Chapter 2: Fractions and Decimals
Chapter 3: Data Handling
Chapter 4: Simple Equations
Chapter 5: Lines and Angles
Chapter 6: The Triangle and its Properties
Chapter 7: Congruence of Triangles
Chapter 8: Comparing Quantities
Chapter 9: Rational Numbers
Chapter 10: Practical Geometry
Chapter 11: Perimeter and Area
Chapter 12: Algebraic Expressions
Chapter 13: Exponents and Powers
Chapter 14: Symmetry
Chapter 15: Visualising Solid Shapes
NCERT Mathematics Class 7
Chapter 10 : Practical Geometry
Draw a line, say AB, take a point C outside it. Through C, draw a line parallel to AB using ruler and compasses only
Draw a line l. Draw a perpendicular to l at any point on l. On this perpendicular choose a point X, 4 cm away from l. Through X, draw a line m parallel to l.
Let l be a line and P be a point not on l. Through P, draw a line m parallel to l. Now join P to any point Q on l. Choose any other point R on m. Through R, draw a line parallel to PQ. Let this meet l at S. What shape do the two sets of parallel lines enclose?
Construct ΔXYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.
Construct an equilateral triangle of side 5.5 cm.
Draw ΔPQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?
Construct ΔABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.
Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.
Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 110°.
Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°.
Construct ΔABC, given m∠A = 60°, m∠B = 30° and AB = 5.8 cm.
Construct ΔPQR if PQ = 5 cm, m∠PQR = 105° and m∠QRP = 40°. (Hint: Recall angle sum property of a triangle).
Examine whether you can construct ΔDEF such that EF = 7.2 cm, m∠E = 110° and m∠F = 80°. Justify your answer.
Construct the right angled ΔPQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm.
Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long
Construct an isosceles right-angled triangle ABC, where, m∠ACB = 90° and AC = 6 cm.
NCERT Mathematics Class 7
Textbook solutions for Class 7
NCERT solutions for Class 7 Mathematics chapter 10 - Practical Geometry
NCERT solutions for Class 7 Maths chapter 10 (Practical Geometry) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the CBSE Mathematics for Class 7 solutions in a manner that help students grasp basic concepts better and faster.
Further, we at shaalaa.com are providing such solutions so that students can prepare for written exams. NCERT textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.
Concepts covered in Class 7 Mathematics chapter 10 Practical Geometry are Constructing a Triangle When the Lengths of Two Sides and the Measure of the Angle Between Them Are Known. (Sas Criterion), Constructing a Right-angled Triangle When the Length of One Leg and Its Hypotenuse Are Given (RHS Criterion), Constructing a Triangle When the Measures of Two of Its Angles and the Length of the Side Included Between Them is Given. (ASA Criterion), Constructing a Triangle When the Lengh of Its Sides Are Known (SSS Criterion), Construction of Triangles, Construction of a Line Parallel to a Given Line, Through a Point Not on the Line.
Using NCERT Class 7 solutions Practical Geometry exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in NCERT Solutions are important questions that can be asked in the final exam. Maximum students of CBSE Class 7 prefer NCERT Textbook Solutions to score more in exam.
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