BE Mechanical Engineering Semester 2 (FE First Year)University of Mumbai
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Applied Physics 2 CBCGS 2018-2019 BE Mechanical Engineering Semester 2 (FE First Year) Question Paper Solution

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Applied Physics 2
CBCGS
2018-2019 December
Marks: 60

[21]1 | Answer The following questions
[3]1.1

Find the divergence of the vector function A=x2 i+x2y2 j+24x2y2z3 k.

Chapter: [10] Electrodynamics
Concept: Curl and Divergence
[3]1.2

What is antireflection coating? What should be the refractive index and minimum thickness of the coating?

Chapter: [7] Interference and Diffraction of Light
Concept: Interference in Thin Film of Constant Thickness Due to Reflected and Transmitted Light
[3]1.3

A glass material A with an optical fibre is made has a refractive index of 1.55. This material is clad with another material whose refractive index is 1.51. The light in the fibre is launched from air. Calculate the numerical aperture of the fibre.

Chapter: [9] Fibre Optics
Concept: Numerical Aperture
[3]1.4

What is difference between Bottom up and Top Down Approach with respect to Nanotechnology.

Chapter: [12] Nanoscience and Nanotechnology
Concept: Two Main Approaches in Nanotechnology
[3]1.5

Write difference between LED and Laser Diode.

Chapter: [8] Lasers
Concept: Applications of Laser
[3]1.6

How is Lissajous figures used to measure unknown frequency?

Chapter: [11] Charge Particle in Electric and Magnetic Fields
Concept: Application of Cro - Frequency
[3]1.7

A parallel beam of light of wavelength 5890 A0 is incident on a glass plate having refractive index 𝝁=𝟏.πŸ“ such that the angle of refraction in the plate is 600. Calculate the smallest thickness of the glass plate which will appear dark by reflected light.

Chapter: [7] Interference and Diffraction of Light
Concept: Wedge Shaped Film(Angle of Wedge and Thickness Measurement)
[15]2 | Answer The following questions
[8]2.1

With the help of proper diagram and necessary equation, explain how Newtons ring experiment is useful to determine the radius of curvature of plano convex lens. In a newton rings experiment the diameter of 5th dark ring is 0.336 cm and the diameter of 15th ring is 0.590 cm. Find the radius of curvature of plano convex lens if the wavelength of light used is 5890 A0.

Chapter: [7] Interference and Diffraction of Light
Concept: Newton’S Rings
[7]2.2

What is monomode and multimode fibre? Explain the term V-number, Calculate the number of modes of a step index optical fibre of diameter 40 ππ’Ž will transmit as its core and cladding refractive indices are 1.5 and 1.46 respectively. Wavelength of light used is 1.5 ππ’Ž.

Chapter: [9] Fibre Optics
Concept: Number of Modes of Propagation
[15]3
[8]3.1

With a neat energy level diagram describe the construction and working of He-Ne Laser. What are the merits and demerits?

Chapter: [8] Lasers
Concept: Applications of Laser
[7]3.2

What is diffraction grating and grating element? Explain experimental method to determine the wavelength of the spectral line using diffraction grating?

Chapter: [7] Interference and Diffraction of Light
Concept: Diffraction Grating
[15]4
[5]4.1

With a neat diagram explain the construction and working of scanning electron microscope.

Chapter: [12] Nanoscience and Nanotechnology
Concept: Important Tools in Nanotechnology - Scanning Electron Microscope
[5]4.2

Derive Bethe’s Law for electron refraction.

Chapter: [11] Charge Particle in Electric and Magnetic Fields
Concept: Electron Refraction
[5]4.3

Derive the condition for absent spectra in grating.

Chapter: [7] Interference and Diffraction of Light
Concept: Diffraction Grating
[15]5
[5]5.1

Draw the block diagram of an optical fibre communication system and explain function of each block.

Chapter: [9] Fibre Optics
Concept: Applications of Optical Fibre
[5]5.2

Derive Maxwell’s Third Equation.

Chapter: [10] Electrodynamics
Concept: Determination of Maxwell’S Four Equations
[5]5.3

An electron enters a uniform magnetic field B=0.23x10-2 Wb/m2 at 450 angle to B. Determine the radius and pitch of helical path. Assume electron speed to be 3x107 m/s.

Chapter: [11] Charge Particle in Electric and Magnetic Fields
Concept: Motion of Electron in Electric Field
[15]6
[5]6.1

If 𝑨=π’™πŸπ’› π’Š−πŸπ’šπŸπ’›πŸπ’‹+π’™π’šπŸπ’›π’Œ. Find 𝛁.𝑨 at point (1,-1,1).

Chapter: [10] Electrodynamics
Concept: Curl and Divergence
[5]6.2

A newtons rings setup is used with a source emitting two wavelength λ1=6000A0 and λ2=4500 A0. It is found that nth dark ring due to 6000A0 coincides with (n+2)th dark ring due to 4500 A0. If the radius of curvature of the lens is 90 cm, find the diameter of nth dark ring of 6000A0.

Chapter: [7] Interference and Diffraction of Light
Concept: Newton’S Rings
[5]6.3

Differentiate between spontaneous and stimulated emission.

Chapter: [8] Lasers
Concept: Spontaneous Emission and Stimulated Emission

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