Answer 1

For any natural number m > 1, 2m, m² − 1, m² + 1 forms a Pythagorean triplet.

If we take m² + 1 = 14, then m² = 13

The value of m will not be an integer.

If we take m² − 1 = 14, then m² = 15

Again the value of m is not an integer.

Let 2m = 14

m = 7

Thus, m² − 1 = 49 − 1 = 48 and m² + 1 = 49 + 1 = 50

Therefore, the required triplet is 14, 48, and 50.