#### Question

Write two solutions of the form x = 0, y = a and x = b, y = 0 for the following equation :

−4x + 3y = 12

#### Solution

Given that ,

−4x + 3y = 12

Substituting x = 0 in the equation

−4x + 3y = 12 , we get

⇒ - 4 × 0 + 3 y = 12

⇒ 3y = 12

⇒ y = 4

Thus x = 0 and y = 4 is a solution of −4x + 3y = 12

Substituting y = 0 in the equation

−4x + 3y = 12 , we get

⇒ - 4x + 3 × 0 = 12

⇒ -4x = 12

⇒ `x = 12 / -4 = -3`

Thus, x = -3 and y = 0 is a solution of −4x + 3y = 12 .

Thus x = 0. y = 4 and x = -3. y = 0 are two solutions of −4x + 3y = 12

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Solution Write Two Solutions of the Form X = 0, Y = a and X = B, Y = 0 for the Following Equation : −4x + 3y = 12 Concept: Solution of a Linear Equation.