is of length 4 cm and divides the circle into two segments. Find the area of the minor segment.

A chord *PQ* of length 12 cm subtends an angle of 120° at the centre of a circle. Find the area of the minor segment cut off by the chord *PQ*.

A chord of circle of radius 14cm makes a right angle at the centre. Find the areas of minor and major segments of the circle.

A chord 10 cm long is drawn in a circle whose radius is 5√2 cm. Find the area of both

segments

A chord AB of circle, of radius 14cm makes an angle of 60° at the centre. Find the area of minor segment of circle.

Find the area of minor segment of a circle of radius 14 cm, when the angle of the corresponding sector is 60^{0} .

A chord of a circle of radius 20 cm sub tends an angle of 90^{0} at the centre . Find the area of the corresponding major segment of the circle

( Use \[\pi = 3 . 14\])

AB is the diameter of a circle, centre O. C is a point on the circumference such that ∠COB = 𝜃. The area of the minor segment cutoff by AC is equal to twice the area of sector BOC.Prove that `"sin"theta/2. "cos"theta/2= pi (1/2−theta/120^@)`

A chord of a circle subtends an angle 𝜃 at the centre of circle. The area of the minor segment cut off by the chord is one eighth of the area of circle. Prove that 8 sin`theta/2 "cos"theta/2+pi =(pitheta)/45`

#### Chapter 13: Areas Related to Circles Exercise 13.40 solutions [Pages 0 - 65]

A plot is in the form of rectangle ABCD having semi-circle on BC. If AB = 60m and BC = 28m, find the area of plot.

A playground has the shape of rectangle, with two semicircles on its smaller sides as diameters, added to its outside. If the sides of rectangle are 36m and 24.5m. find the area of playground.

Find the area of the circle in which a square of area 64 cm^{2} is inscribed. [Use π = 3.14]

A rectangular piece is 20m long and 15m wide from its four corners, quadrants of 3.5m radius have been cut. Find the area of remaining part.

In the following figure, PQRS is a square of side 4 cm. Find the area of the shaded square.

Four cows are tethered at four corners of a square plot of side 50m, so that’ they just cant reach one another. What area will be left ungrazed.

A cow is tied with a rope of length 14 m at the corner of a rectangular field of dimensions `20 m xx 16 m` find the area of the field in which the cow can graze .

A calf is tied with a rope of length 6 m at the corner of a square grassy lawn of side 20 m . If the length of the rope is increased by 5.5 m , find the increase in area of the grassy lawn in which the calf can graze .

A square water tank has its side equal to 40 m. There are four semi-circular grassy plots all round it. Find the cost of turfing the plot at Rs. 1.25 per square metre (Take π = 3.14).

A rectangular park is 100 m by 50 m. It is surrounding by semi-circular flower beds all round. Find the cost of levelling the semi-circular flower beds at 60 paise per square metre (use π = 3.14).

The inside perimeter of a running track (shown in the following figure) is 400 m. The length of each of the straight portion is 90 m and the ends are semi-circles. If the track is everywhere 14 m wide. find the area of the track. Also find the length of the outer running track.

Find the area of the following figure, in square cm, correct to one place of decimal. (Take π = 22/7).

In the following figure, from a rectangular region ABCD with AB = 20 cm, a right triangle AED with AE = 9 cm and DE = 12 cm, is cut off. On the other end, taking BC as diameter, a semicircle is added on outside' the region. Find the area of the shaded region. [Use π =]`22/7` [CBSE 2014]

From each of the two opposite corners of a square of side 8 cm, a quadrant of a circle of radius 1.4 cm is cut. Another circle of radius 4.2 cm is also cut from the centre as shown in the following figure. Find the area of the remaining (Shaded) portion of the square. (Use π = 22/7)

In the following figure, *ABCD* is a rectangle with *AB* = 14 cm and *BC* = 7 cm. Taking *DC*, *BC* and *AD* as diameters, three semi-circles are drawn as shown in the figure. Find the area of the shaded region.

In the following figure, *ABCD* is a rectangle, having *AB *= 20 cm and *BC* = 14 cm. Two sectors of 180° have been cut off. Calculate:

the area of the shaded region.

In the following figure, *ABCD* is a rectangle, having *AB *= 20 cm and *BC* = 14 cm. Two sectors of 180° have been cut off. Calculate:

the length of the boundary of the shaded region.

