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NCERT solutions for Class 12 Mathematics chapter 11 - Three Dimensional Geometry

Mathematics Textbook for Class 12

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Chapters

NCERT Mathematics Class 12

Mathematics Textbook for Class 12

Chapter 11: Three Dimensional Geometry

Chapter 11: Three Dimensional Geometry solutions [Page 467]

Q 2 | Page 467

Find the direction cosines of a line which makes equal angles with the coordinate axes.

Chapter 11: Three Dimensional Geometry solutions [Pages 467 - 478]

Q 1 | Page 467

If a line makes angles 90°, 135°, 45° with xy and z-axes respectively, find its direction cosines.

Q 3 | Page 467

If a line has the direction ratios −18, 12, −4, then what are its direction cosines?

Q 4 | Page 477

Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector.`3hati+2hatj-2hatk`

Q 4 | Page 467

Show that the points (2, 3, 4), (−1, −2, 1), (5, 8, 7) are collinear.

Q 5 | Page 467

Find the Direction Cosines of the Sides of the Triangle Whose Vertices Are (3, 5, -4), (-1, 1, 2) and (-5, -5, -2)

Q 5 | Page 477

Find the equation of the line in vector and in Cartesian form that passes through the point with position vector `2hati -hatj+4hatk`  and is in the direction `hati + 2hatj - hatk`.

Q 6 | Page 477

Find the Cartesian equation of the line which passes through the point (−2, 4, −5) and parallel to the line given by `(x+3)/3 = (y-4)/5 = ("z"+8)/6`

Q 7 | Page 477

The Cartesian equation of a line is `(x-5)/3 = (y+4)/7 = ("z"-6)/2` Write its vector form.

The given line passes through the point (5, −4, 6). The position vector of this point is `veca = 5hati - 4hatj + 6hatk`

Also, the direction ratios of the given line are 3, 7, and 2.

This means that the line is in the direction of vector, `vecb =3hati +7hatj + 2hatk`

It is known that the line through position vector `veca` and in the direction of the vector `vecb`is given by the equation, `vecr = veca+lambdavecb, lambda in R`

This is the required equation of the given line in vector form.

Q 8 | Page 477

Find the vector and the Cartesian equations of the lines that pass through the origin and (5, −2, 3).

Q 9 | Page 478

Find the vector and the Cartesian equations of the line that passes through the points (3, −2, −5), (3, −2, 6).

 

Chapter 11: Three Dimensional Geometry solutions [Pages 477 - 478]

Q 1 | Page 477

Show that the three lines with direction cosines `12/13,(-3)/13,(-4)/13; 4/13,12/13,3/13;3/13,(-4)/13,12/13 ` are mutually perpendicular.

Q 2 | Page 477

Show that the line through the points (1, −1, 2) (3, 4, −2) is perpendicular to the line through the points (0, 3, 2) and (3, 5, 6).

Q 3 | Page 477

Show that the line through the points (4, 7, 8) (2, 3, 4) is parallel to the line through the points (−1, −2, 1), (1, 2, 5).

Q 10.1 | Page 478

Find the angle between the following pairs of lines:

`vecr = 2hati - 5hatj + hatk + lambda(3hati - 2hatj + 6hatk) and vecr = 7hati - 6hatk + mu(hati + 2hatj + 2hatk)`

Q 10.2 | Page 478

Find the angle between the following pairs of lines:

`vecr = 3hati + hatj - 2hatk + lambda(hati - hatj - 2hatk) and vecr = 2hati - hatj -56hatk + mu(3hati - 5hatj - 4hatk)`

Q 11.1 | Page 478

Find the angle between the following pairs of lines: 

`(x-2)/2 = (y-1)/5 = (z+3)/(-3)` and `(x+2)/(-1) = (y-4)/8 = (z -5)/4`

Q 11.2 | Page 478

Find the angle between the following pairs of lines:

`x/y = y/2 = z/1` and `(x-5)/4 = (y-2)/1 = (z - 3)/8`

Q 12 | Page 478

Find the values of p so the line `(1-x)/3 = (7y-14)/2p = (z-3)/2` and `(7-7x)/(3p) = (y -5)/1 = (6-z)/5` are at right angles.

