Chapters
Chapter 2 - Polynomials
Chapter 3 - Pair of Linear Equations in Two Variables
Chapter 4 - Quadratic Equations
Chapter 5 - Arithmetic Progressions
Chapter 6 - Triangles
Chapter 7 - Coordinate Geometry
Chapter 8 - Introduction to Trigonometry
Chapter 9 - Some Applications of Trigonometry
Chapter 10 - Circles
Chapter 11 - Constructions
Chapter 12 - Areas Related to Circles
Chapter 13 - Surface Areas and Volumes
Chapter 14 - Statistics
Chapter 15 - Probability
Chapter 14 - Statistics
Pages 270 - 272
A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 houses in a locality. Find the mean number of plants per house.
Number of plants | 0 - 2 | 2 - 4 | 4 - 6 | 6 - 8 | 8 - 10 | 10 - 12 | 12 - 14 |
Number of houses | 1 | 2 | 1 | 5 | 6 | 2 | 3 |
Which method did you use for finding the mean, and why?
Consider the following distribution of daily wages of 50 worker of a factory.
Daily wages (in Rs) |
100 − 120 |
120 − 140 |
140 −1 60 |
160 − 180 |
180 − 200 |
Number of workers |
12 |
14 |
8 |
6 |
10 |
Find the mean daily wages of the workers of the factory by using an appropriate method.
The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f.
Daily pocket allowance (in Rs | 11 − 13 | 13 − 15 | 15 −17 | 17 − 19 | 19 − 21 | 21 − 23 | 23 − 25 |
Number of workers | 7 | 6 | 9 | 13 | f | 5 | 4 |
Thirty women were examined in a hospital by a doctor and the number of heart beats per minute were recorded and summarized as follows. Fine the mean heart beats per minute for these women, choosing a suitable method.
Number of heart beats per minute | 65 − 68 | 68 − 71 | 71 −74 | 74 − 77 | 77 − 80 | 80 − 83 | 83 − 86 |
Number of women | 2 | 4 | 3 | 8 | 7 | 4 | 2 |
In a retail market, fruit vendors were selling mangoes kept in packing boxes. These boxes contained varying number of mangoes. The following was the distribution of mangoes according to the number of boxes.
Number of mangoe | 50 − 52 | 53 − 55 | 56 − 58 | 59 − 61 | 62 − 64 |
Number of boxes | 15 | 110 | 135 | 115 | 25 |
Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?
The table below shows the daily expenditure on food of 25 households in a locality.
Daily expenditure (in Rs) | 100 − 150 | 150 − 200 | 200 − 250 | 250 − 300 | 300 − 350 |
Number of households | 4 | 5 | 12 | 2 | 2 |
Find the mean daily expenditure on food by a suitable method.
To find out the concentration of SO_{2} in the air (in parts per million, i.e., ppm), the data was collected for 30 localities in a certain city and is presented below:
concentration of SO_{2} (in ppm) | Frequency |
0.00 − 0.04 | 4 |
0.04 − 0.08 | 9 |
0.08 − 0.12 | 9 |
0.12 − 0.16 | 2 |
0.16 − 0.20 | 4 |
0.20 − 0.24 | 2 |
Find the mean concentration of SO_{2} in the air.
A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.
Number of days | 0 − 6 | 6 − 10 | 10 − 14 | 14 − 20 | 20 − 28 | 28 − 38 | 38 − 40 |
Number of students | 11 | 10 | 7 | 4 | 4 | 3 | 1 |
The following table gives the literacy rate (in percentage) of 35 cities. Find the mean literacy rate
Literacy rate (in %) | 45 − 55 | 55 − 65 | 65 − 75 | 75 − 85 | 85 − 95 |
Number of cities | 3 | 10 | 11 | 8 | 3 |
Pages 275 - 276
The following table shows the ages of the patients admitted in a hospital during a year:
age (in years) |
5 − 15 |
15 − 25 |
25 − 35 |
35 − 45 |
45 − 55 |
55 − 65 |
Number of patients |
6 |
11 |
21 |
23 |
14 |
5 |
Find the mode and the mean of the data given above. Compare and interpret the two measures of central tendency.
The following data gives the information on the observed lifetimes (in hours) of 225 electrical components:
Lifetimes (in hours) | 0 − 20 | 20 − 40 | 40 − 60 | 60 − 80 | 80 − 100 | 100 − 120 |
Frequency | 10 | 35 | 52 | 61 | 38 | 29 |
Determine the modal lifetimes of the components.
The following data gives the distribution of total monthly household expenditure of 200 families of a village. Find the modal monthly expenditure of the families. Also, find the mean monthly expenditure.
Expenditure (in Rs) | Number of families |
1000 − 1500 | 24 |
1500 − 2000 | 40 |
2000 − 2500 | 33 |
2500 − 3000 | 28 |
3000 − 3500 | 30 |
3500 − 4000 | 22 |
4000 − 4500 | 16 |
4500 − 5000 | 7 |
The following distribution gives the state-wise teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures.
