X2 Sin X Log X - Mathematics

x2 sin x log

Solution

$\text{ Let } u = x^2 ; v = \sin x; w = \log x$
$\text{ Then }, u' = 2x; v' = \cos x; w' = \frac{1}{x}$
$\text{ Using the product rule }:$
$\frac{d}{dx}\left( uvw \right) = u'vw + uv'w + uvw'$
$\frac{d}{dx}\left( x^2 \sin x \log x \right) = 2x \sin x \log x + x^2 \cos x \log x + x^2 \sin x . \frac{1}{x}$
$= 2x \sin x \log x + x^2 \cos x \log x + x \sin x$

Concept: The Concept of Derivative - Algebra of Derivative of Functions
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APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 30 Derivatives
Exercise 30.4 | Q 9 | Page 39