#### Chapters

Chapter 2: Sales Tax and Value Added Tax

Chapter 3: Banking

Chapter 4: Shares and Dividends

Chapter 5: Linear Inequations

Chapter 6: Quadratic Equations

Chapter 7: Problems Based On Quadratic Equations

Chapter 8: Reflection

Chapter 9: Ratio and Proportion

Chapter 10: Remainder And Factor Theorems

Chapter 11: Matrices

Chapter 12: Distance and Section Formulae

Chapter 13: Equation of A Straight Line

Chapter 14: Symmetry

Chapter 15: Similarity

Chapter 16: Loci

Chapter 17: Circles

Chapter 18: Constructions

Chapter 19: Mensuration I

Chapter 20: Mensuration II

Chapter 21: Trigonometric Identities

Chapter 22: Heights and Distances

Chapter 23: Graphical Representations

Chapter 24: Measures Of Central Tendency

Chapter 25: Probability

#### Frank Frank Class 10 Mathematics Part 2

## Chapter 19: Mensuration I

#### Frank solutions for Class 10 Maths Chapter 19 Exercise Exercise 19.1 [Page 0]

Find the area and perimeter of the circle with the following :

Radius= 2.8 cm

Find the area and perimeter of the circle with the following :

Radius= 10.5 cm

Find the area and perimeter of the circle with the following :

Diameter = 77 cm

Find the area and perimeter of the circle with the following:

Diameter= 35 cm

A bucket is raised from a well by means of a rope wound round a wheel of diameter 35 cm. If the bucket ascends in 2 minutes with a uniform speed of 1.1 m per sec, calculate the number of complete revolutions the wheel makes in raising the bucket.

The circumference of a garden roller is 280 cm. How many revolutions does it make in moving 490 meters?

The diameter of a cycle wheel is `4 5/11` cm. How many revolution will it make in moving 6.3 km ?

The area of a circular ring enclosed between two concentric circles is 88 cm 2. Find the radii of the two circles, if their difference is 1 cm.

Find the area enclosed between two concentric circles, if their radii are 6 cm and 13 cm respectively.

The area between the circumferences of two concentric circles is 2464 cm^{2}. If the inner circle has circumference of 132 cm, calculate the radius of outer circle.

A wire when bent in the form of a square encloses an area of 484 cm^{2}. If the same wire is bent into the form of a circle, find the area of the circle.

A wire bent in the form of an equilateral triangle has an area of 121 `sqrt 3` cm^{2}. If the same wire is bent into the form of a circle , find the area enclosed by the wire.

Find the circumference of the circle whose area is 25 times the area of the circle with radius 7 cm.

The circumference of a circle is equal to the perimeter of a square. The area of the square is 484 sq. m. Find the area of the circle.

Find the area and perimeter of the following semi-circle :

Radius= 1.4 cm

Find the area and perimeter of the following semi-circle :

Diameter= 7 cm

Find the area and perimeter of the following semi-circle :

Diameter= 5.6 cm

A wire is in the form of a circle of radius 42 cm. It is bent into a square.

Determine the side of the square and compare the area of the regions enclosed in two cases.

A 7 m road surrounds a circular garden whose area is 5544 m^{2}. Find the area of the road and the cost of tarring it at the rate of Rs.150 per sq m.

A 4.2 m wide road surrounds a circular plot whose circumference is 176 m. Find the cost of paving the road at Rs 75 m ^{2}.

Two circles touch each other externally. The sum of their areas is 5811 cm^{2} and the distance between their centres is 10 cm. Find the radii of the two circles.

The sum of diameter of two circles is 112 cm and the sum of their areas is 5236 cm^{2} Find the radii of the two circles.

The sum of the radii of two circles is 10.5 cm and the difference of their circumferences is 13. 2 cm. Find the radii of the two circles.

A lawn is in the shape of a semi-circle of diameter 42 m. The lawn is surrounded by a flower bed of width 7 m all around. Find the area of the flower bed in m^{2} .

Find the area enclosed between two concentric cirdes of radii 6.3 cm and 8.4 cm. A third concentric circle is drawn outside the 8.4 cm circle, so that the area enclosed between it and 8.4 cm cirde is the same as that between two inner circles. Find the radii of the third circle correct to two decimal places .

Find the area of the biggest circle that can be cut from a rectangular piece of 44cm by 28 cm. Also, find the area of the paper left after cutting out the circle.

Find the area grazed by a horse tied with a 11. 2 m rope to a corner of a field measuring 25m by 15 m.

Find the area and perimeter of the following sector :

Radius= 4.2 cm, angle at the centre is 60 °

Find the area and perimeter of the following sector :

Radius= 6 cm, angle at the centre is 70°

Find the area and perimeter of the following sector :

Diameter = 42 cm, angle at the centre is 100·.

A horse is tied with a 21 m laig rope to the corner of a field which is in the shape of an equilateral triangle. Find the area of the field over which it can graze.

Find the area of a circular field that has a circumference of 396 m.

Find the circumference of the circle whose area is 81π cm ^{2}.

The diameter of a wheel is 1.4m. How many revolutions does it make in moving a distance of 2.2 kms?

The wheel of the car makes 10 revolutions per second. If its diameter is 70 cm, find the speed of the car in km per hour.

The speed of the car is 66 km/hour. If each wheel of the car is 140 cm in diameter, find the number of revolutions made by each wheel per minute.

A cart wheel makes 9 revolutions per second. If the diameter of the wheel is 42 cm, find its speed in km/hr.

## Chapter 19: Mensuration I

#### Frank Frank Class 10 Mathematics Part 2

## Frank solutions for Class 10 Mathematics chapter 19 - Mensuration I

Frank solutions for Class 10 Maths chapter 19 (Mensuration I) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the CISCE Frank Class 10 Mathematics Part 2 solutions in a manner that help students grasp basic concepts better and faster.

Further, we at Shaalaa.com provide such solutions so that students can prepare for written exams. Frank textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.

Concepts covered in Class 10 Mathematics chapter 19 Mensuration I are Perimeter and Area of a Circle, Area and Volume of Solids - Cone, Area and Volume of Solids - Sphere, Circle - Direct Application Problems Including Inner and Outer Area, Three-dimensional Solids Right Circular Cone, Three-dimensional Solids Sphere, Volume of a Cylinder, Volume of a Combination of Solids.

Using Frank Class 10 solutions Mensuration I exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in Frank Solutions are important questions that can be asked in the final exam. Maximum students of CISCE Class 10 prefer Frank Textbook Solutions to score more in exam.

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