SSC (English Medium) Class 9Maharashtra State Board
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Balbharati solutions for Class 9 chapter 9 - Surface Area and Volume

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Balbharati Balbharati Class 9 Mathematics 2 Geometry

Balbharati Class 9 Mathematics 2 Geometry - Shaalaa.com

Chapter 9: Surface Area and Volume

Practice Set 9.1Practice Set 9.2Practice Set 9.3Problem Set 9

Balbharati solutions for Class 9 Chapter 9 Exercise Practice Set 9.1 [Page 115]

Practice Set 9.1 | Q 1 | Page 115

Length, breadth and height of a cuboid shape box of medicine is 20 cm, 12 cm and 10 cm respectively. Find the surface area of vertical faces and total surface area of this box.

Practice Set 9.1 | Q 2 | Page 115

Total surface area of a box of cuboid shape is 500 sq. unit. Its breadth and height is 6 unit and 5 unit respectively. What is the length of that box ?

Practice Set 9.1 | Q 3 | Page 115

Side of a cube is 4.5 cm. Find the surface area of all vertical faces and total surface area of the cube.

Practice Set 9.1 | Q 4 | Page 115

Total surface area of a cube is 5400 sq. cm. Find the surface area of all vertical faces of the cube.

Practice Set 9.1 | Q 5 | Page 115

Volume of a cuboid is 34.50 cubic metre. Breadth and height of the cuboid is 1.5m and 1.15m respectively. Find its length.

Practice Set 9.1 | Q 6 | Page 115

What will be the volume of a cube having length of edge 7.5 cm ?

Practice Set 9.1 | Q 7 | Page 115

Radius of base of a cylinder is 20 cm and its height is 13 cm, find its curved surface area and total surface area. (π = 3.14)

Practice Set 9.1 | Q 8 | Page 115

Curved surface area of a cylinder is 1980 cmand radius of its base is 15 cm. Find the height of the cylinder. (π = `22/7`)

Balbharati solutions for Class 9 Chapter 9 Exercise Practice Set 9.2 [Page 119]

Practice Set 9.2 | Q 1 | Page 119

Perpendicular height of a cone is 12 cm and its slant height is 13 cm. Find the radius of the base of the cone.

Practice Set 9.2 | Q 2 | Page 119

Find the volume of a cone, if its total surface area is 7128 sq.cm and radius of base is 28 cm.(π = `22/7`)

Practice Set 9.2 | Q 3 | Page 119

Curved surface area of a cone is 251.2 cm2 and radius of its base is 8 cm. Find its slant height and perpendicular height. (π = 3.14 )

Practice Set 9.2 | Q 4 | Page 119

What will be the cost of making a closed cone of tin sheet having radius of base 6 m and slant height 8 m if the rate of making is
Rs.10 per sq.m ?

Practice Set 9.2 | Q 5 | Page 119

Volume of a cone is 6280 cubic cm and base radius of the cone is 30 cm. Find its perpendicular height. (π = 3.14)

Practice Set 9.2 | Q 6 | Page 119

Surface area of a cone is 188.4 sq.cm and its slant height is 10 cm. Find its perpendicular height ( π= 3.14)

Practice Set 9.2 | Q 7 | Page 119

Volume of a cone is 1212 cm3 and its height is 24 cm. Find the surface area of the cone. ( π = `22/7`)

Practice Set 9.2 | Q 8 | Page 119

The curved surface area of a cone is 2200 sq.cm and its slant height is 50 cm. Find the total surface area of cone. (π = `22/7`)

Practice Set 9.2 | Q 9 | Page 119

There are 25 persons in a tent which is conical in shape. Every person needs an area of 4 sq.m. of the ground inside the tent. If height of the tent is 18 m, find the volume of the tent.

Practice Set 9.2 | Q 10 | Page 119

In a field, dry fodder for the cattle is heaped in a conical shape. The height of the cone is 2.1m. and diameter of base is 7.2 m. Find the volume of the fodder. if it is to be covered by polythin in rainy season then how much minimum polythin sheet is needed ?
( π = `22/7` ) and `sqrt 17.37 = 4.17`

Balbharati solutions for Class 9 Chapter 9 Exercise Practice Set 9.3 [Page 123]

Practice Set 9.3 | Q 1.1 | Page 123

Find the surface area and volume of sphere of the following radii.