Number of students per teacher | Number of states/U.T |
15 − 20 | 3 |
20 − 25 | 8 |
25 − 30 | 9 |
30 − 35 | 10 |
35 − 40 | 3 |
40 − 45 | 0 |
45 − 50 | 0 |
50 − 55 | 2 |
The given distribution shows the number of runs scored by some top batsmen of the world in one-day international cricket matches
Runs scored | Number of batsmen |
3000 − 4000 | 4 |
4000 − 5000 | 18 |
5000 − 6000 | 9 |
6000 − 7000 | 7 |
7000 − 8000 | 6 |
8000 − 9000 | 3 |
9000 − 10000 | 1 |
10000 − 11000 | 1 |
Find the mode of the data.
A student noted the number of cars passing through a spot on a road for 100 periods each of 3 minutes and summarised it in the table given below. Find the mode of the data:
Number of cars | 0 − 10 | 10 − 20 | 20 − 30 | 30 − 40 | 40 − 50 | 50 − 60 | 60 − 70 | 70 − 80 |
Frequency | 7 | 14 | 13 | 12 | 20 | 11 | 15 | 8 |
Pages 287 - 289
The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.
Monthly consumption (in units) | Number of consumers |
65 - 85 | 4 |
85 - 105 | 5 |
105 - 125 | 13 |
125 - 145 | 20 |
145 - 165 | 14 |
165 - 185 | 8 |
185 - 205 | 4 |
If the median of the distribution is given below is 28.5, find the values of x and y
Class interval | Frequency |
0 - 10 | 5 |
10 - 20 | x |
20 - 30 | 20 |
30 - 40 | 15 |
40 - 50 | y |
50 - 60 | 5 |
Total | 60 |
A life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are given only to persons having age 18 years onwards but less than 60 year.
Age (in years) | Number of policy holders |
Below 20 | 2 |
Below 25 | 6 |
Below 30 | 24 |
Below 35 | 45 |
Below 40 | 78 |
Below 45 | 89 |
Below 50 | 92 |
Below 55 | 98 |
Below 60 | 100 |
Find the following table gives the distribution of the life time of 400 neon lamps
Life time (in hours) | Number of lamps |
1500 − 2000 | 14 |
2000 − 2500 | 56 |
2500 − 3000 | 60 |
3000 − 3500 | 86 |
3500 − 4000 | 74 |
4000 − 4500 | 62 |
4500 − 5000 | 48 |
Find the median life time of a lamp.
100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:
Number of letters | Number of surnames |
1 - 4 | 6 |
4 − 7 | 30 |
7 - 10 | 40 |
10 - 13 | 6 |
13 - 16 | 4 |
16 − 19 | 4 |
Determine the median number of letters in the surnames. Find the mean number of letters in the surnames? Also, find the modal size of the surnames.
The distribution below gives the weights of 30 students of a class. Find the median weight of the students.
Weight (in kg) | 40 − 45 | 45 − 50 | 50 − 55 | 55 − 60 | 60 − 65 | 65 − 70 | 70 − 75 |
Number of students | 2 | 3 | 8 | 6 | 6 | 3 | 2 |
Page 293
The following distribution gives the daily income of 50 workers of a factory.
Daily income (in Rs | 100 − 120 | 120 − 140 | 140 − 160 | 160 − 180 | 180 − 200 |
Number of workers | 12 | 14 | 8 | 6 | 10 |
Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.
During the medical check-up of 35 students of a class, their weights were recorded as follows:
Weight (in kg | Number of students |
Less than 38 | 0 |
Less than 40 | 3 |
Less than 42 | 5 |
Less than 44 | 9 |
Less than 46 | 14 |
Less than 48 | 28 |
Less than 50 | 32 |
Less than 52 | 35 |
Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.
The following table gives production yield per hectare of wheat of 100 farms of a village.
Production yield (in kg/ha) | 50 − 55 | 55 − 60 | 60 − 65 | 65 − 70 | 70 − 75 | 75 − 80 |
Number of farms | 2 | 8 | 12 | 24 | 38 | 16 |
Change the distribution to a more than type distribution and draw ogive.
Textbook solutions for Class 10
NCERT solutions for Class 10 Mathematics chapter 14 - Statistics
NCERT solutions for Class 10 Mathematics chapter 14 (Statistics) include all questions with solution and detail explanation from Mathematics Textbook for Class 10. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has created the CBSE Mathematics Textbook for Class 10 solutions in a manner that help students grasp basic concepts better and faster.
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Concepts covered in Class 10 Mathematics chapter 14 Statistics are Graphical Representation of Cumulative Frequency Distribution, Mode of Grouped Data, Ogives (Cumulative Frequency Graphs), Mean of Grouped Data, Median of Grouped Data, Introduction of Statistics, Statistics Examples and Solutions.
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