Question

Write two solutions of the form x = 0, y = a and x = b, y = 0 for the following equation :

−4x + 3y = 12

Answer 1

Given that , 

−4x + 3y = 12

Substituting x = 0 in the equation

−4x + 3y = 12 , we get 

⇒  - 4 × 0 + 3 y  = 12

⇒ 3y = 12

⇒  y = 4

Thus x = 0 and y = 4 is a solution of −4x + 3y = 12

Substituting y = 0 in the equation

 −4x + 3y = 12 , we get 

⇒ - 4x  + 3 × 0 = 12 

⇒ -4x = 12 

⇒ `x = 12 / -4 = -3`

Thus, x = -3 and y = 0 is a solution of  −4x + 3y = 12 . 

Thus x = 0. y = 4 and x = -3. y = 0 are two solutions of  −4x + 3y = 12