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Write Nuclear Reaction Equations for β+-decay of 9743tc - Physics

Write nuclear reaction equations for β+-decay of `""_43^97Tc`

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Solution

α is a nucleus of helium `(""_2He^4)` and β is an electron (e− for β− and e+ for β+). In every α-decay, there is a loss of 2 protons and 4 neutrons. In every β+-decay, there is a loss of 1 proton and a neutrino is emitted from the nucleus. In every β−-decay, there is a gain of 1 proton and an antineutrino is emitted from the nucleus.

For the given cases, nuclear reactions can be written as:

`""_43^97 Tc -> _42^97Mo + e^+ + v`

Concept: Radioactivity - Introduction of Radioactivity
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APPEARS IN

NCERT Class 12 Physics Textbook
Chapter 13 Nuclei
Q 6.6 | Page 462
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