Chapters
Chapter 2: Profit , Loss and Discount
Chapter 3: Compound Interest
Chapter 4: Expansions
Chapter 5: Factorisation
Chapter 6: Changing the subject of a formula
Chapter 7: Linear Equations
Chapter 8: Simultaneous Linear Equations
Chapter 9: Indices
Chapter 10: Logarithms
Chapter 11: Triangles and their congruency
Chapter 12: Isosceles Triangle
Chapter 13: Inequalities in Triangles
Chapter 14: Constructions of Triangles
Chapter 15: Mid-point and Intercept Theorems
Chapter 16: Similarity
Chapter 17: Pythagoras Theorem
Chapter 18: Rectilinear Figures
Chapter 19: Quadrilaterals
Chapter 20: Constructions of Quadrilaterals
Chapter 21: Areas Theorems on Parallelograms
Chapter 22: Statistics
Chapter 23: Graphical Representation of Statistical Data
Chapter 24: Perimeter and Area
Chapter 25: Surface Areas and Volume of Solids
Chapter 26: Trigonometrical Ratios
Chapter 27: Trigonometrical Ratios of Standard Angles
Chapter 28: Coordinate Geometry
Chapter 26: Trigonometrical Ratios
Frank solutions for Class 9 Maths ICSE Chapter 26 Trigonometrical Ratios Exercise 26.1
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
sinA = `(12)/(13)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cosB = `(4)/(5)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cotA = `(1)/(11)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cose C = `(15)/(11)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
tan C = `(5)/(12)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
sinB = `sqrt(3)/(2)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cos A = `(7)/(25)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
tanB = `(8)/(15)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
sec B = `(15)/(12)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cosec C = `sqrt(10)`
In ΔABC, ∠A = 90°. If AB = 5 units and AC = 12 units, find: sinB
In ΔABC, ∠A = 90°. If AB = 5 units and AC = 12 units, find: cos C
In ΔABC, ∠A = 90°. If AB = 5 units and AC = 12 units, find: tan B.
In ΔABC, ∠B = 90°. If AB = 12units and BC = 5units, find: sinA
In ΔABC, ∠B = 90°. If AB = 12units and BC = 5units, find: tan A
In ΔABC, ∠B = 90°. If AB = 12units and BC = 5units, find: cos C
In ΔABC, ∠B = 90°. If AB = 12units and BC = 5units, find: cot C
If sinA = `(3)/(5)`, find cosA and tanA.
If cosB = `(1)/(3)` and ∠C = 90°, find sin A, and B and cot A.
If sin θ = `(8)/(17)`, find the other five trigonometric ratios.
If tan = 0.75, find the other trigonometric ratios for A.
If sinA = 0.8, find the other trigonometric ratios for A.
If 8 tanθ = 15, find (i) sinθ, (ii) cotθ, (iii) sin2θ - cot2θ
In the given figure, PQR is a triangle, in which QS ⊥ PR, QS = 3 cm, PS = 4 cm and QR = 12 cm, find the value of: sin P
In the given figure, PQR is a triangle, in which QS ⊥ PR, QS = 3 cm, PS = 4 cm and QR = 12 cm, find the value of: cot2P - cosec2P
In the given figure, PQR is a triangle, in which QS ⊥ PR, QS = 3 cm, PS = 4 cm and QR = 12 cm, find the value of: 4sin2R - `(1)/("tan"^2"P")`
In an isosceles triangle ABC, AB = BC = 6 cm and ∠B = 90°. Find the values of cos C
In an isosceles triangle ABC, AB = BC = 6 cm and ∠B = 90°. Find the values of cosec C
In an isosceles triangle ABC, AB = BC = 6 cm and ∠B = 90°. Find the values of cos2 C + cosec2 C
In the given figure, AD is the median on BC from A. If AD = 8 cm and BC = 12 cm, find the value of sin x
In the given figure, AD is the median on BC from A. If AD = 8 cm and BC = 12 cm, find the value of cos y
In the given figure, AD is the median on BC from A. If AD = 8 cm and BC = 12 cm, find the value of tan x. cot y
In the given figure, AD is the median on BC from A. If AD = 8 cm and BC = 12 cm, find the value of `(1)/("sin"^2 x) - (1)/("tan"^2 x)`
In a right-angled triangle PQR, ∠PQR = 90°, QS ⊥ PR and tan R =`(5)/(12)`, find the value of sin ∠PQS
In a right-angled triangle PQR, ∠PQR = 90°, QS ⊥ PR and tan R =`(5)/(12)`, find the value of tan ∠SQR
In the given figure, ΔABC is right angled at B.AD divides BC in the ratio 1 : 2. Find
(i) `("tan"∠"BAC")/("tan"∠"BAD")` (ii) `("cot"∠"BAC")/("cot"∠"BAD")`
If sin A = `(7)/(25)`, find the value of : `(2"tanA")/"cot A - sin A"`
If sin A = `(7)/(25)`, find the value of : `"cos A" + (1)/"cot A"`
If sin A = `(7)/(25)`, find the value of : cot2A - cosec2A
If cosec θ = `(29)/(20)`, find the value of: cosec θ - `(1)/("cot" θ)`
If cosec θ = `(29)/(20)`, find the value of: `("sec" θ)/("tan" θ - "cosec" θ)`
In the given figure, AC = 13cm, BC = 12 cm and ∠B = 90°. Without using tables, find the values of: sin A cos A
In the given figure, AC = 13cm, BC = 12 cm and ∠B = 90°. Without using tables, find the values of: `("cos A" - "sin A")/("cos A" + "sin A")`
In tan θ = 1, find the value of 5cot2θ + sin2θ - 1.