 4 cm

Practice Set 9.3 | Q 1.2 | Page 123

Find the surface area and volume of sphere of the following radii.

 9 cm

Practice Set 9.3 | Q 1.3 | Page 123

Find the surface area and volume of sphere of the following radii.

3.5 cm

Practice Set 9.3 | Q 2 | Page 123

If the radius of a solid hemisphere is 5 cm, then find its curved surface area and total surface area. ( π = 3.14 )

Practice Set 9.3 | Q 3 | Page 123

If the surface area of a sphere is 2826 cmthen find its volume. ( π= 3.14)

Practice Set 9.3 | Q 4 | Page 123

Find the surface area of a sphere, if its volume is 38808 cubic cm. (π = `22/7`)

Practice Set 9.3 | Q 5 | Page 123

Volume of a hemisphere is 18000 π cubic cm. Find its diameter.

Balbharati solutions for Class 9 Chapter 9 Exercise Problem Set 9 [Page 123]

Problem Set 9 | Q 1 | Page 123

If diameter of a road roller is 0.9 m and its length is 1.4 m, how much area of a field will be pressed in its 500 rotations ?

Problem Set 9 | Q 2 | Page 123

To make an open fish tank, a glass sheet of 2 mm gauge is used. The outer length, breadth and height of the tank are 60.4 cm, 40.4 cm and 40.2 cm respectively. How much maximum volume of water will be contained in it ?

Problem Set 9 | Q 3 | Page 123

If the ratio of radius of base and height of a cone is 5:12 and its volume is 314 cubic metre. Find its perpendicular height and slant height (π = 3.14 )

Problem Set 9 | Q 4 | Page 123

Find the radius of a sphere if its volume is 904.32 cubic cm. ( π = 3.14)

Problem Set 9 | Q 5 | Page 123

Total surface area of a cube is 864 sq.cm. Find its volume.

Problem Set 9 | Q 6 | Page 123

Find the volume of a sphere, if its surface area is 154 sq.cm.

Problem Set 9 | Q 7 | Page 123

Total surface area of a cone is 616 sq.cm. If the slant height of the cone is three times the radius of its base, find its slant height.

Problem Set 9 | Q 8 | Page 123

The inner diameter of a well is 4.20 metre and its depth is 10 metre. Find the inner surface area of the well. Find the cost of plastering it from inside at the rate Rs.52 per sq.m.

Problem Set 9 | Q 9 | Page 123

The length of a road roller is 2.1m and its diameter is 1.4m. For levelling a ground 500 rotations of the road roller were required. How much area of ground was levelled by the road roller? Find the cost of levelling at the rate of Rs. 7 per sq. m.

Chapter 9: Surface Area and Volume

Practice Set 9.1Practice Set 9.2Practice Set 9.3Problem Set 9

Balbharati Balbharati Class 9 Mathematics 2 Geometry

Balbharati Class 9 Mathematics 2 Geometry - Shaalaa.com

Balbharati solutions for Class 9 Geometry chapter 9 - Surface Area and Volume

Balbharati solutions for Class 9 chapter 9 (Surface Area and Volume) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the Maharashtra State Board Balbharati Class 9 Mathematics 2 Geometry solutions in a manner that help students grasp basic concepts better and faster.

Further, we at Shaalaa.com provide such solutions so that students can prepare for written exams. Balbharati textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.

Concepts covered in Class 9 Geometry chapter 9 Surface Area and Volume are Surface Area and Volume of Cube, Cuboid and Cylinder, Area and Volume of Solids - Cone, Area and Volume of Solids - Sphere.

Using Balbharati Class 9 solutions Surface Area and Volume exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in Balbharati Solutions are important questions that can be asked in the final exam. Maximum students of Maharashtra State Board Class 9 prefer Balbharati Textbook Solutions to score more in exam.

Get the free view of chapter 9 Surface Area and Volume Class 9 extra questions for and can use Shaalaa.com to keep it handy for your exam preparation

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