Yellow light emitted from a sodium lamp has a wavelength (λ) of 580 nm. Calculate the frequency (ν) and wave number (v¯) of the yellow light. - Chemistry

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Numerical

Yellow light emitted from a sodium lamp has a wavelength (λ) of 580 nm. Calculate the frequency (ν) and wave number (`bar v`) of the yellow light.

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Solution

From the expression,

`lambda = "c"/"v"`

We get,

`"v" = "c"/lambda`  ....(i)

Where,

ν = frequency of yellow light

c = velocity of light in vacuum = 3 × 108 m/s

λ = wavelength of yellow light = 580 nm = 580 × 10–9 m

Substituting the values in expression (i):

`"v" =(3xx10^8)/(580xx10^(-9)) = 5.17 xx 10^14 "s"^(-1)`

Thus, frequency of yellow light emitted from the sodium lamp

= 5.17 × 1014 s–1

Wave number of yellow light, `barv = 1/lambda`

`= 1/(580xx10^(-9)) = 1.72 xx 10^6  "m"^(-1)`

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Chapter 2: Structure of Atom - EXERCISES [Page 69]

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NCERT Chemistry Part 1 and 2 Class 11
Chapter 2 Structure of Atom
EXERCISES | Q 2.5 | Page 69

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