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# Write Nuclear Reaction Equations for α-decay of 22688ra - CBSE (Science) Class 12 - Physics

#### Question

Write nuclear reaction equations for  α-decay of ""_88^226Ra

#### Solution

α is a nucleus of helium (""_2He^4) and β is an electron (e− for β and e+ for β+). In every α-decay, there is a loss of 2 protons and 4 neutrons. In every β+-decay, there is a loss of 1 proton and a neutrino is emitted from the nucleus. In every β-decay, there is a gain of 1 proton and an antineutrino is emitted from the nucleus.

For the given cases, the various nuclear reactions can be written as:

""_88Ra^226 ->  _86Rn^222 + _2He^4

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#### APPEARS IN

Solution Write Nuclear Reaction Equations for α-decay of 22688ra Concept: Radioactivity - Introduction of Radioactivity.
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