Q 13 | Page 478

Show that the lines `(x-5)/7 = (y + 2)/(-5) = z/1` and `x/1 = y/2 = z/3` are perpendicular to each other.

Q 14 | Page 478

Find the shortest distance between the lines 

`vecr = (hati+2hatj+hatk) + lambda(hati-hatj+hatk)` and `vecr = 2hati - hatj - hatk + mu(2hati + hatj + 2hatk)`

Q 15 | Page 478

Find the shortest distance between the lines `(x+1)/7 = `(y+1)/(-6) = (z+1)/1` and (x-3)/1 = (y-5)/(-2) = (z-7)/1`

Q 16 | Page 478

Find the shortest distance between the lines whose vector equations are `vecr = (hati + 2hatj + 3hatk) + lambda(hati - 3hatj + 2hatk)` and `vecr = 4hati + 5hatj + 6hatk + mu(2hati + 3hatj + hatk)`

Q 17 | Page 478

Find the shortest distance between the lines whose vector equations are

`vecr = (1-t)hati + (t - 2)hatj + (3 -2t)hatk` and `vecr = (s+1)hati + (2s + 1)hatk`

Chapter 11: Three Dimensional Geometry solutions [Pages 493 - 494]

Q 1 | Page 493

In following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

z = 2

Q 1.2 | Page 493

In following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

x + y + z = 1

Q 1.3 | Page 493

In following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

2x + 3y – z = 5

Q 1.4 | Page 493

In following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

5y + 8 = 0

Q 2 | Page 493

Find the vector equation of a plane which is at a distance of 7 units from the origin and normal to the vector.`3hati + 5hatj - 6hatk`

Q 3 | Page 493

In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.

x + y + z = 1

Q 3.1 | Page 493

Find the Cartesian equation of the following planes:

`vecr.(hati + hatj-hatk) = 2`

Q 3.2 | Page 493

Find the Cartesian equation of the following planes:

`vecr.(2hati + 3hatj-4hatk) = 1`

Q 3.3 | Page 493

Find the Cartesian equation of the following planes:

`vecr.[(s-2t)hati + (3 - t)hatj + (2s + t)hatk] = 15`

Q 4.1 | Page 493

In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.

2x + 3y + 4z – 12 = 0

Q 4.2 | Page 493

In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.

3y + 4z – 6 = 0

Q 4.4 | Page 493

In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.

5y + 8 = 0

Q 5.1 | Page 493

Find the vector and Cartesian equation of the planes that passes through the point (1, 0, −2) and the normal to the plane is `hati + hatj - hatk`

Q 5.2 | Page 493

Find the vector and Cartesian equation of the planes that passes through the point (1, 4, 6) and the normal vector to the plane is `hati -2hatj +  hatk`

Q 6.1 | Page 493

Find the equations of the planes that passes through three points.

(1, 1, −1), (6, 4, −5), (−4, −2, 3)

Q 6.2 | Page 493

Find the equations of the planes that passes through three points.

(1, 1, 0), (1, 2, 1), (−2, 2, −1)

Q 7 | Page 493

Find the intercepts cut off by the plane 2x + y – z = 5.

Q 8 | Page 493

Find the equation of the plane with intercept 3 on the y-axis and parallel to ZOX plane.

Q 9 | Page 493

Find the equation of the plane through the intersection of the planes 3x – y + 2z – 4 = 0 and x + y + z – 2 = 0 and the point (2, 2, 1).

Q 10 | Page 493

Find the vector equation of the plane passing through the intersection of the planes `vecr.(2hati + 2hatj - 3hatk) = 7, vecr.(2hati + 5hatj + 3hatk) = 9` and through the point (2, 1, 3)

Q 11 | Page 493

Find the equation of the plane through the line of intersection of the planes x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane x − y + z = 0. Also find the distance of the plane, obtained above, from the origin.

