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Write Nuclear Reaction Equations for α-decay of 22688ra - CBSE (Science) Class 12 - Physics

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Question

Write nuclear reaction equations for  α-decay of `""_88^226Ra`

Solution

α is a nucleus of helium `(""_2He^4)` and β is an electron (e− for β and e+ for β+). In every α-decay, there is a loss of 2 protons and 4 neutrons. In every β+-decay, there is a loss of 1 proton and a neutrino is emitted from the nucleus. In every β-decay, there is a gain of 1 proton and an antineutrino is emitted from the nucleus.

For the given cases, the various nuclear reactions can be written as:

`""_88Ra^226 ->  _86Rn^222 + _2He^4`

  Is there an error in this question or solution?

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Solution Write Nuclear Reaction Equations for α-decay of 22688ra Concept: Radioactivity - Introduction of Radioactivity.
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