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# (X + 5) is a Factor of 2x3 + 5x2 – 28x – 15. Hence, Factorise the Expression 2x3 + 5x2 – 28x – 15 Completely. - Mathematics

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#### Question

(x + 5) is a factor of 2x3 + 5x2 – 28x – 15. Hence, factorise the expression 2x3 + 5x2 – 28x – 15 completely.

#### Solution

Let f(x)=2x^3+5x^2-28x-15

x+5=0  ⇒ x=-5

∴ Remainder = f(-5)

=2(-5)^3+5(-5)^2-28(-5)-15

=-250+125+140-15

=-265+265

=0

Hence, (x+5)is a factoor of f(x)

Now, we have,

∴ 2x^3+5x^2-28x-15=(x+5) (2x^2-5x-3)

=(x+5)[2x^2+6x+x-3]

=(x-5)[2x(x-3)+1(x-3)]

=(x+5) (2x+1) (x-3)

Is there an error in this question or solution?

#### APPEARS IN

Selina Solution for Concise Mathematics for Class 10 ICSE (2020 (Latest))
Chapter 8: Remainder and Factor Theorems
Exercise 8(B) | Q: 1.2 | Page no. 111

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Solution (X + 5) is a Factor of 2x3 + 5x2 – 28x – 15. Hence, Factorise the Expression 2x3 + 5x2 – 28x – 15 Completely. Concept: Factor Theorem.
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