In the given figure, ∠Q = 90°, PS is a median om QR from P, and RT divides PQ in the ratio 1 : 2. Find: `("tan" ∠"PSQ")/("tan"∠"PRQ")`
In the given figure, ∠Q = 90°, PS is a median om QR from P, and RT divides PQ in the ratio 1 : 2. Find: `("tan" ∠"TSQ")/("tan"∠"PRQ")`
In the given figure, AD is perpendicular to BC. Find: 5 cos x
In the given figure, AD is perpendicular to BC. Find: 15 tan y
In the given figure, AD is perpendicular to BC. Find: 5 cos x - 12 sin y + tan x
In the given figure, AD is perpendicular to BC. Find:
`(3)/("sin" x) + (4)/("cos" y) - 4 "tan" y`
In a right-angled triangle ABC, ∠B = 90°, BD = 3, DC = 4, and AC = 13. A point D is inside the triangle such as ∠BDC = 90°.
Find the values of 2 tan ∠BAC - sin ∠BCD
In a right-angled triangle ABC, ∠B = 90°, BD = 3, DC = 4, and AC = 13. A point D is inside the triangle such as ∠BDC = 90°.
Find the values of 3 - 2 cos ∠BAC + 3 cot ∠BCD
If 24cosθ = 7 sinθ, find sinθ + cosθ.
If 4 sinθ = 3 cosθ, find tan2θ + cot2θ
If 4 sinθ = 3 cosθ, find `(6sinθ - 2cosθ )/(6sinθ + 2cosθ )`
If 8tanA = 15, find sinA - cosA.
If 3cosθ - 4sinθ = 2cosθ + sinθ, find tanθ.
If 5cosθ = 3, find the value of `(4cosθ - sinθ)/(2cosθ + sinθ)`
If 4sinθ = `sqrt(13)`, find the value of `(4sinθ - 3cosθ)/(2sinθ + 6cosθ)`
If 4sinθ = `sqrt(13)`, find the value of 4sin3θ - 3sinθ
If 5tanθ = 12, find the value of `(2sinθ - 3cosθ)/(4sinθ - 9cosθ)`.
If 35 sec θ = 37, find the value of sin θ - sin θ tan θ.
If cotθ = `(1)/sqrt(3)`, show that `(1 - cos^2θ)/(2 - sin^2θ) = (3)/(5)`
If cosecθ = `1(9)/(20)`, show that `(1 - sinθ + cosθ)/(1 + sinθ + cosθ) = (3)/(7)`
If b tanθ = a, find the values of `(cosθ + sinθ)/(cosθ - sinθ)`.
If a cotθ = b, prove that `("a"sinθ - "b"cosθ)/("a"sinθ + "b"cosθ) = ("a"^2 - "b"^2)/("a"^2 + "b"^2)`
If cotθ = `sqrt(7)`, show that `("cosec"^2θ -sec^2θ)/("cosec"^2θ + sec^2θ) = (3)/(4)`
If 12cosecθ = 13, find the value of `(sin^2θ - cos^2θ) /(2sinθ cosθ) xx (1)/tan^2θ`.
If 12 cotθ = 13, find the value of `(2sinθ cosθ)/(cos^2θ - sin^2θ)`.
If secA = `(5)/(4)`, cerify that `(3sin"A" - 4sin^3"A")/(4cos^3"A" - 3cos"A") = (3tan"A" - tan^3"A")/(1 - 3tan^2"A")`.
If sinθ = `(3)/(4)`, prove that `sqrt(("cosec"^2θ - cot^2θ)/(sec^2θ - 1)) = sqrt(7)/(3)`.
If secA = `(17)/(8)`, verify that `(3 - 4sin^2 "A")/(4 cos^2 "A" - 3)= (3 - tan^2"A")/(1 - 3tan^2"A")`
If 3 tanθ = 4, prove that `sqrt(secθ - "cosec"θ)/(sqrt(secθ - "cosec"θ)) = (1)/sqrt(7)`.
If tan θ = `"m"/"n"`, show that `"m sin θ - n cos θ"/"m sinθ + n cos θ" = ("m"^2 - "n"^2)/("m"^2 + "n"^2)`
Chapter 26: Trigonometrical Ratios
Frank solutions for Class 9 Maths ICSE chapter 26 - Trigonometrical Ratios
Frank solutions for Class 9 Maths ICSE chapter 26 (Trigonometrical Ratios) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the CISCE Class 9 Maths ICSE solutions in a manner that help students grasp basic concepts better and faster.
Further, we at Shaalaa.com provide such solutions so that students can prepare for written exams. Frank textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.
Concepts covered in Class 9 Maths ICSE chapter 26 Trigonometrical Ratios are Concept of Perpendicular, Base, and Hypotenuse in a Right Triangle, Notation of Angles, Trigonometric Ratios and Its Reciprocal, Reciprocal Relations.
Using Frank Class 9 solutions Trigonometrical Ratios exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in Frank Solutions are important questions that can be asked in the final exam. Maximum students of CISCE Class 9 prefer Frank Textbook Solutions to score more in exam.
Get the free view of chapter 26 Trigonometrical Ratios Class 9 extra questions for Class 9 Maths ICSE and can use Shaalaa.com to keep it handy for your exam preparation