Q 12 | Page 494

Find the angle between the planes whose vector equations are `vecr.(2hati + 2hatj - 3hatk) = 5 and hatr.(3hati - 3hatj  + 5hatk) = 3`

Q 13.1 | Page 494

In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them.

7x + 5y + 6z + 30 = 0 and 3x – y – 10z + 4 = 0

Q 13.2 | Page 494

In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them.

2x + y + 3z – 2 = 0 and x – 2y + 5 = 0

 

Q 13.3 | Page 494

In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them.

2x – 2y + 4z + 5 = 0 and 3x – 3y + 6z – 1 = 0

Q 13.4 | Page 494

In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them.

2x – y + 3z – 1 = 0 and 2x – y + 3z + 3 = 0

Q 13.5 | Page 494

In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them.

4x + 8y + z – 8 = 0 and y + z – 4 = 0

Q 14.1 | Page 494

In the given cases, find the distance of each of the given points from the corresponding given plane.

Point                    Plane
(0, 0, 0)           3x – 4y + 12 z = 3

Q 14.2 | Page 494

In the given cases, find the distance of each of the given points from the corresponding given plane

Point                   Plane

(3, – 2, 1)             2x – y + 2z + 3 = 0

Q 14.3 | Page 494

In the given cases, find the distance of each of the given points from the corresponding given plane.

Point                 Plane

(2, 3, – 5)           x + 2y – 2z = 9

Q 14.4 | Page 494

In the given cases, find the distance of each of the given points from the corresponding given plane.

Point              Plane

(– 6, 0, 0)        2x – 3y + 6z – 2 = 0

Chapter 11: Three Dimensional Geometry solutions [Pages 497 - 499]

Q 1 | Page 497

Show that the line joining the origin to the point (2, 1, 1) is perpendicular to the line determined by the points (3, 5, – 1), (4, 3, – 1).

Q 2 | Page 497

If l1m1n1 and l2m2n2 are the direction cosines of two mutually perpendicular lines, show that the direction cosines of the line perpendicular to both of these are m1n2 − m2n1n1l2 − n2l1l1m2 ­− l2m1.

Q 3 | Page 498

Find the angle between the lines whose direction ratios are aband b − cc − aa − b.

Q 4 | Page 498

Find the equation of a line parallel to x-axis and passing through the origin.

Q 5 | Page 498

If the coordinates of the points A, B, C, D be (1, 2, 3), (4, 5, 7), (­−4, 3, −6) and (2, 9, 2) respectively, then find the angle between the lines AB and CD.

Q 6 | Page 498

If the lines `(x-1)/(-3) = (y -2)/(2k) = (z-3)/2 and (x-1)/(3k) = (y-1)/1 = (z -6)/(-5)` are perpendicular, find the value of k.

Q 7 | Page 498

Find the vector equation of the plane passing through (1, 2, 3) and perpendicular to the plane `vecr.(hati + 2hatj -5hatk) + 9 = 0`

Q 8 | Page 498

Find the equation of the plane passing through (abc) and parallel to the plane `vecr.(hati + hatj + hatk) = 2`

Q 9 | Page 498

Find the shortest distance between lines `vecr = 6hati + 2hatj + 2hatk + lambda(hati - 2hatj + 2hatk)` and `vecr =-4hati - hatk + mu(3hati - 2hatj - 2hatk)`

Q 10 | Page 498

Find the coordinates of the point where the line through (5, 1, 6) and (3, 4, 1) crosses the YZ-plane

Q 11 | Page 498

Find the coordinates of the point where the line through (5, 1, 6) and (3, 4, 1) crosses the ZX − plane.

Q 12 | Page 498

Find the coordinates of the point where the line through (3, ­−4, −5) and (2, − 3, 1) crosses the plane 2x + z = 7).

Q 13 | Page 498

Find the equation of the plane passing through the point (−1, 3, 2) and perpendicular to each of the planes x + 2+ 3z = 5 and 3x + 3z = 0.