In the following figure, the square *ABCD *is divided into five equal parts, all having same area. The central part is circular and the ines *AE*, *GC*, *BF* and *HD* lie along the diagonals *AC* and *BD* of the square. If *AB* = 22 cm, find:

the circumference of the central part.

In the following figure, the square *ABCD *is divided into five equal parts, all having same area. The central part is circular and the lines *AE*, *GC*, *BF* and *HD* lie along the diagonals *AC* and *BD* of the square. If *AB* = 22 cm, find:

the perimeter of the part *ABEF*.

In the following figure find the area of the shaded region. (Use π = 3.14)

In the following figure, *OACB* is a quadrant of a circle with centre *O* and radius 3.5 cm. If *OD* = 2 cm, find the area of the (i) quadrant *OACB* (ii) shaded region.

In the following figure a square OABC is inscribed in a quadrant OPBQ of a circle. If OA = 21 cm, find the area of the shaded region.

In the following figure, OABC is a square of side 7 cm. If OAPC is a quadrant of a circle with centre O, then find the area of the shaded region. (Use π = 22/7)

In the following figure, *OE* = 20 cm. In sector *OSFT*, square *OEFG* is inscribed. Find the area of the shaded region.

Find the area of the shaded region in the following figure, if AC = 24 cm, BC = 10 cm and O is the centre of the circle. (Use π = 3.14)

A circle is inscribed in an equilateral triangle ABC is side 12 cm, touching its sides (the following figure). Find the radius of the inscribed circle and the area of the shaded part.

In the following figure, an equilateral triangle ABC of side 6 cm has been inscribed in a circle. Find the area of the shaded region. (Take π = 3.14).

A circular field has a perimeter of 650 m. A square plot having its vertices on the circumference of the field is marked in the field. Calculate the area of the square plot.

Find the area of a shaded region in the the following figure,where a circular arc of radius 7 cm has been drawn with vertex A of an equilateral triangle ABC of side 14 cm as centre. (Use π = 22/7 and \[\sqrt{3}\] = 1.73)

A regular hexagon is inscribed in a circle. If the area of hexagon is \[24\sqrt{3}\] , find the area of the circle. (Use π = 3.14)

*ABCDEF* is a regular hexagon with centre O (in the following figure). If the area of triangle *OAB* is 9 cm^{2}, find the area of : (i) the hexagon and (ii) the circle in which the haxagon is incribed.

Four equal circles, each of radius 5 cm touch each other as shown in fig. Find the area included etween them.

Four equal circles each of radius a, touch each other. Show that area between them is `6/7a^2`

A child makes a poster on a chart paper drawing a square ABCD of side 14 cm. She draws four circles with centre A, B, C and D in which she suggests different ways to save energy. The circles are drawn in such a way that each circle touches externally two of the three remaining circles (in the following figure). In the shaded region she write a message 'Save Energy'. Find the perimeter and area of the shaded region.

(Use π = 22/7)

The diameter of a coin is 1 cm (in the following figure). If four such coins be placed on a table so that the rim of each touches that of the other two, find the area of the shaded region (Take π = 3.1416).

Two circular pieces of equal radii and maximum area, touching each other are cut out from a rectangular card board of dimensions 14 cm × 7 cm. Find the area of the remaining card board. (Use π = 22/7).

Two circular pieces of equal radii and maximum area, touching each other are cut out from a rectangular card board of dimensions 14 cm × 7 cm. Find the area of the remaining card board. (Use π = 22/7).

In the following figure, *AB* and *CD* are two diameters of a circle perpendicular to each other and *OD* is the diameter of the smaller circle. If *OA* = 7 cm, find the area of the shaded region.

In the the following figure, PSR, RTQ and PAQ are three semicircles of diameter 10 cm, 3 cm and 7 cm respectively. Find the perimeter of shaded region.

In the following figure, two circles with centres *A* and *B* touch each other at the point *C*. If *AC* = 8 cm and *AB* = 3 cm, find the area of the shaded region.

In the following figure, ABCD is a square of side 2a, Find the ratio between

(i) the circumferences

(ii) the areas of the in circle and the circum-circle of the square.

In the following figure, there are three semicircles, A, B and C having diameter 3 cm each, and another semicircle E having a circle D with diameter 4.5 cm are shown. Calculate:

(i) the area of the shaded region

(ii) the cost of painting the shaded region at the rate of 25 paise per cm^{2} , to the nearest rupee.

