Write the expression for the de Broglie wavelength associated with a charged particle of charge q and mass m, when it is accelerated through a potential V.
An electron of mass m is accelerated through a potential difference of V volt. The kinetic energy acquired by the electron is given by `1/2` mv2 = eV
Therefore, the speed v of the electron is v = `sqrt((2"eV")/"m")`
Hence, the de Broglie wavelength of the electron is λ = `"h"/"mv" = "h"/sqrt(2"emV"`
Concept: Matter Waves
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