Q 14 | Page 498

If the points (1, 1, p) and (−3, 0, 1) be equidistant from the plane `vecr.(3hati + 4hatj - 12hatk)+ 13 = 0`, then find the value of p.

Q 15 | Page 498

Find the equation of the plane passing through the line of intersection of the planes `vecr.(hati + hatj + hatk) = 1` and `vecr.(2hati + 3hatj -hatk) + 4 = 0` and parallel to x-axis.

Q 16 | Page 498

If O be the origin and the coordinates of P be (1, 2, −3), then find the equation of the plane passing through P and perpendicular to OP.

Q 17 | Page 498

Find the equation of the plane which contains the line of intersection of the planes `vecrr.(hati + 2hatj + 3hatk) - 4 = 0, vecr.(2hati + htj - hatk) + 5 = 0`,  and which is perpendicular to the plane `vecr.(5hati + 3hatj - 6hatk) + 8 = 0`.

Q 18 | Page 499

Find the distance of the point (−1, −5, −­10) from the point of intersection of the line `vecr = 2hati -hatj + 2hatk + lambda(3hati + 4hatj + 2hatk)` and the plane `vecr.(hati -hatj + hatk) = 5`.

Q 19 | Page 499

Find the vector equation of the line passing through (1, 2, 3) and parallel to the planes `vecr = (hati - hatj + 2hatk)  = 5`and `vecr.(3hati + hatj + hatk) = 6`

Q 20 | Page 499

Find the vector equation of the line passing through the point (1, 2, − 4) and perpendicular to the two lines:  `(x -8)/3 = (y+19)/(-16) = (z - 10)/7 and (x - 15)/3 = (y - 29)/8 = (z- 5)/(-5)`

Q 21 | Page 499

Prove that if a plane has the intercepts abc and is at a distance of P units from the origin, then `1/a^2 + 1/b^2 + 1/c^2 = 1/p^2`

Q 22 | Page 499

Distance between the two planes: 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is

(A) 2 units

(B) 4 units

(C) 8 units

(D)`2/sqrt29 "units"`

Q 23 | Page 499

The planes: 2− y + 4z = 5 and 5x − 2.5y + 10z = 6 are

(A) Perpendicular

(B) Parallel

(C) intersect y-axis

(C) passes through `(0,0,5/4)`

Chapter 11: Three Dimensional Geometry

NCERT Mathematics Class 12

Mathematics Textbook for Class 12

NCERT solutions for Class 12 Mathematics chapter 11 - Three Dimensional Geometry

NCERT solutions for Class 12 Maths chapter 11 (Three Dimensional Geometry) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the CBSE Mathematics Textbook for Class 12 solutions in a manner that help students grasp basic concepts better and faster.

Further, we at Shaalaa.com are providing such solutions so that students can prepare for written exams. NCERT textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.

Concepts covered in Class 12 Mathematics chapter 11 Three Dimensional Geometry are Direction Cosines and Direction Ratios of a Line, Equation of a Line in Space, Shortest Distance Between Two Lines, Plane Passing Through the Intersection of Two Given Planes, Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point, Equation of a Plane in Normal Form, Three - Dimensional Geometry Examples and Solutions, Introduction of Three Dimensional Geometry, Equation of a Plane Passing Through Three Non Collinear Points, Relation Between Direction Ratio and Direction Cosines, Intercept Form of the Equation of a Plane, Coplanarity of Two Lines, Distance of a Point from a Plane, Angle Between Line and a Plane, Angle Between Two Planes, Angle Between Two Lines, Vector and Cartesian Equation of a Plane.

Using NCERT Class 12 solutions Three Dimensional Geometry exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in NCERT Solutions are important questions that can be asked in the final exam. Maximum students of CBSE Class 12 prefer NCERT Textbook Solutions to score more in exam.

Get the free view of chapter 11 Three Dimensional Geometry Class 12 extra questions for Maths and can use Shaalaa.com to keep it handy for your exam preparation

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