In the following figure, *ABC* is a right-angled triangle, ∠*B* = 90°, *AB* = 28 cm and *BC* = 21 cm. With *AC* as diameter a semicircle is drawn and with *BC* as radius a quarter circle is drawn. Find the area of the shaded region correct to two decimal places.

In the following figure, *O* is the centre of a circular arc and *AOB* is a straight line. Find the perimeter and the area of the shaded region correct to one decimal place. (Take π = 3.142)

In the following figure, the boundary of the shaded region consists of four semi-circular arcs, the smallest two being equal. If the diameter of the largest is 14 cm and of the smallest is 3.5 cm, find

the length of the boundary.

the area of the shaded region.

In the following figure, *AB* = 36 cm and M is mid-point of *A*B. Semi-circles are drawn on *AB*, *AM* and *MB *as diameters. *A* circle with centre *C* touches all the three circles. Find the area of the shaded region.

In the following figure, *ABC* is a right angled triangle in which ∠*A* = 90°, *AB* = 21 cm and *AC* = 28 cm. Semi-circles are described on *AB*, *BC* and *AC* as diameters. Find the area of the shaded region.

In the following figure, shows the cross-section of railway tunnel. The radius *OA* of the circular part is 2 m. If ∠*AOB* = 90°, calculate:

the height of the tunnel

In the following figure, shows the cross-section of railway tunnel. The radius *OA* of the circular part is 2 m. If ∠*AOB* = 90°, calculate:

the perimeter of the cross-section

In the following figure, shows the cross-section of railway tunnel. The radius *OA* of the circular part is 2 m. If ∠*AOB* = 90°, calculate:

the area of the cross-section.

In the following figure, shows a kite in which *BCD* is the shape of a quadrant of a circle of radius 42 cm. *ABCD* is a square and Δ *CEF* is an isosceles right angled triangle whose equal sides are 6 cm long. Find the area of the shaded region.

In the following figure, ABCD is a trapezium of area 24.5 cm^{2} , If AD || BC, ∠DAB = 90°, AD = 10 cm, BC = 4 cm and ABE is quadrant of a circle, then find the area of the shaded region. [CBSE 2014]

In the given figure, ABCD is a trapezium with AB || DC, AB = 18 cm DC = 32 cm and the distance between AB and DC is 14 cm. Circles of equal radii 7 cm with centres A, B, C and D have been drawn. Then find the area of the shaded region.

(Use \[\pi = \frac{22}{7}\]

From a thin metallic piece, in the shape of a trapezium *ABCD*, in which *AB* || *CD* and ∠*BCD* = 90°, a quarter circle *BEFC* is removed (in the following figure). Given *AB* = *BC* = 3.5 cm and *DE* = 2 cm, calculate the area of the remaining piece of the metal sheet.

In the following figure, ABC is an equilateral triangle of side 8 cm. A, B and C are the centres of circular arcs of radius 4 cm. Find the area of the shaded region correct upto 2 decimal places. (Take π =3.142 and`sqrt3` = 1.732).

Sides of a triangular field are 15 m , 16 m , 17 m . With three corners of the field a cow , a buffalo and a horse are tied separately with ropes of length 7 m each to graze in the field . Find the area of the field which cannot be grazed by three animals.

In the given figure, the side of square is 28 cm and radius of each circle is half of the length of the side of the square where O and O' are centres of the circles. Find the area of shaded region.

In a hospital used water is collected in a cylindrical tank of diameter 2 m and height 5 m. After recycling, this water is used to irrigate a park of hospital whose length is 25 m and breadth is 20 m. If tank is filled completely then what will be the height of standing water used for irrigating the park.

#### Chapter 13: Areas Related to Circles solutions [Pages 67 - 68]

What is the ratio of the areas of a circle and an equilateral triangle whose diameter and a side are respectively equal?

If the circumference of two circles are in the ratio 2 : 3, what is the ratio of their areas?

Write the area of the sector of a circle whose radius is* r* and length of the arc is l.

What is the length (in terms of π) of the arc that subtends an angle of 36° at the centre of a circle of radius 5 cm?

What is the angle subtended at the centre of a circle of radius 6 cm by an arc of length 3 π cm?

What is the area of a sector of a circle of radius 5 cm formed by an arc of length 3.5 cm?

In a circle of radius 10 cm, an arc subtends an angle of 108° at the centre. what is the area of the sector in terms of π?

If a square is inscribed in a circle, what is the ratio of the areas of the circle and the square?

