Answer 1

\[\text{ We have }, x + 5 > 4x - 10\]
\[ \Rightarrow 5 + 10 > 4x - x (\text{ Transposing x to the RHS and - 10 to the LHS })\]
\[ \Rightarrow 15 > 3x\]
\[ \Rightarrow 3x < 15\]
\[ \Rightarrow x < 5 \left( \text{ Dividing both sides by 3 } \right)\]
\[ \Rightarrow x \in \left( - \infty , 5 \right)\]
\[\text{ Hence, the solution set of the given inequation is } \left( - \infty , 5 \right) .\]