Answer 1

The given quadric equation is `x ^2 - kr + 4 = 0`, and roots are equal.

Then find the value of k.

Here, a = 1, b = -k and , c = 4

As we know that `D = b^2 - 4ac`

Putting the value of  a =1,b = -k and , c = 4

=` (-k)^2 - 4 xx 1 xx 4`

=` k^2- 16`

The given equation will have equal roots, if D = 0

`k^2 - 16 = 0`

`k^2 = 16`

`k = sqrt 16`

 =± 4

Therefore, the value of k =± 4 .