Write the formula for the area of a sector of angle \[\theta\] (in degrees) of a circle of radius r.

Write the formula for the area of a segment in a circle of radius r given that the sector angle is \[\theta\] (in degrees).

If the adjoining figure is a sector of a circle of radius 10.5 cm, what is the perimeter of the sector? (Take \[\pi = 22/7\])

If the diameter of a semi-circular protractor is 14 cm, then find its perimeter.

An arc subtends an angle of 90° at the centre of the circle of the radius 14 cm. Write the area of minor sector thus formed in terms of π.

Find the area of the largest triangle that can be inscribed in a semi-circle of radius* r*units.

Find the area of sector of circle of radius 21 cm and central angle 120^{0}.

What is the area of a square inscribed in a circle of diameter *p *cm ?

If the numerical value of the area of a circle is equal to the numerical value of its circumference , find its radius.

How many revolutions a circular wheel of radius *r *metres makes in covering a distance of *s* metres?

Find the ratio of the area of the circle circumscribing a square to the area of the circle inscribed in the square .

#### Chapter 13: Areas Related to Circles solutions [Pages 69 - 74]

If the circumference and the area of a circle are numerically equal, then diameter of the circle is

\[\frac{\pi}{2}\]

2\[\frac{\pi}{2}\]

2

4

If the difference between the circumference and radius of a circle is 37 cm, then using π = \[\frac{22}{7}\] the circumference (in cm) of the circle is

154

44

14

7

A wire can be bent in the form of a circle of radius 56 cm. If it is bent in the form fo a square, then its area will be

3520 cm

^{2}6400 cm

^{2}7744 cm

^{2}8800 cm

^{2}

If a wire is bent into the shape of a square, then the area of the square is 81 cm^{2} . When wire is bent into a semi-circular shape, then the area of the semi-circle will be

22 cm

^{2}44 cm

^{2}77 cm

^{2}154 cm

^{2}

A circular park has a path of uniform width around it. The difference between the outer and inner circumferences of the circular path is 132 m. Its width is

20 m

21 m

22 m

24 m

The radius of a wheel is 0.25 m. The number of revolutions it will make to travel a distance of 11 km will be

2800

4000

5500

7000

The ratio of the outer and inner perimeters of a circular path is 23 : 22. If the path is 5 metres wide, the diameter of the inner circle is

55 m

110 m

220 m

230 m

The circumference of a circle is 100 m. The side of a square inscribed in the circle is

50\[\sqrt{2}\]

\[\frac{50}{\pi}\]

\[\frac{50\sqrt{2}}{\pi}\]

\[\frac{100\sqrt{2}}{\pi}\]

The area of the incircle of an equilateral triangle of side 42 cm is

\[22\sqrt{3} c m^2\]

231 cm

^{2}462 cm

^{2}924 cm

^{2}

The area of incircle of an equilateral triangle is 154 cm^{2} . The perimeter of the triangle is

71.5 cm

71.7 cm

72.3 cm

72.7 cm

The area of the largest triangle that can be inscribed in a semi-circle of radius r, is

r

^{2}2r

^{2}r

^{3}2r

^{3}

The perimeter of a triangle is 30 cm and the circumference of its incircle is 88 cm. The area of the triangle is

70 cm

^{2}140 cm

^{2}210 cm

^{2}420 cm

^{2}

The area of a circle is 220 cm^{2}. The area of ta square inscribed in it is

49 cm

^{2}70 cm

^{2}140 cm

^{2}150 cm

^{2 }

If the circumference of a circle increases from 4π to 8π, then its area is

halved

doubled

tripled

quadrupled

If the radius of a circle is diminished by 10%, then its area is diminished by

10%

19%

20%

36%

If the area of a square is same as the area of a circle, then the ratio of their perimeters, in terms of π, is

π :\[\sqrt{3}\]

2 : \[\sqrt{\pi}\]

3 :\[\pi\]

\[\pi : \sqrt{2}\]

The area of the largest triangle that can be inscribed in a semi-circle of radius r is

2

*r**r*^{2}*r*\[\sqrt{r}\]

The ratio of the areas of a circle and an equilateral triangle whose diameter and a side are respectively equal, is

\[\pi: \sqrt{2}\]

\[\pi: \sqrt{3}\]

\[\sqrt{3}: \pi\]

\[\sqrt{2}: \pi\]

If the sum of the areas of two circles with radii r_{1} and r_{2} is equal to the area of a circle of radius r, then \[r_1^2 + r_2^2\]

