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Write the equation of the lines through the point (1, −1) perpendicular to 3x + 4y = 6

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#### Solution

Any line perpendicular to 3x + 4y – 6 = 0 will be of the form 4x – 3y + k = 0.

It passes through (1, –1)

⇒ 4 + 3 + k = 0

⇒ k = – 7.

So the required line is 4x – 3y – 7 = 0

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