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NCERT solutions for Class 7 Mathematics chapter 10 - Practical Geometry

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NCERT Mathematics Class 7

Mathematics for Class 7

Chapter 10 : Practical Geometry

Page 196

Q 1 | Page 196

Draw a line, say AB, take a point C outside it. Through C, draw a line parallel to AB using ruler and compasses only

Q 2 | Page 196

Draw a line l. Draw a perpendicular to l at any point on l. On this perpendicular choose a point X, 4 cm away from l. Through X, draw a line m parallel to l.

Q 3 | Page 196

Let l be a line and P be a point not on l. Through P, draw a line m parallel to l. Now join P to any point Q on l. Choose any other point R on m. Through R, draw a line parallel to PQ. Let this meet l at S. What shape do the two sets of parallel lines enclose?

Page 199

Q 1 | Page 199

Construct ΔXYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

Q 2 | Page 199

Construct an equilateral triangle of side 5.5 cm.

Q 3 | Page 199

Draw ΔPQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?

Q 4 | Page 199

Construct ΔABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.

Page 200

Q 1 | Page 200

Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.

Q 2 | Page 200

Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 110°.

Q 3 | Page 200

Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°.

Page 202

Q 1 | Page 202

Construct ΔABC, given m∠A = 60°, m∠B = 30° and AB = 5.8 cm.

Q 2 | Page 202

Construct ΔPQR if PQ = 5 cm, m∠PQR = 105° and m∠QRP = 40°. (Hint: Recall angle sum property of a triangle).

Q 3 | Page 202

Examine whether you can construct ΔDEF such that EF = 7.2 cm, m∠E = 110° and m∠F = 80°. Justify your answer.

Page 203

Q 1 | Page 203

Construct the right angled ΔPQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm.

Q 2 | Page 203

Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long

Q 3 | Page 203

Construct an isosceles right-angled triangle ABC, where, m∠ACB = 90° and AC = 6 cm.

NCERT Mathematics Class 7

Mathematics for Class 7

NCERT solutions for Class 7 Mathematics chapter 10 - Practical Geometry

NCERT solutions for Class 7 Maths chapter 10 (Practical Geometry) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. has the CBSE Mathematics for Class 7 solutions in a manner that help students grasp basic concepts better and faster.

Further, we at are providing such solutions so that students can prepare for written exams. NCERT textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.

Concepts covered in Class 7 Mathematics chapter 10 Practical Geometry are Constructing a Triangle When the Lengths of Two Sides and the Measure of the Angle Between Them Are Known. (Sas Criterion), Constructing a Right-angled Triangle When the Length of One Leg and Its Hypotenuse Are Given (RHS Criterion), Constructing a Triangle When the Measures of Two of Its Angles and the Length of the Side Included Between Them is Given. (ASA Criterion), Constructing a Triangle When the Lengh of Its Sides Are Known (SSS Criterion), Construction of Triangles, Construction of a Line Parallel to a Given Line, Through a Point Not on the Line.

Using NCERT Class 7 solutions Practical Geometry exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in NCERT Solutions are important questions that can be asked in the final exam. Maximum students of CBSE Class 7 prefer NCERT Textbook Solutions to score more in exam.

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