Answer 1

Program :-

Sourse code :

 

//Program for matrix multiplication using functions.
#include <stdio.h>
#include <stdlib.h>
void input(int m, int n, int a[m][n])
{
  for (int i = 0; i < m; i++) {
    for (int j = 0; j < n; j++) {
      printf("%d, %d : ", i, j);
     scanf("%d", &a[i][j]);
    }
  }
}
void print(int m, int n, int a[m][n])
{
int i, j;
for (i = 0; i < m; i++) {
  for (j = 0; j < n; j++) {
    printf("%3d ", a[i][j]);
 }
 printf("\n");
 }
}
void multiply(int m, int n, int p, int a[m][n], int b[n][p], int c[m][p])
{
for (int i = 0; i < m; i++) {
  for (int j = 0; j < p; j++) {
   c[i][j] = 0;
   for (int k = 0; k < n; k++) {
    c[i][j] += a[i][k] * b[k][j];
    }
   }
  }
}
void main()
{
    int r1, c1, r2, c2;
    printf("Row and column for matrix #1 :\n");
    scanf("%d %d", &r1, &c1);
    printf("Row and column for matrix #2 :\n");
    scanf("%d %d", &r2, &c2);
    if (r2 != c1) {
       printf("The matrices are incompatible.\n");
       exit(EXIT_FAILURE);
}
    int mat1[r1][c1], mat2[r2][c2], ans[r1][c2];
    printf("Enter elements of the first matrix.\n");
    input(r1, c1, mat1);
    printf("The elements of the first matrix are :\n");
    print(r1, c1, mat1);
    printf("Enter elements of the second matrix.\n");
    input(r2, c2, mat2);
    printf("The elements of the second matrix are :\n");
    print(r2, c2, mat2);
    multiply(r1, r2, c2, mat1, mat2, ans);
    printf("The product is :\n");
    print(r1, c2, ans);
    getch( );
}

Row and column for matrix #1 : 2 2 Row and column for matrix #2 : 2 2 Enter elements of the first matrix. 0, 0 : 1 0, 1 : 17 1, 0 : 25 1, 1 : 30 The elements of the first matrix are : 1 17 25 30 Enter elements of the second matrix. 0, 0 : 74 0, 1 : 89 1, 0 : 3 1, 1 : 65 The elements of the second matrix are : 74 89 3 65 The product is : 125 1194 1940 4175