>r

^{2}=r

^{2}<r

^{2}None of these

If the perimeter of a semi-circular protractor is 36 cm, then its diameter is

10 cm

12 cm

14 cm

16 cm

The perimeter of the sector *OAB *shown in the following figure, is

\[\frac{64}{3} cm\]

26 cm

\[\frac{64}{5} cm\]

19 cm

If the perimeter of a sector of a circle of radius 6.5 cm is 29 cm, then its area is

58 cm

^{2}52 cm

^{2}25 cm

^{2}56 cm

^{2}

If the area of a sector of a circle bounded by an arc of length 5π cm is equal to 20π cm^{2}, then its radius is

12 cm

16 cm

8 cm

10 cm

The area of the circle that can be inscribed in a square of side 10 cm is

40 π cm

^{2}30 π cm

^{2}100 π cm

^{2}25 π cm

^{2}

If the difference between the circumference and radius of a circle is 37 cm, then its area is

154 cm

^{2}160 cm

^{2}200 cm

^{2}150 cm

^{2}

The area of a circular path of uniform width h surrounding a circular region of radius r is

\[\pi(2r + h)r\]

\[\pi(2r + h)r\]

\[\pi(2r + h)h\]

\[\pi(h + r)r\]

\[\pi(h + r)h\]

If *AB* is a chord of length \[5\sqrt{3}\] cm of a circle with centre *O* and radius 5 cm, then area of sector *OAB* is

\[\frac{3\pi}{8}c m^2 \]

\[\frac{8\pi}{3}c m^2\]

\[25 \pi cm^2\]

\[\frac{25\pi}{3}c m^2\]

The area of a circle whose area and circumference are numerically equal, is

2 \[\pi\] sq. units

4 \[\pi\] units

6\[\pi\]sq. units

8 \[\pi\] sq. units

If diameter of a circle is increased by 40%, then its area increase by

96%

40%

80%

48%

In the following figure, the shaded area is

50 (π−2) cm

^{2}25 (π−2) cm

^{2}25 (π+2) cm

^{2}5 (π−2) cm

^{2}

In the following figure, the area of the segment *PAQ* is

\[\frac{a^2}{4}\left( \pi + 2 \right)\]

\[\frac{a^2}{4}\left( \pi - 2 \right)\]

\[\frac{a^2}{4}\left( \pi - 1 \right)\]

\[\frac{a^2}{4}\left( \pi + 1 \right)\]

If the area of a sector of a circle bounded by an arc of length 5π cm is equal to 20π cm^{2}, then the radius of the circle

12 cm

16 cm

8 cm

10 cm

If the area of a sector of a circle is `5/18` of the area of the circle, then the sector angle is equal to

60°

90°

100°

120°

If he area of a sector of a circle is \[\frac{7}{20}\] of the area of the circle, then the sector angle is equal to

110°

130°

100°

126°

In the following figure, If ABC is an equilateral triangle, then shaded area is equal to

\[\left( \frac{\pi}{3} - \frac{\sqrt{3}}{4} \right) r^2\]

\[\left( \frac{\pi}{3} - \frac{\sqrt{3}}{2} \right) r^2\]

\[\left( \frac{\pi}{3} + \frac{\sqrt{3}}{4} \right) r^2\]

\[\left( \frac{\pi}{3} + \sqrt{3} \right) r^2\]

In the following figure, the area of the shaded region is

3π cm

^{2}6π cm

^{2}9π cm

^{2}7π cm

^{2}

If the perimeter of a circle is equal to that of a square, then the ratio of their areas is

13 : 22

14 : 11

22 : 13

11 : 14

The radius of a circle is 20 cm. It is divided into four parts of equal area by drawing three concentric circles inside it. Then, the radius of the largest of three concentric circles drawn is

10 \[\sqrt{5}\]

10\[\sqrt{3}\]cm

10\[\sqrt{5}\]

10\[\sqrt{2}\]

The area of a sector whose perimeter is four times its radius r units, is

\[\frac{r^2}{4}\]

2r

^{2}sq. unitsr

^{2}sq.units

If a chord of a circle of radius 28 cm makes an angle of 90 ° at the centre, then the area of the major segment is

392 cm

^{2}1456 cm

^{2}1848 cm

^{2}2240 cm

^{2}

If area of a circle inscribed in an equilateral triangle is 48π square units, then perimeter of the triangle is

