Write nuclear reaction equation for β+-decay of C611C. - Physics

Short Note

Write nuclear reaction equation for β+-decay of `""_6^11"C"`.



α is a nucleus of helium `(""_2^4"He")` and β is an electron (e− for β and e+ for β+). In every α-decay, there is a loss of 2 protons and 4 neutrons. In every β+-decay, there is a loss of 1 proton and a neutrino is emitted from the nucleus. In every β-decay, there is a gain of 1 proton and an antineutrino is emitted from the nucleus.

For the given case, the various nuclear reaction can be written as:

`""_6^11"C" ->  _5^11"B" + "e"^+ + "v"`

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Chapter 13: Nuclei - Exercise [Page 462]


NCERT Physics Class 12
Chapter 13 Nuclei
Exercise | Q 13.5 (v) | Page 462
NCERT Physics Class 12
Chapter 13 Nuclei
Exercise | Q 6.5 | Page 462


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Time (s)

Activity (A)
(108 disinte-
grations s−1)
Time (s)

Activity (A
108 disinte-grations s−1)

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