# Write nuclear reaction equation for β−-decay of Bi83210Bi. - Physics

Short Note

Write nuclear reaction equation for β-decay of ""_83^210"Bi".

#### Solution

α is a nucleus of helium (""_2^4"He") and β is an electron (e− for β and e+ for β+). In every α-decay, there is a loss of 2 protons and 4 neutrons. In every β+-decay, there is a loss of 1 proton and a neutrino is emitted from the nucleus. In every β-decay, there is a gain of 1 proton and an antineutrino is emitted from the nucleus.

For the given case, the various nuclear reaction can be written as:

""_83^210"B" ->  _84^210"PO" + "e"^(-) + bar"v"

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#### APPEARS IN

NCERT Physics Part 1 and 2 Class 12
Chapter 13 Nuclei
Exercise | Q 13.6 (iv) | Page 462
NCERT Class 12 Physics Textbook
Chapter 13 Nuclei
Exercise | Q 6.4 | Page 462
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