#### Question

If `x = −1/2` is a zero of the polynomial `p(x)=8x^3-ax^2 -+2` find the value of a.

#### Solution

we have `p(x)=8x^2-ax^2-x=2`

put `x=-1/2`

`⇒p(-1/2)=8xx(-1/2)^3-ax(-1/2)^2-(-1/2)+2`

`=8xx-^1/8-axx1/4+1/2+2`

`=-1-a/4+1/2+2`

`=3/2-a/4`

giventhat `x=^-1/2`is a root of p(x)`

`⇒p(^-1/2)=0`

`∴3/2-a/4=0⇒a/4=3/2⇒a=3/2xx4^2`

`⇒a=6`

Is there an error in this question or solution?

Solution If `X = −1/2` is a Zero of the Polynomial `P(X)=8x^3-ax^2 -+2` Find the Value of A. Concept: Zeroes of a Polynomial.