17 \[\sqrt{3}\]units

36 units

72 units

48\[\sqrt{3}\]units

The hour hand of a clock is 6 cm long. The area swept by it between 11.20 am and 11.55 am is

2.75 cm

^{2}5.5 cm

^{2 }11 cm

^{2}10 cm

^{2}

*ABCD* is a square of side 4 cm. If *E* is a point in the interior of the square such that Δ*CED*is equilateral, then area of Δ *ACE* is

\[2\sqrt{3} - 1 c m^2\]

\[4\sqrt{3} - 1 c m^2\]

\[6\sqrt{3} - 1 c m^2\]

\[8\sqrt{3} - 1 c m^2\]

If the area of a circle is equal to the sum of the areas of two circles of diameters 10 cm and 24 cm, then diameter of the large circle (in cm) is

34

26

17

14

If π is taken as \[\frac{22}{7}\] the distance (in metres) covered by a wheel of diameter 35 cm, in one revolution, is

2.2

1.1

9.625

96.25

ABCD is a rectangle whose three vertices are B (4,0), C (4,3) and D (0, 3). The length of one of its diagonals is

5

4

3

25

Area of the largest triangle that can be inscribed in a semi-circle of radius *r* units is

*r*sq. units^{2 }\[\frac{1}{2}\]

2

*r*sq. units^{2 }\[\sqrt{2}\]

If the sum of the areas of two circles with radii \[r_1\]and \[r_2\] is equal to the area of circle of radius \[r\] then

\[r = r_1 + r_2\]

\[{r_1}^2 + {r_2}^2 = r^2\]

\[r_1 + r_2 < r\]

\[{r_1}^2 + {r_2}^2 < r^2\]

If the sum of the circumferences of the two circles with radii \[r_1\] and \[r_2\] is equal to the circumference of a circle of radius \[r\] then

\[r = r_1 + r_2\]

\[r_1 + r_2 > r\]

\[r_1 + r_2 < r\]

None of these

If the circumference of a circle and the perimeter of a square are equal , then

Area of the circle = Area of the square

Area of the circle < Area of the square

Area of the circle > Area of the square

nothing definite can be said

If the perimeter of a circle is equal to that of a square , then the ratio of their areas is

22 : 7

14 : 11

7 : 22

11 : 14

## Chapter 13: Areas Related to Circles

#### RD Sharma 10 Mathematics

#### Textbook solutions for Class 10

## RD Sharma solutions for Class 10 Mathematics chapter 13 - Areas Related to Circles

RD Sharma solutions for Class 10 Maths chapter 13 (Areas Related to Circles) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the CBSE 10 Mathematics solutions in a manner that help students grasp basic concepts better and faster.

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Concepts covered in Class 10 Mathematics chapter 13 Areas Related to Circles are Theorem of External Division of Chords, Theorem of Internal Division of Chords, Converse of Theorem of the Angle Between Tangent and Secant, Theorem of Angle Between Tangent and Secant, Converse of Cyclic Quadrilateral Theorem, Corollary of Cyclic Quadrilateral Theorem, Theorem of Cyclic Quadrilateral, Corollaries of Inscribed Angle Theorem, Inscribed Angle Theorem, Intercepted Arc, Inscribed Angle, Property of Sum of Measures of Arcs, Tangent Segment Theorem, Converse of Tangent Theorem, Circles passing through one, two, three points, Tangent Properties - If Two Circles Touch, the Point of Contact Lies on the Straight Line Joining Their Centers, Cyclic Properties, Tangent - Secant Theorem, Cyclic Quadrilateral, Angle Subtended by the Arc to the Point on the Circle, Angle Subtended by the Arc to the Centre, Introduction to an Arc, Touching Circles, Number of Tangents from a Point on a Circle, Tangent to a Circle, Tangents and Its Properties, Theorem - Converse of Tangent at Any Point to the Circle is Perpendicular to the Radius, Number of Tangents from a Point to a Circle, Areas of Combinations of Plane Figures, Areas of Sector and Segment of a Circle, Perimeter and Area of a Circle, Problems Based on Areas and Perimeter Or Circumference of Circle, Sector and Segment of a Circle, Areas Related to Circles Examples and Solutions.

Using RD Sharma Class 10 solutions Areas Related to Circles exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in RD Sharma Solutions are important questions that can be asked in the final exam. Maximum students of CBSE Class 10 prefer RD Sharma Textbook Solutions to score more in exam.

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